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Write the acidic equilibrium equation for CsHsNHtReset(g)(aq)HzO OH-NHH3OtHzOo3C2...

Question

Write the acidic equilibrium equation for CsHsNHtReset(g)(aq)HzO OH-NHH3OtHzOo3C2

Write the acidic equilibrium equation for CsHsNHt Reset (g) (aq) HzO OH- N H H3Ot HzOo 3C2



Answers

Write a balanced half-reaction for each of the following in an acidic solution: (a) $\mathrm{SO}_{2}(g) \longrightarrow \mathrm{SO}_{4}{ }^{2-}(a q)$ (b) $\mathrm{BrO}_{3}^{-}(a q) \longrightarrow \mathrm{Br}_{2}(l)$

We have a total of three net Ionic equation corresponding to the equilibrium so three equation can be represented. US. Second equation Will be tart equation can be represented us. There will be three dissociation constant with their three reaction respective, respectively. So okay, a one corresponds to First Association. It would be concentration off product multiplied, divided by the concentration off reactions. The second association going student can be represented us the toad. The association will be your phone negative three. Divide multiplied with it's 30 positive concentration divided by it's You're four to make.

In this question, we have to write a chemical equation that represents the organization of a weak acid AJ. Also, we have to write the equilibrium constant expression for this reaction. Okay, that week I said eight a iron eyes is in water and produces in my nurse And a 30 plus. Yeah. And uh, equilibrium constant. Okay, equilibrium is concentration of E minors times concentration of Hi do near my aunt, divided by the concentration of the week as and this equilibrium constant has a special name and that is a k a k a s s E ionization constant.

So we'll start with what we know. They say that we want 02 going toe water in acidic solution. So we balance our oxygen's to right here. Then we'll balance our hydrogen ins with hydrogen ion because it's, um, acidic solution. So forage plus on this head on this side. Then we need our charges to be balance. So we need four electrons right here, sometimes ph plus ca NBI expressed as h +30 plus. So we would have four electrons plus four h +30 plus plus oxygen goes to But when we do that, we just introduced more four more waters. So we need for four more waters undecided for a total of six water.

When writing an equilibrium constant expression for a weak acid, we follow the same rules that we do to write any equilibrium constant expression. These equilibrium constants are often called K. Eyes or ionization equilibrium constants, but solids and liquids are still excluded and K. E. Q. Or K. I. In our case will be still the products concentrations raised to their coefficient divided by reactant concentrations raised to their coefficients. So for this ionization equilibrium of an acid, then K. Q. Or K. I will be equal to the concentration of hydrogen multiplied by the concentration of the anti on, divided by the concentration of the acid. And we'll follow this pattern for all of them. For this next ionization of an acid, it'll again be concentration of hydrogen multiplied by the concentration of the anti on divided by the concentration of the acid. And for the last one, K. Q or K. I. Is going to be the concentration of hydrogen divided by the concentration of the anti on. It's very multiplied by the concentration of the N. I. N. Divided by the concentration of the acid.


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