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Experiment 14: Visualizing chemical structures using Lewis model[9 POINTS] Draw Lewis structures and determine the geometries for the following moleculesFormulaLewv...

Question

Experiment 14: Visualizing chemical structures using Lewis model[9 POINTS] Draw Lewis structures and determine the geometries for the following moleculesFormulaLewvis StructureElectron-pair geometryMolecular geometryccuPH;I5 POINTS] Draw resonance structures (all vald Lexns structures) for PO; -

Experiment 14: Visualizing chemical structures using Lewis model [9 POINTS] Draw Lewis structures and determine the geometries for the following molecules Formula Lewvis Structure Electron-pair geometry Molecular geometry ccu PH; I5 POINTS] Draw resonance structures (all vald Lexns structures) for PO; -



Answers

Draw the Lewis structure for acetamide $\left(\mathrm{CH}_{3} \mathrm{CONH}_{2}\right),$ an organic compound, and determine the geometry about each interior atom. Experiments show that the geometry about the nitrogen atom in acetamide is nearly planar. What resonance structure can account for the planar geometry about the nitrogen atom?

The Louis structure. Representation off all the five molecules is shown as followed.

Let's first draw the LewiS structure for each of these, The first one is sbc L six minus which contains 48 Valence electrons. 48 valence electrons with six chlorine atoms, uses up all of the valence electrons to bond to the chlorine atoms and give each chlorine and octet. Therefore, with six electron groups all bonding surrounding antimony, we have an Octa he'd roll shape with sp three D. To hybridization. PF three contains 26 valence electrons With 26 valence electrons. We end up with three electron groups that are bonding and one that is non bonding around phosphorus. A total of four electron groups is a tetra hydro electron group geometry. But a tribunal planer molecular, I'm sorry, a tribunal parameter. All molecular geometry for electron groups is always sp three hybridized Zen. In Tetra fluoride contains 36 valence electrons. When we draw the Lewis structure, we end up with six electron group surroundings. In in four of them are bonding. Two of them are non bonding. Six electron groups is an Octa khidr electron group geometry, with four of them bonding, we have a square plane or molecular geometry, and six electron groups is always sp three D to hybridized.

Explanation for the question here we will draw levy structure please please. And product mall killers were free of the flowing. So here behalf and but I. F. Five. Bye Dean paint a floor. Right. So here the levee structure for this molecule is I mean Irene is the central atom. And we have salary. Yeah. Hillary Loreen flooring and flooring florian having seven valencia and six here three long years. And when you know bounded for and here will be the same. Okay. So if mall healers you metro is molecule is your military Is molecule a unitary easier secure, tyrannical and next is part to be we have fighting try all right. And it's levy structure is Yeah. Heidi is a halogen having valence electron seven when in the shared in three long piers and you and its molecular geometry is leadership. Believe me it is showing me a tree. And next week we have in part C we have forced first painter chlorate Islamist structure is here level structure of 1st 1st paint accurate valence electrons and its molecular geometry is try Conan by pira. Middle trade corner. Bye by Roy. Yeah he does molecule is geometry. And next piece we have party selenium to a traveler, right? Islamic structure is selenium. The traveler it the traveler. Right in your small colors. Geometries. See so. And next piece we have. Yeah, but if colour etcetera flow rate is level structure is easier flooring. Mhm. And if small killers Yuma trio B T shaped.

So for this problem we have a few molecules HCP and I O F for minus. And you want to find their electron melodic fury geometries and compare these to find any differences. So let's start with our first HCP we add up the number of valence electrons. As always We know that this molecule needs 10 electrons and the C. H bond here is done since hydrogen can only have one electron tv shared and so are remaining six electrons will go on the C and P bonds. But we know that carbon went to former charge of zero in needs of four electrons total. And so the easier it is to easiest way to make that would make a triple bone. Then we have tried adding to lone parents to make or one lone parent to make a formal charge. We'll find out we were running out of electrons on the spot. Serous to feel its octet. So to affiliate as I built cmp we will do something like this and this all add up to 10 electrons. And if we draw our molecular structure here, you can see that is electronic geometry and its molecular geology. It's pretty clear it's gonna be living here. Yeah. And next we have this I. LF four minus molecule so young we add up all the electrons or valence electrons and we know that this value will have 42 electrons. And the antenna is probably gonna be our central atom here and actually want to first fill in the young test with all these floors with bloom pairs To make. Then we'll have a former charge of zero and only have used up 32 electron. So we have 10 electrons left between the I and your. And we can start by putting it over the phone and then adding too little paris to this out students so that this one can form a charge of zero as well. And he added two remaining electron respond to the central Atom hired. I and now we see that island. The central animal have a charger or negative. One of the rest of the items will have a formal charge of zero. And that's okay because I have done in the halogen. So it's relatively electoral negative. So it all right to put a negative one former charge on it. And if we draw our molecular structure here, we know that the electron geometry that's going to be an actor. He grows. So we just followed this shape of the Yalta hydro and replace one of the bonds with the lone pair. This is what we will come up with. And this molecular geology here is actually called a square pyramidal. It when it when central atom has six electron regions, but only one of them is a lone pair. So for our first molecule, we can see that the molecular and electron geometries are the same since there aren't any lone pairs on this, so there wouldn't be any different. But on the second molecule here we can see that electron geology and molecular geometries different since have six electron regions, but one of them is a lone pairs, so the lone pair won't be included in the molecular geometry, and the molecular geometry is only concerning the physical bonds within the atom, while the electron geometries count both of them pears and the bonds.


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