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Find the linear velocity of a point on the edge of the wheel rotating 20 times per min: The diameter of the wheel is 25 inches: Round to the nearest tenth: WANT YOU...

Question

Find the linear velocity of a point on the edge of the wheel rotating 20 times per min: The diameter of the wheel is 25 inches: Round to the nearest tenth: WANT YOUR ANSWER INEIMN"4.79

Find the linear velocity of a point on the edge of the wheel rotating 20 times per min: The diameter of the wheel is 25 inches: Round to the nearest tenth: WANT YOUR ANSWER INEIMN" 4.79



Answers

A bicycle wheel of diameter 30.0 in. rotates twice each second. Find the linear velocity of a point on the wheel.

In the institution we have given a disk whose radius is 10 semi and is rotating with an angular speed of 20 radiance per second. And we have to find its linear experience. So this is our disk and That this is its radius. That is given to us that is 0.1 m. And it is rotating about its axis with an angular the state of 20 radian per second. So let this is Omega is equal to 20 radiant per second. And we have to find it's linear speed at a point on the rim. So in the first part we have to find linear velocity. A point of him which is given by we is equals to our into omega. So here are is the idea that is 0.1 m and omega is 20. So after solving this we get two m per second. So this is the answer of our first bad. This is in diagram we can so that disease our We Now in the second part we have to find the linear speed at the middle of the radius, so mm linear velocity. Yeah, middle of radius is given by Being is equals two Are by two and 2 Omega. So this is 0.1 device to, and this is 20. So after following this we get velocity V, which is one m per second. So this is the answer of power. Second part. Thank you.

Before we know the anglers. Early near spit they called your anger Spit times Glinda Rania's. So we should get the anguished bit hereby question we should get equal to jewelry version by minute. So wish again the jury version. We're means done that. Jewell Times one Dr. Rosen will beat you guys so time will do. Bye. And then tamps would riders Nico George 25 feet If I was you get a good Jew. Um, and then 100 Right On we go Jew 100 times pry encoded 300 for thing I ah boned 16 uh, be a fit for a minute.

In this caution that areas off the Ferris wheel is equal to 25 feets, and it is given that the village rotating at two revolutions per minute, we have to find linear speeding feet per minute. Now, as we know, distance covered in one revolution will be Quito circumference off dance circle. And that is two pi R now the value of Ari's 25. So therefore, it will be 50 pie feats, and the distance covered in two revolutions will be equal toe to multiplied with 50 pie, and that will be equal toe 100 pie foods. Now, by putting the value of by here, we will get approximately Quito 314 feeds. Therefore, the linear spirit off the Ferris wheel will be 314 feats per minute.

His feet is given by the formula. We go to our comical now that a subsidiary values just fine into by 20 as well defined. This we can't quite right. For hence Tellinya. Speed is by before millimeters seconds.


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