5

The energy states for an electron in hypothetical atom are represented below A cold sample of gas of such atoms is illuminated by brief flash with continuous spectr...

Question

The energy states for an electron in hypothetical atom are represented below A cold sample of gas of such atoms is illuminated by brief flash with continuous spectrum: The atoms are then observed to emit light with discrete wavelengths. Which of the following transitions produces the longest wavelength light?lBt040033t0 22 t0 |Gmun Sule

The energy states for an electron in hypothetical atom are represented below A cold sample of gas of such atoms is illuminated by brief flash with continuous spectrum: The atoms are then observed to emit light with discrete wavelengths. Which of the following transitions produces the longest wavelength light?l Bt0 4003 3t0 2 2 t0 | Gmun Sule



Answers

Use the energy level diagram for the atoms of a substance to answer the next two questions.
Which electron transition will result in the emission of a photon with the longest wavelength?
(A) n = 4 to n = 3
(B) n = 4 to n = 2
(C) n = 4 to n = 1
(D) n = 3 to n = 2
(E) n = 3 to n = 1

Okay, so in this problem, you haven't Adam. That's like hydrogen. It's a one electron, Adam, and we know that it takes 17.5 evey. Diane, I see atoms and we want to get the energy level, the energy at each of the levels. And so, basically, if you look at the equation for hydrogen, the energy levels E N is minus 13.6 e v, divided by N squared. With this 13.6 number is tthe e ionization energy for hydrogen. And so we can analogous Lee sub in, um, the ionization energy in this case, 15.17 point 50 evey to get the energy spectrum. So we could say that the energy spectrum looks like, um minus 17.5 e v invited by N squared. And so, um, we can evaluate that for these various end some of the scroll down to all the end. So it's an equals 12345 So I'm gonna go ahead and evaluate each one. So for an equals one, it's 17.5. For an equals two, it's gonna be, um, 17.5, divided by two squared, which is four says 4.375 e b. These are all gonna be units of TV. You will put it at the end. And then for three, that would be three squared. So that's nine. So it's 1.9 for and I guess I should try to use the same number of Sig Figs. So I'll go ahead and make this heat. And for the next one, that's gonna be so. That's 1234 squared. So we want to divide it by 16. 17.516 is one point 09 My realm that right 1.9 Yes. And for five, we want to evaluate it at five square, just one of five. So that's, um, 0.7. So those would be the energy levels. Um, and then they're all negative because of the electron is bound great. And then we want to get the wavelength, um, of light from going toe unequal studio ankles for so you can see that going from an equals for toe One is, um, 75.63 then 321 is 79.76. So the difference in energy levels? Um, yeah, Actually, I make. I'm not going to subtract those. I don't think that's mathematically correct. So what I want to do is, um, I'm going to do it a long way, and then maybe at the end, think if there was a faster way to do it. So if an Adam if an electron is going from the n equals two to the N equals for a level, it's going from this energy to this energy and that difference who I could do that in my head is, um, 3.27 so that he is going to be 3.27 e v. And then if I stop that equal to HC over lambda and sulfur lambda, I get lambda is HC divided by that. So go ahead and plug that in. Let's see you see, divided by 3.27 And I thought I'm getting 379 nanometers. So go ahead and write that down 379 nano meters. So just kind of looking at that and then comparing that in this chart, so from an equals two down equals for, um, the difference in the the wavelength needed to go from four did. 1 to 2 to one is equal two. It looks like it's like 20 something. And so, um, you want an actual accurately get that, And that's because energy is inversely proportional toe lambda. And so it doesn't have a simple linear relationship. So I think this is the way that you would want to answer this quest.

In this question were given four possible transitions of an electron in a hydrogen atom and asked which of them results in the longest wavelength emission? Uh, during its transition, I've included an energy level diagram so that we can do it without doing detailed calculations. Our first choice is thean equals four to any close three transition choice be we have the n equals one. Tow n equals to transition choice. See, Thean equals one to n equals six. Transition and choice D thean equals three 10 equals to transition. The first thing to notice is that the problem specifically asked about emissions. This tells us that we're looking for a transition from, ah, higher energy level to a lower energy level. If we go the other way around, it would be talking about absorption. This allows us to eliminate choices B and C um, because their energy levels go from lower levels, toe higher levels. And so we're left with choices. A and D big choice. A talks about the transition between level four and level three. We're Choice D refers to the transition between level three and level two. Now, from the diagram, we can tell that the energy admitted in the transition from 3 to 2. I'm not is in fact there greater then the energy emitted during the transition from 4 to 3. However, that's not directly what we're being asked about in the problem were asked about wavelength recall that we can actually use Planck's equation to directly relate energy to frequency. So the higher the energy, the higher the frequency. So we also know that the frequency of the transition from 3 to 2 is going to be greater than the frequency of the transition from 4 to 3. From this point. Recall that we can relate wave length and frequency by the speed of light, but in this case, they're inversely related. So we can say that the wavelength of the transition from 3 to 2 is actually less than the wavelength of the transition from 4 to 3, because the transition from 4 to 3 is less energetic now. This tells us, in fact, that the longest wavelength of a mission from our choices then is in fact the transition from energy level four toe energy level three

As predictors transition would have the shortest wavelength. The shortest wavelength would be the same as the highest energy as they are proportional. The wave length is proportional to one over the energy. Um, we can also e is equal to each C over Lambda is our calculation there. And we know that the energy is related to the principal quantum number. So n is equal to one. Um followed by N is equal to two by n is equal to three. 10 is equal or and is equal to five. This would be the highest energy on the left here. This would be the lowest energy on the right here. So the transition, right, having the shortest wavelength would be the transition with the highest energy. What, which is from and equals one to end equals two. And this is choice a

In this culture were given a hypothetical atom makes 40 sorry energy levels. I'm gonna find one of the respective energy states. So what are the energies off the energy states are given death. The amount of energy to my own ice. This atom is actually 17 five e v. Assuming that the atom was only originally in the Garden state. So what this tells us is the energy of the growing state because energy of organization just taking Energia infinity, which is assumed to be zero, write the reference point minus of 80 energy, anti growing state going stay. Energy is basically negative 17.5. I'm gonna put it over here now to find you other respective energy levels. We gonna make use off the energies off the photons that I meet it. So I gave only the way flanks. We can find the energy off this four tons by taking each see over the way things are going. You CFCs one to force your e v nanometers. So I can't quickly your uncertain times off evey you know, electron puts so depending on what we thank you wanna put in over here? You can't get the energy or foot on. And if their energy photon by energy conservation, we can get the respective energy levels. Right? See, for example. And she for that go to e to just be taking anyone, plus the energy lt Fulton, which in this case, it's what four through, divided by 94.54 nanometers. Right? And so doing the calculations should be quite simple. May should be tickets. You to to be negative four point tree it if you I'm going to repeat these steps for the other energy. Nevers, right? Just have just that. We will have a different fault on energy by Sabeti. Same steps. All right, e tree, just e one, the for two. This tree going for e four. Finally, 45? No, for know that we have all the various energies for the energy. Devils can go on to the second putt. That is, if you're an electron transits from any costa for you. Any closer to 90 energy off this photo on that meter. Just be taking 84 minus you too. So the forests nick difficult 0.1 UV minus e to which is ah, four point negative four point treats. They see energy only photo on finding wavelength recreate is to each see over Lunda. So, Linda just beating each see, just want to force your e v dot Centimeters fell. Obaidi Energy 3.2 it e v. And you forget about 37 eats no vetoes. Just be with flying off the photo on that is meeting.


Similar Solved Questions

5 answers
Point) Determine which values of p the following integrals converge. Give your answer in each case by selecting the appropriate inequality and then entering numerical value in the box to define a range of p values for which the integral converges If the integral never converges, select and enter none for the numerical value_ either case be sure that you can rigorously prove convergence and divergence for different values of p.(a) J2 x(ln(x))PIn(x)dx(b) Jz
point) Determine which values of p the following integrals converge. Give your answer in each case by selecting the appropriate inequality and then entering numerical value in the box to define a range of p values for which the integral converges If the integral never converges, select and enter non...
4 answers
Exercise 1.7. Let X,X_X be a random sample from X : Neblr. p) . where is known. Find the MLE for p , E(X) ad Var(x).Examnle L.6. Let
Exercise 1.7. Let X,X_X be a random sample from X : Neblr. p) . where is known. Find the MLE for p , E(X) ad Var(x). Examnle L.6. Let...
5 answers
OrantlenoIDAs k Intereatad companne Prolaon Tundr Fannant Hmntr contiudr unt PODE Aroinct corpicuda [mauringune Eornct eac-i outplit #bora Faat would tha P-vatue br for Ha MLAAI Y*ar 0023 ~iue 005 995 Pwalue 99750t 9 ~Vaiut 995 0o5 P-value =None of tne ansivers cotted
Orantleno IDAs k Intereatad companne Prolaon Tundr Fannant Hmntr contiudr unt PODE Aroinct corpicuda [mauringune Eornct eac-i outplit #bora Faat would tha P-vatue br for Ha MLAAI Y*ar 0023 ~iue 005 995 Pwalue 9975 0t 9 ~Vaiut 995 0o5 P-value = None of tne ansivers cotted...
5 answers
Use the graph of $f$ shown in the figure to sketch the graph of each of the following.(A) $y=f(x)+2$(B) $y=f(x-3)$(C) $y=2 f(x)-4$(D) $y=4-f(x+2)$
Use the graph of $f$ shown in the figure to sketch the graph of each of the following. (A) $y=f(x)+2$ (B) $y=f(x-3)$ (C) $y=2 f(x)-4$ (D) $y=4-f(x+2)$...
1 answers
Let $S$ be the collection of vectors $\left[\begin{array}{l}x \\ y \\ z\end{array}\right]$ in $\mathbb{R}^{3}$ that satisfy the given property. In each case, either prove that S forms a subspace of $\mathbb{R}^{3}$ or give a counterexample to show that it does not. $$|x-y|=|y-z|$$
Let $S$ be the collection of vectors $\left[\begin{array}{l}x \\ y \\ z\end{array}\right]$ in $\mathbb{R}^{3}$ that satisfy the given property. In each case, either prove that S forms a subspace of $\mathbb{R}^{3}$ or give a counterexample to show that it does not. $$|x-y|=|y-z|$$...
5 answers
Ceneral 'Gtm mrscung eanet brota " IaletJcencncJekt = d Narent genes that emadaearlontha 9 ] ] ] dhbnd {toEeneutiontype Ciot Vinodatnunt tnattrt [ Yo MwlanMe 04 H natorthatuntErttIncomplete DenttInce Merlrkane tormthis phenonenonAnch Int Ame RenolyDrELDreItanenne Ortieet anerent idradluk
Ceneral 'Gtm mrscung eanet brota " Ialet Jcencnc Jekt = d Narent genes that e madaearlon tha 9 ] ] ] dhbnd {to Eeneution type Ciot Vino datnunt tnattrt [ Yo Mwlan Me 04 H nat orthatuntErtt Incomplete DenttInce Merlrkane torm this phenonenon Anch Int Ame RenolyDr ELDreIt anenne Ortieet ane...
5 answers
Course: 20278HUNZZUHistoncal Bac?MoMonshitting485ignmentsDHcMowor;rans-ommaneMatnway | Algstudentdesmo comlactivityquilder'srudenc/60330 113935c316cedc7fd6#screenldy_1Transformations Kd Uir OialNexlMatch each graph to the expression that transforms the black solid graph into the blue dashed graph.{f6+)f(x)-2f(-x)
Course: 20278 HUNZZU Histoncal Bac? MoMon shitting 485ignments DHcMowor; rans-ommane Matnway | Alg studentdesmo comlactivityquilder'srudenc/60330 113935c316cedc7fd6#screenldy_1 Transformations Kd Uir Oial Nexl Match each graph to the expression that transforms the black solid graph into the blu...
5 answers
Figure shows particle with positive charge qand mass m moves through velocity selector consisting of a magnetic field and an electric field The electric field points downward; as shown in FigureFigureIn which direction must point for the magnetic force to oppose the electric force?
Figure shows particle with positive charge qand mass m moves through velocity selector consisting of a magnetic field and an electric field The electric field points downward; as shown in Figure Figure In which direction must point for the magnetic force to oppose the electric force?...
5 answers
In Exercises $5-30$ , find an appropriate viewing window for the given function and use it to display its graph$$f(x)=x^{5}-5 x^{4}+10$$
In Exercises $5-30$ , find an appropriate viewing window for the given function and use it to display its graph $$f(x)=x^{5}-5 x^{4}+10$$...
5 answers
Consider the following product.Ilv IQ+ 2) #1) (+1)Find the factor of the product when i m4.Find the factorof the product when i 5 31Findithe product;|
Consider the following product. Ilv IQ+ 2) #1) (+1) Find the factor of the product when i m4. Find the factorof the product when i 5 31 Findithe product;|...
5 answers
16. (12 points) The standard deviation of sample of 30 factory the hourly wages of & random find 0 95% conficence ioteeral fo 84.45. Assuming normal distribution, Use 12-distribution_ interval for the variance &? and the standard deviation
16. (12 points) The standard deviation of sample of 30 factory the hourly wages of & random find 0 95% conficence ioteeral fo 84.45. Assuming normal distribution, Use 12-distribution_ interval for the variance &? and the standard deviation...
5 answers
Histology " VOCAB Wrlte = Word from the box euch blank bclo #The inside hollo " Dncam The center of solid orqan Layers around the medulla fibrous covering of an organ ball-shaped structure A gelatinous gooey mixture tube that carries some substancecapsulecolloidcortotfolliclelumen medulladuct
Histology " VOCAB Wrlte = Word from the box euch blank bclo # The inside hollo " Dncam The center of solid orqan Layers around the medulla fibrous covering of an organ ball-shaped structure A gelatinous gooey mixture tube that carries some substance capsule colloid cortot follicle lumen me...
5 answers
Iclartiy the mjer Frad Uctis)forthefollawing rextion Seed; all that <ppl. " the rexttion fgernct vie d prodcict, Shlet Ne Teuoion'NBSXv(Ux Fezeiio
Iclartiy the mjer Frad Uctis)forthefollawing rextion Seed; all that <ppl. " the rexttion fgernct vie d prodcict, Shlet Ne Teuoion' NBS Xv (Ux Fezeiio...
5 answers
(Inctios Show that 1 {8} - [ by (x)f ~lx is a bijective
(Inctios Show that 1 {8} - [ by (x)f ~lx is a bijective...
5 answers
Given the equation y = 7sin(3(z + 4)) + 6The amplitude is:The period is:The horizontal shift is:units to the ([Select an answerThe midline is: y =Check Answer
Given the equation y = 7sin(3(z + 4)) + 6 The amplitude is: The period is: The horizontal shift is: units to the ([Select an answer The midline is: y = Check Answer...

-- 0.019605--