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Draw out the structure of the following molecules. (12pts) 4-chlorobenzoic acid 2,4-dimethylpentanalcis-1-bromo-3-isopropylcyclopentaneethyl 3-ethylhexanoate...

Question

Draw out the structure of the following molecules. (12pts) 4-chlorobenzoic acid 2,4-dimethylpentanalcis-1-bromo-3-isopropylcyclopentaneethyl 3-ethylhexanoate

Draw out the structure of the following molecules. (12pts) 4-chlorobenzoic acid 2,4-dimethylpentanal cis-1-bromo-3-isopropylcyclopentane ethyl 3-ethylhexanoate



Answers

Draw a structure for each compound. (a) butylbenzene (b) 1 -ethyl- 2 -iodobenzene (c) para-dimethylbenzene

Again in this caution on. So we have to draw the condensed structure of home love off the listed compounds. So starting with option egg, the given compound is toe tile one hexen old, so there will be one to between 456 six street lane carbon gene ch tweet Ch. Two See it's tool CH two. See, It's too see It's too on DDE Who, while there will be two carbon chain on sick and carbon moving towards Option B, we have the given name as metal Finn. I'll keep it on so the representation is Here we go. Carbon double bonded oxygen. See, it's three there. Will we have the representation towards auction? See, the given name is Farah Broom. Oh, Ben's weak acid. So Ben's a week. Sorry, there's not a c o Etch Ben's week Mean benzene and para blow Moe means bro Mean at the end. Here we have the ring presentation Auction E The given name off the compound is a tie. Beautiful either. So it I will be ch three ch two excision Beetle will be now ch two. See? It's too see? It's too ch three. No, the next last components and die. The type bends the mind. So structure representation is carbon nitrogen ch three ch three Double bonded oxygen, Yeah.

Hello Today we're solving problem number 19. Draw the structure of each of the following. So let's begin with a ah, good rule of thumb. Whenever you're trying to break down the name of a compound is to look at the Suffolk, the last half of the name that will tell you the basic structure and the first half of the name will tell you all the extra constituents that are added on to that basic structure. So in this case, in a we have this Suffolk's octane. Okay, Oct meaning eight. This is telling us that this is an eight carbon compound. So let's begin by drawing that 12 345678 Now we can look at the first half to determine what the constituents are. Okay, In the first half of the name, we see this die metal die meaning to and methyl meaning a metal subs substitue int. So there's two methods substitue INTs and where they located there, located at the second and third Carbon. So all we have to do is draw a methyl group at the second carbon and at the third carbon Now moving on to be okay. Here we have the stuff fix. Cyclo hexane. So this is a six carbon ah ring. So 123 four, five, six. There we go. Six carbon ring. Okay. And then if we look at the first half of the name, we see that there is one. There's an ethyl substitue in at the one position. So arbitrarily picking the one position here is the one, Ethel. And then we see that at the three position there is a method all. So let's say going clockwise from from that first carbon too. Three here is the three metal. I hope that

Okay. This problem is asking us to propose a structure for each of these compounds. So first up, I have this ethyl acetate. Okay, so noting that it has the ending of eight, I know that that is going to be a car box late or a Esther. And because I had to have something in front of that something. Eight. I know it's going to be an Esther in which this group, my Ethel, is going to be the carbon group after my oxygen. So I'm gonna have my Esther in which I have the oxygen and attached the oxygen. I have my effort group. Yes, that's gonna look like this. Okay. And then any time Missy ass it, we know that from issued a gas. Did we know that from ask tone that just corresponds to my carbon eel connected to a ch three just like that? Okay, so that is going to be in my structure of ethyl acetate. Next up we have this Alfa metal moronic acid. So we might recognize melodic Esther, um, acid from melodic Esther. And that looked something like this in which we had my to Esther's and then in the middle we had that awful carpet. Okay, So moronic. Esther would look something like this, But as far as melodic acid goes, anything we have acid that's gonna correspond to car black silk assets. Someone have my to hydrogen is on the side, so I have to car books, look acids. And then because I have Alfa Metal, that's gonna correspond to the awful carbon. I'm gonna have a methyl group. So just like that, that is my Alfa my phone melodic acid. Okay, next up is Bay Taquito, Esther. So this one, we have pretty good creative control because we can actually make it up. So I'm gonna have my key tone like that was going to get ch three over here and then on the beta carbon. So here's carbon zero. Here's Alfa. And then here's beta on that beta carbon. I have the presence of my Esther, and then we have creative control because I can make this any Esther I want. So I can even make it a turbulent if I wanted to. Okay, but that's just gonna be for that compound. Okay, that's a beta keto, Ester. And now let's make it an you know, Tanamor of cycle Penton. So when I have my structure of cycle pets No, I'm just gonna make it into the regular key tone first. So I have a five member green because I have cyclo painting, and then the own corresponds to the keystone, and then the email Tanamor is going to be something like this in which I haven't gonna be like this. I have my five member during still, But instead of having this auction with a double bond, I'm gonna have something like this in which I have my make a charge there and my cocaine right there. Okay, so just like that. Okay? And we get that from basically deprived nation using a piece onto this Alfa Carbon, that awful carbon is going to get the appropriated moving the electrons onto this single want to make a double bond and moving the electrons up to the auction to eventually make my you know, Tanamor. Okay. And then last but not least, is the carb oxalic acid obtained from melodic Esther synthesis with a Pro Bowl bromide. Okay, So moronic. Esther synthesis is going to be utilizing melodic Esther, in which I have a compound that looks like this. Okay, so this is my melodic Esther. And I'm going to react that with apropo bromide. So just reacting this plane out with purple bromide isn't gonna do much. But we have director of the base first in order to get that pro for bromide attached to it. So I used l b A. I could also use probably actually more likely more likely use my sodium oxide. And that is going to take off the most aesthetic hydrogen of my melodic Esther, which is my awful carbon hydrogen. So this one right here after that, you will obtain this that carbon nuclear file and then that carbon cliff all can go ahead and intact. My purple bromide case of that proper remind is going to behave as an elector file to this nuclear file. So have 123 carbons, and then I have my bro mean attached to the third carbon. So I'm gonna attack that carbon, releasing my brewing as a leaving group. Okay, so the structure of this is going to be this So far, so have my melodic Esther and attached to this awful carbon. I'm gonna be connected to 123 carbons. So that is the structure so far. But again, this is a carb oxalic acid obtained from the obtained from the melodic Esther synthesis case. Demonic Esther synthesis utilizes a base to make my nuclear filled carbon Get right there. And then we attack our carbon, You or our, um electrify. Okay, I added my carbons to that carbon for here and now I have to proceed with my melodic Esther synthesis, and that is going to utilize adroll assis. So I have it. Three a plus, h 20 and heat is basically gonna make thes Esther's into carb oxalic acids. I'm gonna have a very similar structure. I'm gonna have my moronic acid. Okay? And then on that central carbon, I'm gonna have the connection to 123 carpets And then last but not least, is the utilisation of heat. He is going to proceed with a D card box elation, reaction in which we basically take off one of these car box look acids with heat, and that's gonna form carbon dioxide. So as far as my structure goes, I'm gonna end up with this. When have my car books look acid? I'm gonna have the connection to this Alfa Carbon. So this Alva Carbon right there corresponds to that awful carbon right there. And then, of course, we still have the connection to 123 carbons. So that is going to be my final structure of my car box. Look. Asset obtained from a moronic Esther synthesis with Pro Bowl bromide. Okay. And these are all my structures.

This is the answer to Chapter 20 to problem number five fromthe Smith Organic chemistry textbook. Uh, this problem gives us eight compound names and were asked to draw a structure for each name. Ah, and so the rules for naming carbon you'll, uh, well, car back. So Gassid derivative compounds are nicely summarized in table 22.2. It's on the page were maybe two pages above this question. But the rules are also discussed at length above that of a table 22.2 has it has a pretty good summary. Um, okay, so for a we have five metal helped in oil chloride. So Hempton oil tells us that this is gonna be a seven carbon chain on and it's gonna be a nascent chloride. Um, okay, so that is going to look like this one, too. 34567 Uh So, um, here's our ask chloride. And, of course, the carbon that is part of the carbon. You would actually be carbon number one. Um, And so in that case, 2345 So five MB Ethel helped in oil chloride. Okay. S o there. Is that for B? We have isopropyl pro bono. It, um And so this is gonna be an Esther. Um, and so pro bono eight tells us that we're gonna have three carbons, uh, on the side with the carbon you and then we'll have our other oxygen and will have an isopropyl group there. So there we go. Isopropyl propane. Know it for See how we have acetic formic anhydride. Um and so this is a mixed and hydride. So the one side is gonna be formic anhydride. So a single carbon, then we have our central and hydride oxygen on. Then our other side is an acetic group. So one carbon two carbons. Okay, so that's acetic, formic and hydride. Ah, for Port de we have n icea beautiful and metal Butane a meid or butin a mind. Okay, so an eye so beautiful. So we have a nice a beautiful group on our nitrogen and metal. So we have a metal group on our nitrogen as well. Butin a mind. So let's start with butin a mind So 1234 Here's our carbon ume. Here's our nitrogen That makes this in a mine on And then we have ah metal group on the end, and I so beautiful group And so there they are. So, uh, n icea beautiful and metal butin a mind. So there we go. Um, for E We have three metal paint. A kn night trial. Okay, so Pentti night trial is gonna be 1234 night trial so that our carbon carbon one eye's gonna be the night trial carbon And so then we'll have four more for that maintain chain. Ah, and then we have a metal group at carbon three. And so there that is Okay, uh, for F uh, f is gonna be Ortho sayin, Oh, Ben's OIC acid. Okay, So, sayin, Oh, Ben's OIC acid Um Okay, so we can start by drawing the benzene ring. Uh, Ortho sayin, Oh, Ben's are okay, so let's drop in. So Gassid So here's Ben's OIC acid Orth O scion. Oh, so in the Ortho position, we have a night trial or a cyanide on. And so there's Ortho Science of Enzo Gassid. All right, Fergie? No, we have sec beautiful to metal hex and knowing. Okay. Ah, sec beautiful to metal hex. Unknowing. Okay, so we have a hex in No. Eight as sort of the base of this molecule, right? Six. So the six carbon Esther, um, with a two metal substitution. So there is that. And then the other side of our Esther is gonna be a second beautiful group. And so there is a sec beauty group, Okay. And so that sec bugle to metal hex and know it, Um And so lastly for H, we have n ethel hacks. Ain't hacks in a meid. Okay, so Hexen of mine. 123456 So here is, uh, Hexen of mine. Ah, and then an asshole. 12 So there's our ethel group on the nitrogen and nitrogen always makes three bonds, so we need to put one hydrogen on it, okay? And so there we go. There's an Ethel Texana mind. Um, And again, if if you need thio, review any of these rules or or practice Table 22.2 has a good summary of the rules for naming carb oxalic acid derivatives. Ah, and that's the answer to chapter 20 to problem number five


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