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40.676 kB object is rotated about fixed 0.17 m rdius . with constant centripetal force Ez 5.28 N acting On the object. The specd of the objec} is measured to be [.1...

Question

40.676 kB object is rotated about fixed 0.17 m rdius . with constant centripetal force Ez 5.28 N acting On the object. The specd of the objec} is measured to be [.15 mVs. When 50 grams Of mass is added T0 the object, while the other conditions are kept the same . Ihe speed of the object is expected (0 decrease remain the sane increaseprojectile has an initial speed of 3.58 ms when fired horizontally: When fired at an angle of 36* from the horizontal , what would be the vertical component of its

40.676 kB object is rotated about fixed 0.17 m rdius . with constant centripetal force Ez 5.28 N acting On the object. The specd of the objec} is measured to be [.15 mVs. When 50 grams Of mass is added T0 the object, while the other conditions are kept the same . Ihe speed of the object is expected (0 decrease remain the sane increase projectile has an initial speed of 3.58 ms when fired horizontally: When fired at an angle of 36* from the horizontal , what would be the vertical component of its velocity the moment leaves the mechanism? 0 mls 2.90 mls 2.10 mls 358 s A projectile has an initial velocity of 3.64 mls when fired horizontally_ When fired at an angle of 438 from the horizontal , what would be the horizontal component of its velocity the moment iL leaves the mechanism? 0 mls 2.66 mls 2.48 mls 3.64 ms



Answers

A projectile is launched from $\mathrm{O}$ at the foot of an inclined plane inclined at $30^{\circ}$ to the horizontal, with an initial velocity $\mathrm{u}_{1}$, at angle of projection $60^{\circ}$ to the horizontal to reach a point $B$ on the top of the incline. From the position $B$ it is launched with velocity $\mathrm{u}_{2}$ at $60^{\circ}$ to the horizontal to reach back $\mathrm{O}$ at the foot. If $\mathrm{t}_{1}$, and $\mathrm{t}_{2}$ are the times of flight in 1 st and 2 nd cases respectively, then match the following: Column I (a) $\frac{\mathrm{u}_{1}}{\mathrm{u}_{2}}$ (b) $\frac{\mathrm{t}_{1}}{\mathrm{t}_{2}}$ (c) Modulus value of acceleration normal to the plane (in $\mathrm{ms}^{-2}$ ) (d) Modulus value of acceleration parallel to the plane (in $\mathrm{ms}^{-2}$ ) Column II (p) $5 \sqrt{3}$ (q) $\frac{1}{\sqrt{2}}$ (r) $\sqrt{2}$ (s) same for both

Hi, everybody. So, for this one, we didn't know what. The projector has a weight of £45. And with respect, symmetry determines proximity. Rate of session Be, um, if it's further know the radius of the gyration of the special and determined exact values of the two possible razor procession. Okay. And we can start by kind of drawing a little image. Um, my image, of course, is not gonna be a perfect not stupid. Good. Sorry. Had something on the screen here. So there we go. Andi, it looks like a little bullet. So and here we have. Sure that's what they show in the image. So I'm just coughing the image that they have. Um, but you can do your own image if it helps, but I like to kind of copies of these images that it helps me think it through. It's also just nice that someone helps you know you with your thinking. Okay. And so it is moving this way. Okay, because you know how Ebola is actually spinning, okay. And from about here to hear way have d and then here is beta angle beta. And from about here, Thio here we have C okay on eso now express the drag force due to the first couple system. And so the drag force is gonna equal thio um, de hoops That does not look like a d does it? Eagle thio d sign Beta minus w co sign Beta and I had okay. And, um okay, so can the drag force is an atmospheric drag force. Okay? And we need express the moment about G. So the moment here about G on that's gonna be expressed with m g equals D. Okay, let me make my I am sorry. I cannot write these today. Apparently. So D si side beta j hat. Okay. And now here the g is mg and distance between G is CP. Okay. And so we have the data equals beta equals three degrees. Okay. And express the moment about the mass center and express the moment and essentially has little hatchet m g equals thio. I inertia w Z minus anoosha. Bye. Co sign a data 552 different ways. Um, there are two different ways to write. Five. So you need to write by, like this or, um like this. I wish whether you can which other way I like to call this the Disney Fi. It looks like the Disney sig. Simple. Okay, sign data. And again, learning to write Greek letter is just right, um, but clear, precise everyone else, but kind of figure out which way you like for yourself. And so now we have to compare these two. So what we're gonna do is replace this here. Okay, so from that, we have d c sign beta J hat. And actually, we don't need the j hot here. Okay? And equals I the minus I by cosine data and yeah, I'm just saying the letters, um, because it's faster. Thio say the equation when I just do that. And so we're gonna call this equation three s. So we got to express the angular velocity here, and that's gonna be a capital five class little FYI, co sign data. Yeah, We're just gonna plug that in here. We're gonna scroll down. So we have d c sign they signed beta. Okay. Equals nurse Sha Times five plus little by co sign data. Okay. Minus I buy co sign data by sign data. And let's simplify this. So we have d c equals I Bye. Five. Um, plus A for the inertia five squared co sign data minus I five. Fire co sign data. And I believe, have I been riding down the thing? The longtime school time? Give me one second. Oops. And what we could do is actually replace this one up here with data. Because we did that here. Um, So since we've been placing that, here we go, Here we go. And this actually came to all of that, and that's what I was trying to figure out. Fix that and do this. And here we have d c equals I Bye bye. Minus I Inertia minus inertia. Five squared, co sign data. Okay. And so for this got neglect. We can neglect this term. And eh? So what we'll do is we have I Bye. Five is about equivalent to D. C. And so you're five is going to be about D. C. Over. Hi. Over Capital Five and way also have m equals weight over gravity. The mass. So we have £45 times 32.2 ft for a second squared equals 1.3975 I be squared and feet and this actually is equal to a slug. Here we go on where it's going to school down again on we can express the access Then. So we have the access thin from inertia here of em que busy square. And this is gonna be 1.3975 times two inches, which is times beat, divided by 12 inches squared. And in here we get 0.0 3882 slug be square. And now we can express your cap of five, which is the rate of spin as to pie in 60. So this is your weight of spin. Okay? Yeah. Here we go. And this one is two pi 6000 r e f okay, divided by 60. And we have 37 699 0.11 18 divided by 60. And we get 6. 28 0.32 radiance per second. Okay. And now weaken Dio is a and four A. What can do is we go back up to 25 on. We're using this equation here. So we're bringing that down here. Uh huh. And here we could substitute what? We have £25. Six inches times 1 ft, divided by 12 inches, Divided by 0.3882 Slug beef squared time 6 to 8 0.3 Thio lady in a second. Okay? And this is gonna equal thio 0.512 for radiance per second and we need to convert RPM. So it's 62 pi on is gonna equal to 4.89 r p m master rate of procession. So put rates No. Three session. Okay. And now for B. Yeah, we have to find the moment moment of inertia about K X, which is looks like this. And in here get 1.39 75 find a divided by 12 square equals 0.6211 slug feet squared. And, um, Now what we're gonna dio is plug it into, like, this whole thing into our equation that we had up above. So we're gonna plug it into this one right here. Yeah. Okay. I'll give you a second coffee guy down. Okay, so now I'm just gonna write it out. So we have 25 six inches divided by well eat walls and now right, 0.3882 Bye. 6 to 8.32 Radiance for second. It's not gonna put units here, so it saves us time. Why is the same units that I use up above here eso You should already know it. You can write them down. Helps you out. Okay, I'm just saving space. 0.6211 minus what's Oh e. I mean, it's that go minus 0.0 3882 times by squared times co signed to three Degrees Way. Don't need to make that that day. Here we go. Okay. So you can honestly town I would try to solve for this little bad. The five on was some simplified 12.5 equals 24.391 five minus 0.581 by square. And if we have it right, we have 0.581 I squared minus 24.3915 Mine bus 4.5 equals zero, And we could actually dio Oh, the classic formula here. Um, forget a formula just to help us. This is one of those formulas that you think you would never used to use. all the time. Physics. So remember it the nice Um, it's a really nice formula that a lot of Matthews is some reason even high up math. So it's a good one toe, remember? So we have 24.391 plus minus. Um, 24.391 squared minus four times 0.581 times 12.5 divided by two times 0.581 Yes. All right, five. Okay. And here we get 24.391 plus or minus. Um, 23.775 divided by 1.163 And from this you have 0.5189 radiance per second or 41.42 radiance per seconds. You're not quite done. So now we gotta convert these tow our PM. So we've been converted to R p M. And what we're gonna do is multiply both of these, Uh, bye. 60 two pi r p m radiance for a second, but you just multiply them each by bath. And so the first one you get 4.96 our PM and the second one we get 396 are Yeah. Okay. And those were your answers. Thank you, guys.

This scenario, we have a condom that makes on Anglo 55 degrees to the ground on to the end of the common is 10 feet above ground. We're extra body weight, me horizontal and vertical of the sons that a person would travel if there earn or a shot from the kind on with on initial velocity off 85 feet per second in a 4.3 their guns. So using over first you cradle identifying or the naughty is equal to be not is you call to 85 Beat for circled Vettel is equal to 55 degrees Andi time is equal to we're 0.3 seconds. So X is equal to 85. I was cost of 55 degrees times or point. These servants, you're really reaching that. That gives us your 100 on buying 0.6 or meet. So this really being the horizontal, the stuns I traveled proceeding to find the red tickle the stunts traveled your use you see creation that says that. Why's you Goto? Why not us? We not sign the little times T minus 16 t squared. Why not? Is equal to 10 beat? We not is equal gene 85 beat pressure pond their tires equal to 50 by decays Stage a beautiful on the time you still equal to work right? That punch therefore using or equation Why is a Capulet you and treat push 80 fryer I am sign of 55 times 4.3 minus 16 times four point me good Onda, pay attention to the fifty five hundred 4.3. The 55 is not multiplying. The other 55 was not multiplying 4.3 your into your body weight 85 sign 55 1st I'm then multiply Not right for 33 You're either waiting or expression we create on I should say Sorry, we get 10 US 200 on 99 point or minus your 95 coins A where Gadot's he called you 13 point 56 Thank you. Therefore the person traveled Vertical the stunt So 13.56 street Andi Uh, horizontal these times. Oh, you 100 on 9.64 feet. We were also asked to find the angle at which the person was shot. If they have an initial velocity on 75 feet for a second. If the distance off the how long from deem it is 175.5 feet on. If it took 3.5 seconds for them to heat the mitt, getting Teoh using or first equation again soon because we're finding the angle at which the person was during, we're going to solve our digital. Starving for a theater gives us X over we not to because equal to or stato taking the inverse of both sides. Bringing Kurt Us English the X over. We not I'm Steve. You see, hold to that at all on and we call that they said X was equal to, ah, 175 wait by Meet we not waas 75 feet per second on the time was. So wait five that hunts the Seattle Jekyll gene lost English of while on the 70 high point five over 75 times. Deeply troubled in putting us into a cocky little theater, l is equal to 40 age point. You're agrees to the nearest tent. Therefore we're angle is equal to 28 point you're give Utes

In this one, we're going to be able to relate the results from the ballistic pendulum to the results um that we're to find the initial velocity of a bullet that was fired at a at a block that's hanging from a pendulum that is on a pendulum and the bullet will embed itself in the block and will swing up to some height H. And we know from the previous example how to relate the initial velocity of the bullet to that height. And we're going to get a result based on some data that was given. And we're going to relate that to the same experiment done. But instead of using the ballistic pendulum, we're just going to use projectile motion to calculate the initial velocity of the bullet and we're going to compare the answers. So first we're going to plug in the values given into the previously known ballistic pendulum equation. And so we need to plug in the massive each Uh with each object for which we need to convert two kg. So we divide by 1000 in order to get from grams to kilograms. So the mass of the bullet will be 0.0688 kilograms Plus the massive block, which is .263 kg. And divided by .06 88 kilograms. All that times the square root of two times change and 9.81 m per second squared Times H. Which we need to convert to meters. To get from cm to m. You divide by 100. So this is 0.0 868 meters. You plug this into a calculator. You'll find that it's approximately 6.163 meters per second, apologies. 6.3 right ahead of myself, Approximately 6.3 meters per second. That's our first results using the ballistic pendulum. If we use projectile motion equations, we know that from automatic equations and protect our motion. That the equation of motion for the Y coordinate of anything moving through the air Will be negative. 1/2. T squared plus a term that relates to the initial velocity in the Y direction. But in this case our bullet is being fired exactly horizontal so there is no initial velocity in the Y direction. So that second term would be zero. Some B zero plus the initial height. We do the same thing with the X. We know there's no acceleration in the X. Direction. We're neglecting any resistance. And so this this will be the initial velocity in the X direction, which we can just label the same thing that we were able to answer over here. Visa one, I times T plus the initial X exposition. And we can move our coordinate systems such that this is zero. We can start at the origin wherever the X coordinate of the bullet, wherever it starts can be zero. And so we want to know what this is and what we can measure is the range of the projectile, which we also labeled as X. And we can also measure the initial height which we I will call by some zero and I'll call this max for the range. And so we want to know we want to be able to relate the range to this initial velocity, which we can do if we find the time at which the bullet hits the ground. And so we want to know when why Is equal to zero. And so we can just solve this equation. We know that one we want to solve for 11 half Gt squared is equal to Y sub zero, selling for tea. This would be the square root of two. White 0 over G. And we're only considering the positive square root here. Since we're not going to be considering any such thing as a negative time. And so we can plug this value into here. Or we can first, since we know that X when changes equation a little bit X max is equal to the initial, the initial call this T max initial velocity times time max or the range Is related to these two. So then we then know that the initial velocity is just the range divided by the time at which the range or the bullet gets to that range which is equal to X max Divided by the square root of two. poverty, which is exactly what is said in the problem. Just instead of X max, they have X instead of Y zero, they just have Wife. So we found the proper equation for the initial velocity of the bullet. And now we can plug in the data that was given. We were given that The maximum range was equal to 257 centimetres. Which again we're going to convert to meters divided by 100, Which is 2.57 meters. In The initial hate was measured to be 85.3 cm, which again divide by 100 to be 0.853 meters. If we plug these two into the above equation, we find that the initial velocity is equal to 2.57 divided by the square root of two times 0.853 All over G. Which is about 9.1. Plug this into a calculator. You'll find that that's approximately 6.163 meters per second. The value I accidentally vote earlier. So we actually find that we would get a lower velocity even though we would expect by both methods that we would find the exact same initial velocity since we're firing it the exact same way and that's where the difference might lie between these two values would depend on are approximations. In the 1st 2 ballistic pendulum problem, we assumed that we did not assume there was no friction. We took into account the friction and we didn't really make too many assumptions. We just use the conservation of momentum and energy, which are true under all of the assumptions that we made in the projectile motion case we neglected air resistance. But for a bullet that's traveling relatively slow, it can be in the air for a relatively long time and that's actually, it will be in the air regardless of its initial velocity, but air resistance could play a very significant role in its velocity. So if we neglect air resistance and we calculator, we measure what the range would be. It would actually be less than what it would be if we had no air resistance. So if the range is less. So if we look at this equation, if our range is lower, then it actually should be because we we experience air resistance in normal life, then the initial velocity will be lower, and that is indeed what we found. So we were able to calculate the initial velocity through two different methods but are approximations which were neglecting air resistance in the second case, turns out to be too significant to neglect

In this problem we are given function are which represents the distance and object travels up the inclined plane as shown in this diagram. So part A is asking us to show that these two functions are actually equal to each other. So therefore what we're gonna do is we're gonna start with giving information and we're going to distribute uh the expression in front of parenthesis to get rid of it. So therefore this the same thing as initial velocity square square root over 16 times. Co sin of theta and sign up to minus initial velocity square square root over 16 of clothes. Sine square data. So now if you remember that sign of two data, double angle formula is same thing as to sign of data of times, coastline of data. So if I divided by two then that's that's going to give us what coast annotated and saN of data equals two. So therefore this part, I can rewrite it as initial velocity square square root to over 16 times. So sign a data times co sign of data is same thing as a sign of two data over to and then minus initial velocity square square root over 16. And we know what co star square data is, which is one of the half angle formula that's equivalent to one plus co sign of two data over to. So now I'm going to get rid of this too. So there's the same thing as one half times 1/16. So therefore we give initial velocity square square to over 32 times sine of data minus same thing I'm gonna do one half times 1/16. So we have initial velocity square square to over 32 times one plus co sign of data Tuesday to So now I can see that both terms have in this velocity square square or 2/32. So I'm going to factor that out. So what we have left is a sign of data sign up. I'm sorry I forgot the tooth data here, sign of tooth data and then minus one plus co sign of tooth ato. And now what we're gonna do is we're going to simplify what's inside of parenthesis. So as you can see we have demonstrated that the function are Is equivalent to initial velocity square square to over 32 times sign of tooth data minus co sign of two theta minus one. And that's exactly what we were trying to prove right here. Okay, exactly the same thing. Sign of tooth data -2. Close and so it's exactly the same thing. So now next part B B is asking us to solve this equation Sign of two Theta plus co sign of tooth data equals to zero because solving for data will help us will help us find the angle data that maximizes that distance travel. So therefore the first thing I'm gonna do is I'm going to subtract close on the tooth data on both sides. So therefore we have signs of tooth data equals two negative co sign of tooth daito. And now I'm going to divide both sides by co sign of two Theta we know by definition sign over co sign the same thing. A tangent. So we have tangent of tooth data Equals 2 -1. And now what I'm gonna do is I'm going to let you equals two to feed. Okay so therefore I'm looking for Tangent of U. equals 2 -1. So you're going to look at the unit circle. So in order to get negative one the X and y. Is going to have same number where one is negative and one is positive. So therefore the two possible solution is when you is at three pi over four. Okay square to over to the by by negative square tool to it's gonna be negative one and then the other one is located as £7 or for the same thing it's gonna give you negative one as well when you look in the co sign and sign value. So therefore we know that you equals two three pi over four And uh seven pie all the four. So now we know what you equals two. So now I can substitute you into this equation. So this is three pi over four equals to two. Data. So when you divided by two so data is going to be equal to three pi over eight and then next one um I'm gonna let you equals to seven pi over four Equals to two. Data. Again divided by two. So data is going to be equal to seven. High Over eight. Okay. Now remember we have a domain restriction for this. Uh the domain restriction for this is that data has to be between 45 and 90°. So has to between 45° Between 45 and 90°. Okay. So therefore you can multiply this by 180 over pi to see how many degrees that is. And when you do that in your calculator You get about 67.5°. And next one same thing multiplied this by 180 over pie. So data in degrees is about 157.5°. So the only accept acceptable answer is that data has to be three pi over eight. That's the answer. This one can be hit. Okay because it's not in the domain restriction. So now we know the data. So questions see parsi is asking you to find The maximum distance if the initial velocity is 32 ft/s. So we know that from the from earlier equation we know that the function is equal to initial velocity square square root two over ah over 32 times sine of tooth data minus co sign of two theta minus one. So we're gonna plug in our data. So our data here is three Pi over eight. So we so and they give you the initial velocity which is 32. So you can have 32 squared square root of 2/32 times sine of two times 3 pi over eight minus co sign of of two times three pi over eight And then -1. Yes. So now we can simplify this. Okay, so 32 square over 32 is just going to give you 32, so therefore we have 32 square two times. Uh This is gonna be a sign of six pi over eight, which is the same thing as three pi over four, come on minus co sign of again, double that. That's the same thing as three pi over four And then -1. And now you can use your unit circle to find out what is a sign of three pi over four years. So sign of £3 before is negative. I mean it's positive square to over two and the co sign is negative square to over two. So therefore we have positive square 2/2 minus negative screw to over to And then -1. So now we're going to simplify this. So I'm going to make this as 2/2. So we have the same denominator, so therefore we finally have 32 square or two times the common denominator is too. So we have square two plus square too minus two. So therefore this gives us 32 Squirrel two times To school to -2/2. And we can simplify this even more. So that's going to give us 32 square two times to factor out the two. So that's gonna be to times square to minus one over to. So therefore the fraction is gone. So therefore we have 32 The Square two times the square to -1. And if you distribute the 32 square to, that's going to give you 32 times two -32 square root of two and 32 times two is going to give you 64. So therefore we have 64 -32 sq Root two. Okay, so that's your answer. Or you can leave it as Does the same thing as 32 times two minus square to. It doesn't matter which one you do. Okay. Both answers are correct. And if you want to in decimal the maximum distance is going to be 18.75. So now the last part is asking us to graph are subzero. Okay, graph are sub zero. So the so you're going to turn on your calculator And here's my our sub zero and I did not put you know 32 square the square or to over 16. Okay. You can simplify 32 square and divide by 16. You'll see that it's going to give you 64 square or two. So I tapping my functioning why one. And because this is a trick function, you're gonna press room seven. Okay. But we have a domain restriction. Your domain has to be between 45 and 90°. So you need to go to your windows after the graph is done. So go to windows and your ex minimum is gonna be 45°. Which is same thing and second which is same thing as pie divided by four. And it ends at 90° which is Pi over two. And then I'm gonna let the scale to be pi over eight. And then I know the maximum distance he is you know At least 18 point something. So therefore I'm going to make white maximum to be 20. And now you're gonna press graph again. So now let's use the calculator to find the maximum so second trace and choose four. And I'm going to move cursor left of the maximum little bit. Okay that's good enter. And then I'm going to move the right, passing the maximum point, enter Enter one Last Time. So according to the calculator, the angle that will ensure that the object travels the maximum distance. The angle is approximately 1.178 09 45 And then the maximum distance Is 18.745166. So text. Okay, so the angle is at 1.17809 ft. That's in radiant. And let's say that's the same thing as 23 pi over 83 seconds pi divided by eight. It's almost same. Okay. So therefore compared to our answers, B and C. Our answers were very close. So this is the answer we found from using our calculator. But by hand we we found is 18.75 And then the angle was three pi over eight.


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point) If 1 f(z) dz -3 and g(r) dr = 3, what is the value of f(r)ly) dA where D is the rectangle: ~3 < 1 < 1, 0 < y < 1?...
1 answers
Determine whether each of these functions from $\{a, b, c, d\}$ to itself is one-to-one. a) $f(a)=b, f(b)=a, f(c)=c, f(d)=d$ b) $f(a)=b, f(b)=b, f(c)=d, f(d)=c$ c) $f(a)=d, f(b)=b, f(c)=c, f(d)=d$
Determine whether each of these functions from $\{a, b, c, d\}$ to itself is one-to-one. a) $f(a)=b, f(b)=a, f(c)=c, f(d)=d$ b) $f(a)=b, f(b)=b, f(c)=d, f(d)=c$ c) $f(a)=d, f(b)=b, f(c)=c, f(d)=d$...
5 answers
Uesnon 14Find the binomial series representation for the If the series is written in the 'form A + Bx+Cx? + Dx' + give the value of DGuidelines for submitting numerical answers: 1. Only use numerical characters: ie: Enter the number without any units comm characters Enter the decimal value and round your answer t0 3 decimal places Using scicnbi
uesnon 14 Find the binomial series representation for the If the series is written in the 'form A + Bx+Cx? + Dx' + give the value of D Guidelines for submitting numerical answers: 1. Only use numerical characters: ie: Enter the number without any units comm characters Enter the decimal val...
5 answers
Colorationin the peppered moth (Biston betularia) dominant to m (light) determined by a single gene with two alleles: M (melanic) is In a sample of 1200 moths,you determine that 1008 ofthe Hardy-Weinberg rule; what is the moths are dark According to the expected number of moths that are heterozygous? 432489530576610
Colorationin the peppered moth (Biston betularia) dominant to m (light) determined by a single gene with two alleles: M (melanic) is In a sample of 1200 moths,you determine that 1008 ofthe Hardy-Weinberg rule; what is the moths are dark According to the expected number of moths that are heterozygous...
5 answers
(1 point) Suppose Rlis the shaded region in the figure, and flx,yXis continuous function on R. Find the limits of integration for the following itorated integrals. [s6wd4 = K" I" f6.ndydfkx,y)dA = K' I" fndxdy
(1 point) Suppose Rlis the shaded region in the figure, and flx,yXis continuous function on R. Find the limits of integration for the following itorated integrals. [s6wd4 = K" I" f6.ndyd fkx,y)dA = K' I" fndxdy...
5 answers
The ycar 2004 Ine worio nescnvcs olnaluralgus wuru upcroxmaldy 8015 trillion cubic focl nul sumu YculInc worio consumption onnalurulaus wus approrimutel 1.990 per year: If the demand continues grow at this rate nettesenes naice gas are iound what year will tne word reserves this resource depleted?Irillion cUbr Icul und wus grounnn UrdonuniallyaboulThe world reserves will [ depleted in the yea (Round Iha nearos yuir needed )
the ycar 2004 Ine worio nescnvcs olnaluralgus wuru upcroxmaldy 8015 trillion cubic focl nul sumu YculInc worio consumption onnalurulaus wus approrimutel 1.990 per year: If the demand continues grow at this rate nettesenes naice gas are iound what year will tne word reserves this resource depleted? I...
4 answers
Delerine Uheher th senvs Coras or divecges1 + #7 + 37 +44 & 4 4
Delerine Uheher th senvs Coras or divecges 1 + #7 + 37 + 44 & 4 4...
5 answers
Quarterback throws a football with angle of elevation of 40"and speed of 19 m/s_ [1] Draw vector diagram of the situation: b) [4] Find the horizontal and vertical components of the velocity vector
quarterback throws a football with angle of elevation of 40"and speed of 19 m/s_ [1] Draw vector diagram of the situation: b) [4] Find the horizontal and vertical components of the velocity vector...

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