GanWhlch oethe Itc Hucminai Mennne odilnxucdumpuna InotusAput DenaTheeouttonorey lor ttie movemont 0l Ilie potassium Irto Vha coll, aatection the 0* Ur1ao AIP hxtto...

IUPAC namc of rhe compound $\mathrm{K}_{3}\left[\mathrm{~F}_{\mathrm{C}}(\mathrm{CN})_{5} \mathrm{CO}\right]$ is (a) Potassium pentacyanocarbonylferrate (III) (b) Potassium carbonylpentacyanoferrate (III) (c) Pomssium penracyanocarbonylfertare (II) (d) Potassium carbonylpentacyanoferrate (II)

So in this problem, the half life off Basham progression 40. It's equal to Eunice 1.27 gross stinky power nine years when you convert it into skins. We helped by 1.27 Crossed a couple nine with 3.156 crossed innkeeper. See one Because in one year you are stupid One fax exporting for so scared. So half life off progression 40 is equal to 4.0 Cross stinky power. 16 skins. No, we're given the mass off professional ride in the simple physical too. One kg further. Yeah, you're right. Molecular myself. Guess it depression, right? Must both profession, right? Is that correct? 74 point double five jumper money as the no date off. My life is equal to it into Do you read it by to get constant. So we want to find the cake. Monster can do so by the Iranian aggression. Get decay. Constant is true, Ellen, To divide by half life this absolutely or your half life in the question which is a good to 4.0 cross stinky power. 16 scans. When we saw this, we get decay. Constant is equal to 1.73 Cross didn't keep over minus 70. First again. No. We'll find number off. More off. The passion will ride in one kid You, by using informal back number more physical, too. Must do it by more enormous. This mass is a kilogram of physical 2000 Graham in the mult. Enormous off Jesse L is equal to 74 point double 5 g Permal. So will this all this to get 13.4 moles off? Yes, I shall write anyone. Kitty, you'll find number of molecules only killed off Passion Parade. It's a quick too. And which is God? Took number of moles multiply by. Well, that resident there is. You know number thwart is equal to 13.4 and your god rose number is equal to 6.2 across. Thank you. Power 23. So number of molecules off gas yell oppression correct in one cage is equal to when you saw this. You get eight point 08 Cross stinky power. 24 molecules is one molecule off. The passion chloride contains one. It, um off profession so we can find a number for passion. Mickens number of passionate and will drop this actually number off the pressure Midterms in one kg is equal to 8.0. It cross stinky power. 24 victims Is that elected governments off profession 40 in nature is good too. Is it a point? No zero to person. So number off depression 40 victims in one kg is equal to 0.0 to multiply by 8.0 It crossed inky power de for we get in breath pressure 40 It comes in rickety off oppression Career physical too. Nine point 69 Cross stinky power 19 e P A. No. Yes, we are given, Nick, we finally 89% off profession 40 years and it gives gives beat a mission. So number of emissions retain nations from simple off one key Pleasant ride you to the care profession. 40 physical toe 0.89 Multiply right nine point 69 Cross stinky power 19 We saw this. You get it Won't six to gross dinky power 19 Because no, we'll find Do you like me? You give me enough beta particles. Impression 40 is equal to there isn't a formula. Yeah, into the cake constant as in is equal to. And 162 was taking power in 19 because and and raise equal to one point 73 cross. Thank you. Power minus 17 person. So we get activity is equal to 1491. The case per second, which is a Quito bakery. This is the answer to your question.

Yeah. Question number 1 21 on. To calculate the rate constant, we will use the equation that relates to the half life. And so the red constant so t half life equals 0.693 divided by K On board the second one will be 1.25 Multiply 10 days to power. Nine white equals natural. Log off to divided by King. We can substitute the value off K equals 5.55 Multiply 10 days to pour negative 10. Que represents the rate constant. Now further, we need to calculate the particles off here. 40 positive. In this case, we need to use the molecular marks off. Casey L. The avocados number on style Commentary off kecil. So calculating. We have 1 g off castle multiplied with one mole off castle divided by 74.6 g off kecil multiplied with avocados. Number by one mole off castle. One particle off que positive divided by one atom off. Case here now canceling of the values The status Phone 6.2 Atoms off Casey L So on. The number of particles turned out to be 8.7 multiplied 10 days to power. 21. This represents the number off particles off potash in positive. Since the abundance off potash in positive is so since the abundance off Natasha positive is 0.117%. We will multiply the number off irons, the we will multiply the number off irons, which is 8.7 Sorry. You know, uh, eight point zito seven, multiply 10 days to power. 21 wait zero point Zito. Zito, um 117 toe. Find the exact particles off petition. Positive. Fine. In this case, solving we have nine point 44 multiple night, 10 days to power. 17 particles present. Moving on to the next step further, We need to calculate the number this integrations. In this case, we need to convert the date constant two seconds, two per seconds. So we already have the late constant, which is five 0.55 Multiply 10 days to power. Negative 10 no one by ear, multiplied by ear by 365 days off a year. 360. I'm sorry. Then we have one day divided by 24 hours multiplied with one hour divided by 16 minutes multiplied with one minute divided by 60 seconds. Calculating the number off this integrations, the raid constant per second turns out to be 1.76 multiplied 10 days to power. Negative 17 for a second. Finally, we multiply the number of particles we have with the rate constant per seconds. So taking the weight constant and multiplying it with 9.44 10 days to power 17 particles. We have the number off disintegration. Xaz 17 decays for a second.

On adding k n 02 N CS three Ceo at solution to the neutral solution of c o c r two there is the formation of yellow orange precipitated of K three C o n O to hold six. So just look at it carefully. I'm writing the reaction six KNO two plus CS three she oh edge plus ceo cl terry will react to form, get to the see all And or too old. six plus two K C L CS Teresi. Okay. Plus half I stood therefore according to the option in this problem, option C each correct answer.

Hey, guys, let's do problem 99 in this problem, the average atomic weight of what a shame is given and its three naturally occurring I start ups. Maximum mess is also given, and only the percentage abundance off partition with 41 mass number is given. Now we need to calculate the percentage dependence off the other two, the other twice eaters. So let us write down the information that is given. The first information given is the atomic weight off photo Shame and the other two informations are the the mass off each three off the Assad jobs, which are region here, and only the percentage abundance off the petition with mass number of 41 is given, which is 6.73% age. No, we need to figure out what is the percentage of abundance off audition with mass number of 39 40. So we know the total natural abundance off any element is 100% age. Therefore, we can write down the one. The first run is having the national abundance off say later we can take any Number X, and the other one then should have the natural abundance off 100 miners, 6.73 minus X. So we need to figure out what is developed X and then we can calculate what are the national abundance off? 39 K and 40 days. They just right on one thing. 100 minus 6.73 means 93.27 Okay, so these should be done. Natural abundance of these elements. No, we know that atomic weight is the weighted average off done masses of national organizer troops. What does that mean? That means that Adamik wait is the some off the It is the sum we need to take the summer off. The abundance off any isotope multiplied by its mass. Therefore, abundance off. I set up. What a shame I started with my similar 29 divided by 100 multiplied by mass off this I sort of. And when we take the summer off the similar thing for all the three and sit ups, we get that to make weight off that element. Therefore, abundance off petition with mass number 40 divided by 100 multiplied by the same it's mess and then when it trade and take the same or some abundance off petition with US number or 41 divided, 100 multiplied by its mess. Now most of the informations are given. Most of the values are given. We need to calculate eggs. Let us place the numbers that weight off for the shame is 39.98 in you. Evidence off petition with mass number 39 is X divided by 100. It's I started with Mess is 38.964 Hey, emu, then we need to take the some, then the abundance off petition with mass number off 40 es. The evidence is 93.27 minus X divided by 100. We need to want to play the whole thing with I set up smells, which is 39.964 and finally 6.7 20 very 100 multiplied by 40.962 am you Now we need to do this simple calculation. We can use the calculator and just please the numbers. How can I 0.98 a. M. U and I just went to divide this a mess by 100. Therefore, it will be 0.38964 x I am you. Then let's break down this part. If you break it down What we will get ease. 37.27 am U minus 0.39964 in you. And finally the last room. This one, we'll give you two point 757 in you. Now I will take the values reaching having eggs on the left hand side off the creation and the other one is this one. This should be our next. So I will just take these two on the left hand side which will re 0.39964 minus 0.38964 x in you and in on the right hand side. What we believed with is 37.27 I am you plus 2.757 I am you and minus this one will go to the right hand side. Therefore, there should be a minus sign before how to 9.98 AM you then what we even get is finally if you do the calculations zero wine 01 x in you each other zero point 9 to 9 he and you. Therefore, what we can say is we can say is X equal to 0.929 divided by 0.1 which is 93% age. Therefore, the natural evidence off. What a shame with 39 mass number is 93 percentage. Therefore, the other one with mass number of 40 should have the value off 93.27 Minus 93 equals you zero point 27 or we can say that it is 0.3 percentage. Therefore, our answer to this problem is the percentage abundance off rotation with 39 mass number is 93% age and the other one with 40 mass number is 0.3%.