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Your calculations Your work should be clear to get a Iul For the following problems You must show all credit 2 H2O(g) the following data given at 25 %C: 2 H2S(g) +...

Question

Your calculations Your work should be clear to get a Iul For the following problems You must show all credit 2 H2O(g) the following data given at 25 %C: 2 H2S(g) + 3 02(g) 5 2 S02(g) For the reaction: -296.8 -121.8 AH%f (kJlmol) -189.6 162.2 188.8 s"(Jmol-K) 205.8 214.2 Calculate the standard Gibbs free energy change AG" at 25*C (10 pts:)one sentence. (2 %) b) Is this reaction spontaneous? (2 %) Why? Explain into calculate the equilibrium constant for the reaction above; If you are is

your calculations Your work should be clear to get a Iul For the following problems You must show all credit 2 H2O(g) the following data given at 25 %C: 2 H2S(g) + 3 02(g) 5 2 S02(g) For the reaction: -296.8 -121.8 AH%f (kJlmol) -189.6 162.2 188.8 s"(Jmol-K) 205.8 214.2 Calculate the standard Gibbs free energy change AG" at 25*C (10 pts:) one sentence. (2 %) b) Is this reaction spontaneous? (2 %) Why? Explain in to calculate the equilibrium constant for the reaction above; If you are is one complete less than Or equal 1 ? (3 pts-) Explain your answer would this Keq" be bigger thanl_ sentence



Answers

Both the forward reaction and the reverse reaction in the following equilibrium are believed to be elementary steps: $$ \mathrm{CO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{COCl}(g)+\mathrm{Cl}(g) $$ At $25^{\circ} \mathrm{C}$ the rate constants for the forward and reverse reactions are $1.4 \times 10^{-28} \mathrm{M}^{-1} \mathrm{~s}^{-1}$ and $9.3 \times 10^{10} \mathrm{M}^{-1} \mathrm{~s}^{-1}$, respectively. (a) What is the value for the equilibrium constant at $25^{\circ} \mathrm{C} ?$ (b) Are reactants or products more plentiful at equilibrium? (c) What additional information would you need in order to decide whether the reaction as written is endothermic or exothermic?

In this given chemical reaction, three molecules of a reacts with one molecule, er B to produce two molecule of C and one molecule of D. One thing we cannot hear that is in gaseous state. B is in pure solid estate, while C and D are inadequate state. Now, after the, after this reaction has achieved equilibrium, their concentrations in terms of mood or more clarity is given in the problem. So is 2.48 mol B is 2.41 mole C has the concentration 1.13 Mueller, and D has the concentration 2.27 Golden. So these are the datas are the equilibrium values Now in the problem, it is also mentioned that volume of the flask in which the a gas has filled. The volume is 1.87 liter. And we have to find equilibrium constant for this lee Jackson. So first of all, we will we will convert all the concentrations in a single unit, since C. And they are already in Mueller units. Therefore we will convert the concentration of a also in Mueller unit. So how Mueller unity is achieved for that. We divide the moral values with the uh most by volume. So here for a the mole is 2.48 moles divided by volume is 1.87 later. So this will be the modularity of I guess now the question is how we will write expression for Casey or equilibrium constants. We know that while we write the expression for equilibrium constants, we neglect the pure solids and pure liquids here. Pure solid is present and that is at um be therefore we will neglect its concentration since its concentration will not change with time, it will be always unity. Now, first we enumerated, we write the product concentration 1st. So what is the water? The products that are C&D. Now the power of these concentrations will be their corresponding coefficient. Now, coefficient of CS two, Therefore, concentration of C will be squired and coefficient of D is one. Therefore there will be one in the power of fish, in the power of the concentration of D. So this will be divided by the concentration of reactant and there is only one reactant since we are neglecting the concentration of be it, since it's a pure solid. Therefore, concentration of A. And its coefficient is three. Therefore it will go into the power of A. So this is equal to now we can put the data's of their concentration values at the equilibrium. So C. Is one point 13 Mueller police square and two D. Has the concentration 2.27 Mueller Divided by concentration of a. That is 2.48 divided by 1.87 whole cube. So from here we get the value of Casey that is equals two, one point 242 So the correct option is option E. That is one point 24 so this will be the answer for this problem.

Calculating the eagerly broom constant from immigration. Delta G equals negative Artie off natural log Delta G is Gibbs Free Energy. He is the temperature, and our is the gas constant. We have time. Preacher in degree senses 25 degree senses to convert any time preacher into Kelvin. We just have to add 273.15 Adding this we have 298.15 degree. Kelvin asked him, Preacher for auction e Considering the reaction between oxygen on Florin, the equilibrium constant that is natural log off gay has to be calculated, substituting in the values into equation. We have lnk that is natural. Log off K equals three point 71 now taking anti log on both side to cancel out natural log. We have equilibrium. Constant equals 41 for option B using the same equation the nuts, the natural log off. Kay turns out to be negative off 2.945 and taking anti lock. We have value equilibrium Constant 0.53 for auction seat. The natural log equally. Bloomie's 31.870 on taking anti lock. We have value off equilibrium equals 6.9 into 10 days to about 13. For Option B, the value is 0.0 six 45 Taking Andy Look, The equilibrium constant is 1.9 for Option E. We need to substitute it. Calo Jules Mole for the elegy on 8.314 Jewels for More Kelvin, for our by the temperature is 298.15 Calvin, using the same immigration as shown Auntie taking and taking anti log on both side. The equilibrium constant for this reaction turns out to be 0.0.

Okay, so the reaction here is three a. Which is a gas because B. Which is a solid gives us to see which is a chris and D. Which is Aquarius, I'm not gonna worry about are solid. And let's let's work with everything in polarity here at 1.1, 3 more And 2- seven more. And for a, I'm told that I have 2.48 moles And that's going to be in our volume of 1.87 L. That's gonna be 1.33 moller. And that's true at equilibrium. So we'll go ahead and write RK for this. It's going to be the concentration of C squared time's D. All over the concentration of a cube. Okay, We're gonna ignore because it's a solid. So we'll plug in our concentrations at equilibrium. We need them all to be in polarity. So we're going to get a K. c. here equal to 1.23. So that's going to be answered. A.

So this question asked us to calculate the equilibrium constant. And so we're gonna actually have to derive a formal from that for that, for something with body wouldn't give it well, this formula. And so we're basically just going to go through 100 steps to solve for Katie Que In order to get a formula, we're gonna take a lot of cake. You, and then are going to take anti law, which usually means taking it. Raising it. Um, Toby 10 to the power off. Negative Delta, gee, divided by 2.303 times our teeth here we know T is at 2 98 Kelvin, or room temperature. That's 25 degrees Celsius. And R is this constant of 8.314 joules per mole for Kevin. So again, it's pretty much just plugging chug because they give you all the information we know are we know T. And the question for each part gives us this Dalton She thought so. First for parking. The Delta G standard off negative 10,880. Jules, we're going to get a equilibrium constant of 80.57 movie on Same thing Delta G standard e equals 3400. Put it into the equation at the beginning. And you're any at 0.25 Equilibrium, constant here with ability. Stared equal to negative 3 9000 We're gonna get 6.81 times 10 to the sixth. Has a good room. Constant. Um, parte de delta G stare is negative. 14,001 are sorry. Negative. 141,820 jewels. Put that into the formula at the beginning of this video unit. Get seven. Court, go through tough times. 10 the 24 and last, but not least with Nick with adult G standard of negative. I wouldn't have any 100 individuals you're going to get Get the red 10 very at 2.13 as your equilibrium constant. And because he's equilibrium, constant, they're not gonna have any units associated with, um so just leave it that way back. And that's your answer.


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