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[-/1 Points]DETAILSOSCAT1 7.2.124.MY NOTESPRACTICE ANOTHERThere Hn Hatunna the top of bulldlng From Jlocation 600 feet from the buse of the bullding the angla of el...

Question

[-/1 Points]DETAILSOSCAT1 7.2.124.MY NOTESPRACTICE ANOTHERThere Hn Hatunna the top of bulldlng From Jlocation 600 feet from the buse of the bullding the angla of elcvation tnc tOp tho bullding Tuasured From tha sume location; tne onglg clevatlon t0 the top of the antenna mcdsurcc be 430 Find the height of the untcnnj (Round Your answer t0 threc decimol placcs:)Addllional [email protected] Dulaln Length = Ropht Trlangla Side Ledm E Exomplo[-/1 Points]DETAILSOSCATI 7.2.126.MY NOTESPRACTICE ANOTHERJa

[-/1 Points] DETAILS OSCAT1 7.2.124. MY NOTES PRACTICE ANOTHER There Hn Hatunna the top of bulldlng From Jlocation 600 feet from the buse of the bullding the angla of elcvation tnc tOp tho bullding Tuasured From tha sume location; tne onglg clevatlon t0 the top of the antenna mcdsurcc be 430 Find the height of the untcnnj (Round Your answer t0 threc decimol placcs:) Addllional Materlala @Boor Dulaln Length = Ropht Trlangla Side Ledm E Exomplo [-/1 Points] DETAILS OSCATI 7.2.126. MY NOTES PRACTICE ANOTHER Ja-It ludder leans Hominsi bullalng 50 that the angle bet veentn0 ground and the indder Indder I%och Up (hu Elde ol thy building? (Round Youi unswor t0 (our cecim places;} How high does Ine Addiliont Mntenals Dd e8cok Detenlre Longth al Right Triang & Side" ICnm Dy Example



Answers

There is an antenna on the top of a building. From a location 300 feet from the base of the building, the angle of elevation to the top of the building is measured to be $40^{\circ} .$ From the same location, the angle of elevation to the top of the antenna is measured to be $43^{\circ} .$ Find the height of the antenna.

Hi Agreement. This is the problem based on production off electro magnetic tapes by an antenna experiment performed by the hearts as well as by Marconi. So for this problem, we have to calculate the height off. Marconi ending up required for transmission off radio broadcast at frequency off 5 60 clo hearts and 1600 clots. Part a babe lent off signal to be transmitted is shit. See upon F C. Is the speed off light on f is the frequency 5 60 chlorides 5 60 in 2000. So you will get 5 36 m. So height off angina is 1/4 off prevalent. 5 36 upon four. That is 1 34 m on for a second. They can signal having the frequency. Lambda is called toe three into 10 to the power eight upon. Okay. Okay. 1600 kilohertz. So it would be Yeah. 1 88 m hence. Height off. Antenna enquiries. 1/4 off a village that is 46.9 m. That's all for this problem. Thanks for watching it

In this problem. We have a building with an antenna on top, and then we have a point that's 300 feet from the base. So suppose this is my point. And this is 300 feet. And here's my building. And here's my antenna. Okay, So what else do we know? We know that the distance between the point and the base of the building is 300 feet, so we can label that. And we know the elevation angle of elevation to the top of the building is 40 degrees, so that would be our angle right there. And we also know that the angle of elevation to the top of the antenna is 43 degrees all the way up to there. That entire angle is 43 now, making the assumption that the building and the ground are perpendicular. We have to right triangles, the bigger one with a red side and the smaller one with blue site. So ultimately, what we want is to know the height of the antenna or the the yet just the height of the antenna. So the easiest things to find in this problem are the height of the building which I'm going to call X and the entire height of antenna plus building, which I'm going to call. Why? So if I can find X and I could find why, then I'll get what I want. Which is why minus X, the height of the antenna. Okay, so let's start with the big triangle and that has the red angle 43 degrees and we can write the equation. Tangent of 43 degrees equals. Why over 300? So why is 300 tangent 43 and then we can switch over to the smaller right triangle, which has the 40 degree angle, and we can write the equation. Tangent of 40 degrees equals x over 300. So x is 300 tangent, 40 from there. Remember, what we want is why minus X So why minus X is going to be 300 tangent 43 degrees minus 300 tangent 40 degrees and we could put that in the calculators to approximate it and we should get just about 28.2 feet

For this problem on the topic of electromagnetic waves, we are told that the figure shows us a hurts antenna. And most AM radio stations use a MArconi antenna, which consists of the top half of this hurts antenna. The lower end of the center is connected to the ground and the ground serves as the missing lower half. We want to know the heights of Marconi antennas for radio stations broadcasting At 560 kHz and 1600 kHz. Now, we essentially want to find firstly the wavelength lambda and we know linda is equal to the speed of electromagnetic wave. See over its frequency F. And we know This to be 500 and 36 meters Using a frequency of 560 kHz and C3 times 10 to the eight m/s. And so the height age, he is equal to lambda over four. And so This is 100 and 34 m for a radio station broadcasting at 560 kHz. Now, for a radio station that is broadcasting At, 1000, kHz. Again, we have lambda is equal to see over F. And we get the Waveland Of this radio wave to be 188 m. And so the height age of the marconi antenna is λ over four, and this is 46.9 meters.

In this problem were given if one is equal to 560 kilohertz, which is equal toe 560. Multiply will take about three hurts and the frequency toe is given US 1600 kilohertz which is equal toe 1600. Multiply by. Thank you. Power three hurts Now we will find in the first part will find Linda one by using from the sea divide by a fun physical too three Multiple We think about eight divided by 560 Multi. Thank you. Power three we get Linda. One is equal to 535 127 m now in order to find height often, Tina, we will use for my physical toe. Linda one divided by four, which is about 535.7 liter. Divided by four we get each one is equal to 133.3 m. Is the answer the first part of the question in the second part, But we will first find we have lent to which is a good to see. Devoured by F two C is three multiplied by taking power. Eight. We taper skin divide the after a 1600 multiple. Um, I think for three herds we get Lambda two is equal toe 108 7 point 5 m. Now, in order to find H two will use formula Linda to do it by four his lumber to his 107.5 m dread. By four we get S two is equal to 46 point 875 m the height off. And Tina too. Which is the answer, The second part of the question.


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