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C CHEHICAL REACTIONS Finding molecular formula from molar mass and elemental anal_Compound X has molar mnass of 86.09 mol and the following composition:clement mass...

Question

C CHEHICAL REACTIONS Finding molecular formula from molar mass and elemental anal_Compound X has molar mnass of 86.09 mol and the following composition:clement mass %carbon55.81%0hydrogen 7.0290oxygen37.1790Write the molecular formula of XExplanemcnchecSCarci

C CHEHICAL REACTIONS Finding molecular formula from molar mass and elemental anal_ Compound X has molar mnass of 86.09 mol and the following composition: clement mass % carbon 55.81%0 hydrogen 7.0290 oxygen 37.1790 Write the molecular formula of X Explanemcn chec SCarci



Answers

The molar mass and empirical formula of several compounds are listed. Find the molecular formula of each compound.
a. C4H9, 114.22 g>mol
b. CCl, 284.77 g>mol
c. C3H2N, 312.29 g>mol

So here we are, given a list of different chemical compounds and were asked to determine the molecular formula from the empirical. So for our first compound were given a molar mass of 186 g for multi, and our empirical formula is C. Six H seven N. So we first find the molar mass of C six H seven and the unit and we find that the molar mass is equivalent to 93 g per mole. So that would mean that we would have two times of the empirical formula. So this becomes C. 12, age 14 and two. And we're going to repeat a similar process for other compounds. So for our second compound we have a desired molar mass of 181 g, promote and we have C. Two hcl. So the molar mass of this empirical formula would be 24 plus one plus 35.45 And we can find that we can be divided by total molar mass by the molar mass of the empirical formula. There's approximately three empirical formula units. So this becomes C six H three, C L three. And we're going to repeat this process for our last compound and the empirical formula unit C five, H 10 and S. Two. And we're giving information that the overall Mueller mess that we desire is 296.54 g per mole mm. And the empirical formula, the molar mass of the empirical formula, structural unit, yeah, is equivalent to about 148. So the contribution would be essentially too. So this would have a final uh this will find have molecular formula of C 10, H 20 and two S four. And these are final answers.

In this situation, we have an unknown compound made up of these four elements. I'm listing carbon, hydrogen, nitrogen in oxygen. All right. And we've been given the total mass of these four compounds to be one point to see life. Six, 8569 grams. This is the mass of this unknown compound made up of these moments where we're to find the molecular formula of this copper. What? We We've been given the mass of each element. Yeah. So in this column here, I'm gonna write math. It's so for carbon. We have 0.2 0.7238 grams compound. Just meet up with this. Wait. Carbon for hydrogen. It zero wounds zero 7088 grams for a nitrogen. It 01 for, 07 grams. And then for oxygen, it 0.3 214 Gramps. And then we already have the total at the bottom. Oh, So how are we can't find the molecular for to find the molecular formula. We need to know how much of each Adam is present. So we used to know the ratio. The other. Each element is in relative to one another. so to find that we need to work in walls in the equation for moles, formula is mass divided by molar mass capital and all right, Sarge, gonna about, uh um Gerada table and divide these masses by the molar mass of each element. So for carbon, it's this mess over 12. I went, 01 grams per mole. And here I'll just list out what the calculation equals. So is your plaint. Six year, two moles, carbon certainly have for hydrogen will take that mass over there and divided by one. Well, basically equal 2.7. When then, If we use all the 66 we can get a more accurate number. And for a nitrogen, take this number and divide it by forging grams per mole. That gives us 0.1 the oxygen Take this number and divided by 16 grams per mole and we get 0.2 So all right, here we have the molar ratio of each. Um, when will our amount of each item in this compound So this could be the sub scripts we used, but we need to work in integers. In order to do that, we will take our smallest number here and divide it. But each of these other numbers to find, like what? The whole number issues and will assign the smallest number to be one. So what we'll do now is take 0.2. You want me say divide I zero point 0.1? Yeah. Take these numbers of highway 0.1 to find, you know, an integer value. So then, for nitrogen, we would get one just 0.1 about by sequins. Everyone I hear believe need a cartel later. Supine 02 divided by 0.1 is simply too. And for Urban 56 I just wanted be seven relatively. So there we have it. These are the sub scripts for this, um, compound. All right. Here. So it was carbon six hydrogen, seven engines, one nitrogen into oxygen's. This is our compound

All right. So, um, in this question, we have an unknown compound made up of these four elements where you're trying to find the molecular free. Okay, so here we've been given the mass of each element within the compound. So for carbon, it was 0.299 Corey ums, It's his own units of grams. Just bracket up top there. Haejoo, We've been giving 0.5849 grams for a nitrogen. We've been given zero point 2318 grams and oxygen this 1.3 to 8 grams. Okay, so are for us to find the amount of each element present to write the month of formula, we need to know the ratio of, like, how much of each Adam is there. So to find that ratio, we can't work with mass. We must use malls in the units more. Okay, So in order to find moments, we simply take maps and divided by Miller Mus. Right? Okay, so you know the molar mass of all of these Adams by looking at the our periodic table sold just taken this mass and divided by the molar rats. And here's what we get so for up for carbon, we take 0.2 to 9 grams and divided by the 12.1 grams per mole. And we get to a point zero or zero points your tooth for 89 moles engine. Take this number whether by the one gram per mole recently get 0.58 Your 0.0 58 0 to 9 for an estrogen will take this mass and divide it by the 14 grams. Mol, when we get 0.16 55 and for oxygen, we take this mass and divided by the 16 grams per mole. And then we get quite a small number 8.3 times 10 to the exploding negative three. Okay, so then we could use these numbers for the mullahs, Max, but not for a moment for the molecular formula. But we need to work and introduce values. Therefore, we must divide each of these moles by a constant, you know, trade into entered your and my constant that we will use is the smallest mole quantity, which is this oxygen case will take each of these malls and divided by the by the 0.8 by the 8.3 times. Tend to the negative three. So this will effectively, um, take this these molds here in tournament whole positive numbers. So we know for oxygen that would make it give it a one for nitrogen. Got a two. Once we do that division for Haijun, it's seven and oxygen of three. See? And it's with these numbers that we can form our molecular formula. It's carbon three hydrogen, seven nitrogen to with the one oxygen, Yeah.

Good day. In this question, we will know the molecular formula of the Cuban compounds. So in order to know this, we used the molecular formula is equal to the empirical formula or the simplest form of the compound. What they applied by an where N. Is equal to the mother must given Andy empirical formula must and is the ratio of the mother must given. And the empirical formula must. So you see this we will substitute be given parameter is so for a letter A. We have and Is equal to the given mother Mas is 114.22 from the spare more, divided by the empirical formula must. Obviously for H language is 57.13 from sperm all will give us to. Therefore molecular formula is equal to See for age nine times two Which is four times 2 is eight And nine times 2 is 18. Next for letter B. We have and is equal to 284.77 from sperm all the mother must given invited by the empirical form enemas, Which is 47.46 g per mole Will give us six. Therefore the molecular formula yes, Equal to c. c. n. Times six. Well, give us C six cl six. And lastly, or let their C. We have and equals 312.29 g per bowl where the Mueller was given. And the mother must of the empirical mas of c. three H. 2 and is 52 by serial six g per mole. This will give us six. Therefore the molecular formula Is equal to c. three H two and time six. Well, give us C. 3 13, 6, 18 To a time 6, 12. And and Sheiks. Thank you.


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