5

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Question

Aje ejoqeued Mau 341 Jo} Xala^ a4140 SaJeuipJoo)WPJFm8sun + Kq UMOp pa1llys uay1 pue 8 jo Jopje} Aq payniaJls squn L 1464 paviys (x) fs1 (x) 3 eoqejed Mau a4} Jo} Xalia 341 j0 SaJeuIpJOOD a41 8N5 (r) [uo SuopeuoJsuen buImoljoy 841 bujuuoyad Aq 4 + r)o = ( Wo} 841 Ui uoiduny Mau & 818313290 uonisano '97* 8 SDI4Qu3v eJqaDIv '8 jaidey)

aje ejoqeued Mau 341 Jo} Xala^ a4140 SaJeuipJoo) WPJ Fm8 sun + Kq UMOp pa1llys uay1 pue 8 jo Jopje} Aq payniaJls squn L 1464 paviys (x) fs1 (x) 3 eoqejed Mau a4} Jo} Xalia 341 j0 SaJeuIpJOOD a41 8N5 (r) [uo SuopeuoJsuen buImoljoy 841 bujuuoyad Aq 4 + r)o = ( Wo} 841 Ui uoiduny Mau & 818313 290 uonisano '97* 8 SDI4Qu3v eJqaDIv '8 jaidey)



Answers

As we've seen, Eq. (7.33) describes the beat pattern. Let's now derive a different version of that expression assuming that the two overlapping equal-amplitude cosine waves have angular spatial frequencies of $k_{c}+\Delta k$ and $k_{c}-\Delta k,$ and angular temporal frequencies of $\omega_{c}+\Delta \omega$ and $\omega_{c}-\Delta \omega,$ respectively. Here $k_{c}$ and $\omega_{c}$ correspond to the central frequencies. Show that the resultant wave is then $$E=2 E_{01} \cos (\Delta k x-\Delta \omega t) \cos \left(k_{c} x-\omega_{c} t\right)$$ Explain how each term relates back to $$E=2 E_{01} \cos \left(k_{m} x-\omega_{m} t\right) \cos (\bar{k} x-\bar{\omega} t)$$ Prove that the speed of the envelope, which is the wavelength of the envelope divided by the period of the envelope, equals the group velocity, namely, $\Delta \omega / \Delta k$.

Hello students in this question we have given that dale e divided by telex. It is equal to minus, They'll be divided by delta T. It is applies to harmonic vector. So the vector, it is equal to the note. Of course K x minus omega t. And be vector. It is equal to be not vector cost of K x minus omega T. So which eaves that he not calls to C b, not? We have to show it. Okay, so hence we can write that this situation from here. So differential differentiating the situation with respect to this X. So we will obtain that minus E note signed of K x minus omega T. And molecular by this case. Okay. And this will be equals two differentiating this. Be vector with respect to this time. So we will often from here that this minus sign. Okay, and due to discuss the differential differentiation will be minus of sign, be not and omega and then K X A sign of Oh, so this differentiation will be equal to be not manipulated by omega sign of K x minus omega t. Okay, so from here, after rearranging, we get from here, this signed K X minus omega T. And this annex this will be cancelled out. So from here we get minus C. Note, it is equal to from here we get the not particularly omega. So now taking the magnitudes only another minus omega will also be there, so minus omega will be there, so this will be cancelled out. So we get from here is not, this is equal to see more clearly. Uh this cave will be there. Okay, so this can be written as omega K. Molecular Beano and this omega bike, it is the speed of the wave and here it is, the speed of the wave that is C and B. Not. So this become the proof for this problem. Thank you.

In this problem, I'm writing the Got it reaction. So just look at it carefully. The correct reactions are he had assad CO three solid plus K to Seattle flowers plus a C. Oh, it will react to form no PPT. So this is a corrective statement as well as Bs here, too. Plus a C. O reg plus get to see God or forward will react to form yellow PPT. So option A and D. R. Correct here.

Question is which The products opened via Oxy Mercury Ation of Built one. I'll be So build one is not this product, and when it is react with oxygen circulation circulation. Then, with the help of Marcon Kickoff Edition, which will add on the the stable cargo goddamn carbon without rearrangement. That's why. Which will lead on this carbon? So CS three CH 2 c. Well, that's a double bonus yesterday, But this is unacceptable because of it. Can open your eyes and give your debts. He has. He has to CST. Thank you. So, here's the very problem.

Hi everyone. So in discussion they asked the product acting higher. Obscene regulation Jessica plus, additional support of beauty and one will give a B is A is CS three CH two C o C. S, three beads, CH three ch, two ch, two ch oh then seeds, CH three ch two ch chocolates that Cholo and the CS three CH two CH plus and sewage. So in this case option is correct. Option E. It's correct current. Yeah. Your time Ladies CS three CH 2 C2 Taliban. See edge built one in on reaction with Ngos corporations and so forth & c. s. L. four. It should be a self old. Yeah, gives Yes CH three CH two C double bond. Oh ch three. Okay.


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