4

1 atm. 2> 30.0 IW cyelopropane in 3: and 31) What is the pressure; Ji 2 the Wj total pressure 1 a volume of 3000 mL? in mmHg 6 1 330 1 1 Page 6 of 7 5 3 1 mmHg a...

Question

1 atm. 2> 30.0 IW cyelopropane in 3: and 31) What is the pressure; Ji 2 the Wj total pressure 1 a volume of 3000 mL? in mmHg 6 1 330 1 1 Page 6 of 7 5 3 1 mmHg and thc partial aneslletic g sample of 02 g1s. which ` mol 01 pressuTe oi (he Oryeen Ifthe partial pressure of Spring L 2017

1 atm. 2> 30.0 IW cyelopropane in 3: and 31) What is the pressure; Ji 2 the Wj total pressure 1 a volume of 3000 mL? in mmHg 6 1 330 1 1 Page 6 of 7 5 3 1 mmHg and thc partial aneslletic g sample of 02 g1s. which ` mol 01 pressuTe oi (he Oryeen Ifthe partial pressure of Spring L 2017



Answers

A 20.0 L flask contains 0.776 g of He and 3.61 g of $\mathrm{CO}_{2}$ at 300 $\mathrm{K} .$
(a) What is the partial pressure of He in mm Hg?
(b) What is the partial pressure of $\mathrm{CO}_{2}$ in $\mathrm{mm} \mathrm{Hg}$ ?

Yeah. Okay. So this actual question actually is related about the gas. So the first question is how many milligrams of the ironing with satellite into evacuate seven 115 L flask. So first I want to do is PV use ideal gas law PV equals NRT. So in this case we are assuming that it's in the vapor pressure saturated. So actually the P. R. Dean equals to the vapor pressure and they is a flask. So now we can use that to calculate the more. So the other thing we need Just equals two p. I. Holding the pressure or times V over R. T. So here the P. Value the pressure is vapor pressure .466 Times 133. Then times the value Is equals to 750. Yeah, Times 10-6. Because you have to use the units military street miners at Power Street and our 8.314 & T. is 30° C six around 303.15. Now we can do the calculations here And actually equals two around .386 46 moore's of the irony. So now we know in order to feel this. Okay, so I think I did wrong calculation then just do that again. Point oh no point 466 times 133 Times 7 50/1 10,000 over one million. Right? So I want And over 8.314 times, you know, also over 303.15. and actually equals two around 1. 4, four times 10 to -5 more. So, the Iraqi and the mass or simple equals to the more mass times the moors. So the more massive iron is 200 54. And times this number, The more severe organ. And this actually equals two around 4.68 Times 10: -3 g. And this is answer. So the question be is if three uh milligrams everything I used what would be the final pressure in the flask? So then in this case the B we first need to calculate the morse of the Ireland in which equal to the mass over the more mass. So it's three times 10 to minus three g Over 254. And this equals two around 1.18 times tender minus phi moore's. And same here we use P. V. Equals through NRT. In this case we want to calculate the p. It was two N. R. P over V. Which is 1.18 times 10 to -5 Times 8.314 times The T. He here is 303.145 over the volume 750 times 10: -6. And saying we use a calculator to the calculations. So this is actually around. Yeah, searching 9.69 Pasqua Which is equals two around 0.3 a millimeter mercury And see if 7.85 mg argument used or will be the final pressure. So at most we know they can only reach its vapor pressure, right? It will be saturated. So as saturated case only About uh five mg of the album will be used. But in this case you have a 7.85, which means Here the 7.85 mg sardine is far more enough. So it will actually reach the precious state which the equivalent state, which means the pressure, which is simply Visa vapour pressure 0.466 milli meter mature E. And this is answer.

Defending a position off. So they imagine carbonate. I assume we have one more off sodium hatching company and also sodium carbonate being placed in the vessel. Ah, we have 2.10 a t m l cum dollar side. And also we have, uh, seven after team men Meter Mercury Off Warner. And when this vessel brained scream port Teoh 12 degrees Celsius, what would be the change in the parcel? Pressure off coming down side and also water when the whole system artifical livio. Okay, so from here we have ah, the impersonal reaction to generate gas from solid. And we already also given KP. Okay, so for KP off. Let's look, first of all, let's look at that. You could even expression off his reaction so the K B should be equals to the pressure pressure also to you. Times of harsher pressure of water and does not depends on the concentration off the salt. It's because the constant registration of solid is constant. So it makes no fat on the over your delirium. Okay, so therefore, um, you want to know how were the partial fracture off? Come down side water change. We just lets you find out in the initial condition. This is at equilibrium. But we've. And because Libya, if you're away from equilibrium, how would the system change? It is with you respond to extend Bish a new equilibrium. Okay, so we're going to fine. No, que que Will be the reaction. Croshere. So we're going to take the pressure pressure off. HTM. Sorry to a personal pressure off Seo two unit tm multiply the partial pressure water. Ah, in a t. M s. Well, so we have to deal conversion. So we just into device 7 15 by 7 60 and that we can follow their a t. M. The conversion factor between MSK You are being a better America. Reacher. 18 minutes. That's when a team comes to 7 60 million mercury. Okay, so from here, we should be able to off to find desolate. 211 times. Sanford into ourselves. 63rd Russian crushing que your roughly over 1.98 ihsaa one for night. Okay, so we go back to go get our KP So KPC 1.3. So from here we can see that cures speaker thing our decode Libyan constant So Ah, when this system with acute bigger than equilibrium constant Dan, the whole ah system or the reaction we prefer to shift to left. Okay, so we go back to our chemical reaction over here. Ships there were laughs. I mean, we have more reported being to be really shoulder to form our reactant. You know, where we have sodium carbonate, we every of covering dioxide with water to phone sodium hydrogen carbonate. So, in other words, when they you could even extend dish. So at equilibrium, toe pressure pressure off C C. Which you and the pressure pesh pressure off a stool. Well, d quiz when compare to the initial concentration.

So in this problem, we've been asked to find P gas in atmospheres. We're using an open ended man, OMETER, which is pictured here, and we're given that atmospheric pressure is equal to 738.5 tour. We are also given the change in height of the mercury is 2.35 centimeters. So if we view the diagram, we can tell that the gas pressure is less than atmospheric pressure. And we can tell this because of the liquid mercury, we can see that the liquid mercury is lower on the side of the atmospheric pressure than it is on the side of the gas pressure. So the gas pressure is less than exerting less force onto the mercury than the atmospheric pressure is. So this tells us that in order to find our guest pressure, all we need to dio is take the atmospheric pressure which was given to us and subtract the change in height. If this had been the other way around, where the gas was greater than the atmospheric pressure, we would simply be adding the change in height instead. Now our atmospheric pressure has been given to us as 7 38.5 tour, but we are working here in millimeters of mercury. So you may recall that one tour is equal 21 millimeter off mercury. So it's a simple one. Toe one conversion, 738.5. Tour is also 738 0.5 millimeters of mercury, and our change in height that we need to plug into our formula was given to us in centimeters. Again, we want millimeters. Um, there are 10 millimeters in a centimeter, so we're simply multiplying by 10. And that gives us 23 0.5 millimeters. So if we plug these numbers into our equation, we have that peak ass equals seven 38.5 millimeters of mercury minus 23.5 and then just doing our subtraction, we come up with seven 115 millimeters of mercury as our gas pressure. No, we do have one more step because the problem specifically asked for the gas pressure in atmospheres. So the conversion for this is one atmosphere is equal to 700 60 millimeters of mercury. So the equation to solve this our gas pressure in Excuse me there gas pressure in atmospheres is equal. 27 15 millimeters of mercury times one atmosphere over 760 millimeters of mercury. Our units cancel out, leaving us with atmospheres. So we know we've set up our equation the correct way in. Once we do the math, we get an answer of gas pressure in atmospheres equal to zero point nine four atmospheres on. There you have it.


Similar Solved Questions

5 answers
1 11M16833002888R 88 LMacBook Pro1
1 1 1 M 1 68 3 3 002 888 R 88 L MacBook Pro 1...
5 answers
In what orbital do the lone pair of electrons on the indicated N atom reside in the following?Which of the following is most basic?NHzCHGNHzWhich of the labeled atom is most basic In the follcwing molecule?
In what orbital do the lone pair of electrons on the indicated N atom reside in the following? Which of the following is most basic? NHz CHGNHz Which of the labeled atom is most basic In the follcwing molecule?...
2 answers
(&t K be d no Jet . behne map o XxX by dlxiy)- {1 7 4 Jhathat 1 0 metic (m X (et r70 and vey hnd W %en bal BCxir)
(&t K be d no Jet . behne map o XxX by dlxiy)- {1 7 4 Jhathat 1 0 metic (m X (et r70 and vey hnd W %en bal BCxir)...
3 answers
Theorem 5.25: Let F be a function defined neighborhood of the point aud such that lit F(=) = F(L):lim f(r) =lthtnlitn F(fe)er liwu f (r)F(L):
Theorem 5.25: Let F be a function defined neighborhood of the point aud such that lit F(=) = F(L): lim f(r) =l thtn litn F(fe)er liwu f (r) F(L):...
5 answers
What is the maximum efficiency that heat engine could have when operating between the normal boiling and freezing temperatures of water?
What is the maximum efficiency that heat engine could have when operating between the normal boiling and freezing temperatures of water?...
5 answers
HIW #41) There are three spheres hanging from cotton threads. Spheres and _ 2 are observed t0 repel each other; and spheres and 3 are observed t0 attract each other.Which sphere(s) might be positively charged? Explain why:(6) Which sphere(s) might be negatively charged? Explain why.(c) Which sphere(s) might be electrically neutral? Explain why.
HIW #4 1) There are three spheres hanging from cotton threads. Spheres and _ 2 are observed t0 repel each other; and spheres and 3 are observed t0 attract each other. Which sphere(s) might be positively charged? Explain why: (6) Which sphere(s) might be negatively charged? Explain why. (c) Which sph...
5 answers
Ka (+5) Lee (-7) %laI7*-` 9*+ SolveComplete the following tableEdeinucultabLSFind exact sine, cosine,and tangent values for each angle 1358 4] rads
ka (+5) Lee (-7) %la I7*-` 9*+ Solve Complete the following table Ed einu cul tab LS Find exact sine, cosine,and tangent values for each angle 1358 4] rads...
5 answers
Probleu Wli Use Simulink to plot the solution of the following equations for 0 <t<2: 641 + 41220poiutsL511 7x2 + f(t)where f() = 3t. [Hint; For representing the function f() . use the Ramp block in the Sources library]: Show the plots of solutions xI() and .2() separately (NOT in the same graph).
Probleu Wli Use Simulink to plot the solution of the following equations for 0 <t<2: 641 + 412 20poiutsL 511 7x2 + f(t) where f() = 3t. [Hint; For representing the function f() . use the Ramp block in the Sources library]: Show the plots of solutions xI() and .2() separately (NOT in the same g...
5 answers
BiuretHO CHz HC-ChzReagentA tetrapeptide Pro-Ala-Leu-TrpBiuretReagentNinhydrinEgg albuminReagent heatHOCHzXanthoproteic TestOHDenaturationMilk proteinsby HCI
Biuret HO CHz HC-Chz Reagent A tetrapeptide Pro-Ala-Leu-Trp Biuret Reagent Ninhydrin Egg albumin Reagent heat HO CHz Xanthoproteic Test OH Denaturation Milk proteins by HCI...
5 answers
3 XUO}423J Find V Find 4
3 XUO} 423J Find V Find 4...
5 answers
A projectile is fired with a velocity of 40 m / s and an elevation angle of 37 How high is the object at time t = 2 s. (g = 10 m /s^2)
A projectile is fired with a velocity of 40 m / s and an elevation angle of 37 How high is the object at time t = 2 s. (g = 10 m /s^2)...
5 answers
Consider the dissolution of CaCl₂: CaCl₂(s) → Ca²⁺(aq) +2Cl⁻(aq) ∆H = -81.5 kJ/mol A 15.0-g sample of CaCl₂ is dissolved in245 g water with both substances at 25.0°C. Calculate the finaltemperature of the solution assuming no heat loss to thesurroundings and assuming the solution has a specific heat capacityof 4.18 J/°C・g.
Consider the dissolution of CaCl₂: CaCl₂(s) → Ca²⁺(aq) + 2Cl⁻(aq) ∆H = -81.5 kJ/mol A 15.0-g sample of CaCl₂ is dissolved in 245 g water with both substances at 25.0°C. Calculate the final temperature of the solution assuming no heat loss to the surr...
5 answers
Is 1 = {1}?
Is 1 = {1}?...
5 answers
An observer notices an airplane flying directly overhead. Twominutes later the airplane is at an angle of elevation of 27.Assuming the airplane is travelling with constant speed andaltitude, what will be it's angle of elevation after another twominutes?
An observer notices an airplane flying directly overhead. Two minutes later the airplane is at an angle of elevation of 27. Assuming the airplane is travelling with constant speed and altitude, what will be it's angle of elevation after another two minutes?...
5 answers
Asie4 0anJL0auo paiasd Jo [e1quo [email protected] Ul @z WJa} e 3APY 01 aqissod 1! SI 8
asie4 0 anJL0 auo paias d Jo [e1quo [email protected] Ul @z WJa} e 3APY 01 aqissod 1! SI 8...
5 answers
DETAILSMY NOTESFlnd the number units that produces the minimum average cost per unit C in the given equation 0.OO1x] 686unlts
DETAILS MY NOTES Flnd the number units that produces the minimum average cost per unit C in the given equation 0.OO1x] 686 unlts...
5 answers
Are these vectors dependent Or independent? Justify Your answer; Hint: You May want t0 Use the following representation; [J 7, [4J (6 marks)
Are these vectors dependent Or independent? Justify Your answer; Hint: You May want t0 Use the following representation; [J 7, [4J (6 marks)...
4 answers
Use tnis illustration :0 show how PAD forms (Scroll Up {0 see enlargement)Use thi; illustration t0 show- now varicone vein; form (Scrollupto =ee #niargeten?Sendme copy Of my fesponsesc?subinit
Use tnis illustration :0 show how PAD forms (Scroll Up {0 see enlargement) Use thi; illustration t0 show- now varicone vein; form (Scrollupto =ee #niargeten? Sendme copy Of my fesponses c? subinit...

-- 0.020354--