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Rnar 1 (Rouna 1 Hl deamal places ) 1 aleasttnrel W apinox chledcn nat te prodomidi muounut bvy 'PinExpl antton8 D-0 00 8 8 Dp 8 8 lo...

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Rnar 1 (Rouna 1 Hl deamal places ) 1 aleasttnrel W apinox chledcn nat te prodomidi muounut bvy 'PinExpl antton8 D-0 00 8 8 Dp 8 8 lo

rnar 1 (Rouna 1 Hl deamal places ) 1 aleasttnrel W apinox chledcn nat te prodomidi muounut bvy 'Pin Expl antton 8 D-0 00 8 8 Dp 8 8 lo



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$\mathrm{K}_{2} \mathrm{CrO}_{1}$ givcs a ycllow precipitare on rcaction with: (a) $C_{4}^{2}$ (b) $\mathrm{Fe}^{3}$ (c) $\mathrm{Ba}^{2}$ (d) $\mathrm{Pb}^{2}$

The problem we're told the matrix A. Is equal The 3 -22 zero on negative four. And negative three to negative form. And the Matrix B is a matrix 40 two negative one negative 13 Now first we want to find A plus B. Now in order to add two matrices they must have the exact same dimensions. Well a is a three x 3 makers But B is a three x 2. And so that means that this is not possible because they don't have the same dimensions. Yeah. We also want to find A minus B. Yeah this is something else that we can't do because these don't have the same dimensions. And so this is still not possible. Yeah. Now we can find to A to A. Just means take everything in A. And multiply it by two. So that top probably six. And then get a 44 Than 0 to -8. The -6 4 -2. Yeah. And then lastly we want negative three B. And so it just means to take everything and be And multiply it by -3. That's 1912 0. Then you have 63 3 -9. So that's our matrix -3 B.

I only have a matrix A. As the Matrix 0 -27 five four, negative three. And be the matrons 840 zero 14 Now first thing we want to find here is a plus B. Finding a Polsby just means add the parts that go together. So I had the top left with the top left, the middle with the middle, the top right with the top right. And then so on zero plus eight gives us eight. They have two was forced to 707 On the bottom 505 four Plus 1 is five. Three plus four is one. So that's our major. It's A plus B. No a minus B is very similar. So if we subtract instead So in the top left, zero mindset is -8. They have to -4 is negative soups 7 -07. On the bottom 5 0 is five. 4 -1 is three. And I give 3 -4. There's negative stuff not for the matrix to A. That just means take every component in a multiplied by two. Mhm. And so this becomes zero. Now you're four 14 10, eight -6. That's our matrix to a. We have three. B is very similar to just take everything and be multiply it by -3. So it's 1924. May have 12 zero zero nee of three. No, you have 12.

We're going to find the component forms um going from .12.2. So each time we'll be taking our second point and subtracting the corresponding component from the first. So for our first factor we would consider that we do negative four minus negative six and a negative one minus negative. To notice those minus negatives end up being adding. So we get 2 to 1. So it can either be written with the brackets or we can write it in R I. J form which would be to I plus one J. And I don't have to write the one. If you just see the J. You know that there's a one there Kate. Now our next vector notice every single time we're going to be doing negative 1 0. Well this is already in kind of its component form because its origination is at zero. So we can really write our vector as just the negative 161 And if we write an I. J and k notation we could have a negative I plus six, J plus K. Now our third we'll have to a nine minus four A one minus one and a negative three minus negative three. So in the end I have no J and K. So in the notation that I've already written with brackets you would actually place in a zero where there are, you know, um no components of that form. But when you go to write it in I. J and K, you just write that as five A. If you don't write the J and K component, then it's known that those are zero.

And this problem we are given that Matrix A. is the three x 2. Matrix six I get 1- zero. Now you have 34. Mhm. And Matrix B is the Matrix Uh huh. 31 And yet 1560. And we want to find first A plus B. Now to add to major cities, you just add the corresponding components together. So top left close, Top left Is what goes on. The top left search plus three is 9. Top ride was top ride, It was in the top right now give one postponement 0. And then we proceed in this matter. Two plus negative one is one, zero Plus 5 is five. They have three plus six is three Than 4.0. As for And so that is our Matrix A plus B. Now for the Matrix A minus B. Take our correspondent components again and subtract the light terms 6 -3 is three -1 -1 is -2. Two minus negative one is three, 0 -5 is -5. Then you have 3 -6 is -9. 4 0 is four. Now for two a. We take everything and a and multiply it by two. six times 2 is 12 in one times two is that you have to We have 40 -6 and eight. And then lastly we want the matrix negative three C. I'm sorry, 93 B. Three B. That means take everything and be and multiply it by negative three 789 Now you have three. Three may have 15 negative 18 zero.


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