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Two point charges of 7.52x 10 Care situated in a Cartesian coordinate system: One charge is at the origin while the other isat (0.81,0) m. What is the magnitude of ...

Question

Two point charges of 7.52x 10 Care situated in a Cartesian coordinate system: One charge is at the origin while the other isat (0.81,0) m. What is the magnitude of the net electric field at the location (0,0.71) m?

Two point charges of 7.52x 10 Care situated in a Cartesian coordinate system: One charge is at the origin while the other isat (0.81,0) m. What is the magnitude of the net electric field at the location (0,0.71) m?



Answers

Two electric charges, $q_{1}=+20.0 \mathrm{nC}$ and $q_{2}=+10.0 \mathrm{nC}$ are located on the $x$ -axis at $x=0 \mathrm{m}$ and $x=1.00 \mathrm{m}$ respectively. What is the magnitude of the electric field at the point $x=0.50 \mathrm{m}, y=0.50 \mathrm{m} ?$

Question 75 states that a point You're at the origin of the coordinate system produces the electric field 56,000 Newtons per Coolum in the X direction on the X axis at the location of X equals negative 0.65 meters. Determine the sign and magnitude of the charge. This is scenario we have here. If this is our exit system, this is X and this is why the state that we have a point charge at the origin that produces an electric field at X equals. I need a 0.65 meters from the origin in the X directions. Maybe I should put this is a vector and this is a vector direction. This is our e at this point. So based on this information, we want to find the magnitude and sign of our point charge. Cuba will say so. We know that the electric field for a point charge is given as K times Q over distance squared. Here is a very relaxed arms going to X as my distance indicator because we know it's solely in the X direction, so it's fairly straightforward. Some just look for the magnitude here so the magnitude electric field and then based on the direction of the electric field will determine the sign. So we'll do that after. But we know this equation. We don't even know X the distance away Speaking this rearrange this equation saw for the magnitude of the charge to be the magnitude of the electric field times X squared did by the bike A And so, um, all these terms again aren't given to us. We have 56,000 Newton per cool times the distance created again the direction the distances matter just the absolute value of the distance. 0.65 meters. This whole term is squared, divided by R constant K Coolum constant you know, 8.99 times in the nine. And so by doing this we find that the magnitude of the charge it's 2.6. Thanks for to sing your silly for that 2.6 micro cools so we know the magnitude. So did the church is 2.6 micro Coombs and now the sign we see that we know the point chart is at the center and the electric field is pointing towards the centre or the ordinations a pointed towards the origin. So that's new. We think of it. Electric negative electric charges have electric field lines that point towards the center of the point charge. And so since this electric field at a distance to the left of the origin is pointing towards the origin, that must mean that are charge is negative. So we can say that our final answer is that their charges. Native 2.6 micro cools.

Hi, everyone. Here it is. Given a creepy at the point is 36,000 neutral particle, um, and only accepts is and distance of appointees by less 0.75 m. We have to find that cube. So a great field having the magnitude get your way hardest script? Or did you buy X square so you can be electric feet 36,000 17 plate upon nine into 10 to the bubble. Nine. So to build a B 2.25 and to the power monastic school, Um, and it is negative charge because electric field lines are towards the charge that sometime

How long were given? Two point charges lie on the X axis. This is X axis and this is why accessible. So first charges at access equal to 0.25 m. And another charge is at distance 0.75 m here. This is charged Cuban and this is charged cute. Right? So mhm. Mhm. We have to find the point where electric field is zero. So we know that electric field will be zero at between these two charges somewhere as opposed here. And this distances of those acts the electric field due to charge Cuban will be this direction and due to charge Q two in this direction you do. So we can write even will be equal to que que and Y axis square and it will be equal to okay cue to buy this distance. This distance is zero. The Distance between Cuban and Q two is a call to D which is a call to 0.75 -0.25. Which is a call to 0.50. So this is a call to Tito will be called to the stands between these two pointers minus X. That means d minus X squared. So when these two magnitudes are equal, we can say that net magnetic magnet I've so in that electric field will be zero at this point. So Okay into Cuban by Access Square. Should we call the KQ two by the minus X squared? So cable cancel each other? No Cuban is a cold 0.25 Micro column. That's the square into it is zero 1 6 Micro Cooler. They were d minus set. That means 0.50 minus X squared. So we can ride it is 0.50 -1 Squared. 16 way 25 images, four by five mm. So we can write 0.50 -7 YX is equal to four by five. So what is it called off? Zero point 5, 0 into 5 -5 x is equal to four x. So X will be equal to 0.50 into five by nine. So this location actually we call to right zero point X will be equal to zero 278 m now from the X axis. Yes, this location, location of this point from origin will be called to This distance, which is 0.25. Let's X. So This is 0.25 plus 0.27 eight. It is around 0.278. So The location of this point where electric field is zero is equal to zero 5- eight m. This is the answer. Thank you.

The problem we have given two point charges lie on the X axis support. This is y axis and here this is X axis. So point judge Which is 1.6 micro column at X is equal to one m. Yes of course This Cuban is a called a 1.65 micro column and another charge Which is that 2.50 m. And ah This charges according to -2.30 micro gula. So We have to find the place where the electric field is zero. So if we see this is negative charge and the magnitude of this charge is greater and this is positive charge and magnitude of this positive charges less than compared to this cute to charge. So I suppose this is the point at this point Where electric field is zero supposed this distance is X. now the distance between these Cuban and Q two is given to us which is equal to 2.50 -1 does. It stands as a quarter 1.50. Now at this point electric field you to charge Cuban will be in this direction. An electric field due to charge to two will be in this direction. So we will right. The magnitude of even is a call to K Cuban by X square. Where is the magnitude of it? Will be equal to K Q two by this distance. Deep list X square. So we equal this world so that the net electric field on this point will be equal to zero. So this is K model of Cuban by X square. Okay. Most of you do Deep Bliss X square. So this will be called to D plus X by X. Esquire. Is it called Kyoto Like you And now you two is 2.30 And this is 1.65. Okay. Mhm. So we can right here, B is equal to 1.50 plus X. Y. X. is equal to and the road 2.30 divided by 1.65. It is equal to one 1806. So from here we can find the distance X. So this is a little 0.1806 X is equal to 1.50 X is equal to 1.50, divided by 0.1806, Which is equal to 8.305. This is the stands X. And we right the distance X from this point. So this X is equal to 8.305. So now we can find this location on the X. Axis because we know that at this point this is charged Cuban. And this point is from explain these X. X. Is is The location of Cuban charges given to us, which is one m. This is when we did so. From here, X is given to us Which is 8.305. So the location of this point on X axis will be equal to 8.30 five minus one On the negative x axis. So this will be called to -7.30 five m. This is the right answer. Thank you.


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