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If 6.10 9 of propane Is allowed to completely combust; calculate the mass of carbon dioxlde formed at the end: Remember the units [Hint: write does the chemical equ...

Question

If 6.10 9 of propane Is allowed to completely combust; calculate the mass of carbon dioxlde formed at the end: Remember the units [Hint: write does the chemical equation and then balance it]Anbwog:

If 6.10 9 of propane Is allowed to completely combust; calculate the mass of carbon dioxlde formed at the end: Remember the units [Hint: write does the chemical equation and then balance it] Anbwog:



Answers

Many home barbeques are fueled with propane gas $\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)$ What mass of carbon dioxide (in kg) is produced upon the complete combustion of 18.9 L of propane (approximate contents of one 5 -gallon tank)? Assume that the density of the liquid propane in the tank is 0.621 $\mathrm{g} / \mathrm{mL}$ . (Hint: Begin by writing a balanced equation for the combustion reaction.)

So in this question, given that propane gas is used as it will be. As for barbecues. Now he's asked that what massive Clarinex reforms on complete combustion of 18.9 L of movement with density Given this European 6-1 gram for No first, we'll find myself 18.9 to support. And that is, we can find out by multiplying the volume introducing that is 18.9 Leaders in two, now will change the world of uh, Latest to multiple back in two or 3. So 18.9 to 23 miles into european 61 grandpa mm element, cancel our and will remain with uh, 7 11,036 70.9 g or 11.73 16 cages. Uh, I just look at the combustion reaction to prevent that is preventing us in a properly excess oxygen gives Uh, three moles of carbon dioxide plus four moles of water. Now we have to concentrate on the balls of carbon dioxide. So it is, we can see that from one mole of combustion of propane, we get three moles of carbon tax. Hence from uh, we have to find her debt from this much amount of propane, how much most or how much mass of theo to it will be produced. So, uh, national finals the most appropriate by dividing the molar mass of propane. So when you divide the molar mass of proving that is 44.1, we get, we get the morals of propane. Now from one model propane, we can get three months of carbon taxes. So we multiply three moles of carbon dioxide from one mole of propane. Then we multiply 44.3g as uh, model massive uh, three days, 44 points for each model. Many multiplayer. All these uh, grams of protein grams of protein will cancel it. Most of them also cancel out most of commendation, most common types of cancer and will remember grams of suit. And so if we went over all this will get 25,219 0.676 g of zero. Or we can roughly ascended to 35.22 kg of zero. And you can say that 25, Kg of steel to Well, we'll be formed on complete combustion of 18.18.9 L of propane. Yeah.

Let's calculate the mass of carbon outside in kilograms. Um, that will react with 18. Leaders of propane will first start with a balance equation are balanced equation. Here is C three H eight plus five oxygen gas, which will produce three sealed to gas and for each to old gas. We're starting with 18.9 leaders c three h eight over two mill leaders apply the density grams c three h eight per mil Leader C three h eight uh, Moeller Math 44.9 grounds in one more on strike geometry. One more c three h 8 to 3 moles of seal, too. We'll continue down here. One more. Sio two has a molar mass of 44 0.1 grams and convert two kilograms 1000 grams in one kilogram, and we will solve here to find that this is equal to 35 point one kilograms of CO. Two that would be produced

Okay, Question 84. We have to find the amount of carbon the outset produced, then 18.9 liters. All my opinion C three h h is burned in Austrian. The witness do you take. That's why I go do given Tracy or two. Bless Paul H. Two, now 18.9 liters has a density off 0.6 to 1. So the masses multiplied. Based little 16 to 1 unions. The more amounts off Japanese 44 on that of Carbonell cities. Also 44. So one beautiful grants of propane with that rate they into 44 g off common. Guilty united you so 44 g preparing hundreds, three into 40 Program carbon. So 1 g program in rates three in the body board apart. What people That is 3 g off. Probably so. 1 18.9 in two boys, 6 to 1, 6 to 1. You know, Graham off propane billion rate pinto. Three into 44.44. That is equal to three. Yeah, I don't want to be 35 point 21 reason


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