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QuesilonGiven a trigonometric equation y = ~2 cos(4x-T)Determine amplitude , period and phase shift_b) Forming a table for sketching the graph for cycle beginning...

Question

QuesilonGiven a trigonometric equation y = ~2 cos(4x-T)Determine amplitude , period and phase shift_b) Forming a table for sketching the graph for cycle beginning *=0_

Quesilon Given a trigonometric equation y = ~2 cos(4x-T) Determine amplitude , period and phase shift_ b) Forming a table for sketching the graph for cycle beginning *=0_



Answers

Find the amplitude, the period, and the phase shift and sketch the graph of the equation. $$y=\sin (2 x-\pi)+1$$

We are going to do problem number five in this question, what we're going to do, they just draw the graph of Just read the graph. Have to decide the question that is y equals two sign. Ex menaced by by two X. Minutes by But we have a photograph of this and they provide amplitude period and face except in this case. Okay so if you see amplitude here is one and nothing is multiplied to sign function And period is to buy as nothing is multiplied 2X. But her face, it will be there phase cept That is by by by two by way too and it will be towards right, okay so let me just draw the graph here. So as the british to buy so we are going to mark like successors to buy. Okay suppose it to this will be managed to buy half of managed to buy his madness by this is bye the amplitude is one. So this is one of the side. It is management now normal in normal certain case what happens? We just draw it like this. Okay, withdraw a normal case, withdraw shine function like this on liberty. There is a first set of five by two so we are going to accept it by 52 Okay so this part will be starting from here. Okay, so red party swing this graph. So this is how our graph it looks like. Okay, let me just uh make it a little bit of accuracy. Yeah, this is how our graph it looked like it will just keep on going like this. Similarly this will happen to the site also, so it will be going like this and more than like this only. Okay so here this red line is our deal graph of this problem. Okay, so I'm just putting a tarmac and this green line saws that how face it took place here. Okay, so this is the answer in this case. That's all. Thank you.

We have why equals to sign off X minus by vacuum. The standard form is why equals two. He signed off B X plus E. When y equals to smb explicit. You know, amplitude is equal to more of a thing. Is in this case is one next let's find the period. We know period is given by two Pi divided by Model B. This is to buy divided by one which is to buy next. We have to find the phase shift. Phase shift is given us minus C over B. This is minus. Seeing these cases minus five by two, Divided by B is one. So this comes us by over two. So we have the amplitude of the period under fisher. Now we will first find the interval that contains exactly one cycle for the sign. That can be found where zero be explicit Lies between 0-2 pi. We will solve this inequality in this case it's zero. He says x minus 52 tupac. This becomes by by two X two pi plus by by two ways 5512. So we have the region of X that contains exactly one sign reef. Now the amplitude is one, so let's plot the ground. This is five by two. He says bye three power by two 25 And this is five violent. We both like this. This is the way for one period. I'm glad you're here is one Here, it's -1 and it keeps them. That's all. This is how the Rockefeller zero. This is -5. Right? Why? And X.

Mhm. For this equation equals -2 vehicles to pie can see calls pie, hence the amplitude is the service value of a meticulous, too. The period is two pi over the absolute value of B. Very two girls, one and the first shift echoes minor C, or B, which because miners a half.

Mhm. For this equation equals -2 vehicles to pie can see calls pie, hence the amplitude is the service value of a meticulous, too. The period is two pi over the absolute value of B. Very two girls, one and the first shift echoes minor C, or B, which because miners a half.


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