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B) Calculate f te-stdt.CO C) Calculate J6 t2e-st dt.D) Calculate f6 t3e-stdt....

Question

B) Calculate f te-stdt.CO C) Calculate J6 t2e-st dt.D) Calculate f6 t3e-stdt.

B) Calculate f te-stdt. CO C) Calculate J6 t2e-st dt. D) Calculate f6 t3e-stdt.



Answers

Calculate (a) $f(0),$ (b) $f(1),(c) f(-2),(d) f(3 / 2)$. $$f(x)=1-\frac{1}{(x+1)^{2}}$$

Hello. So here we have the function F. Of X is equal to two, X squared minus three X plus two. So the part A we want to find F of zero. So f zero is going to be equal to just two times zero squared minus three times zero plus two. So the first two terms go to zero ff zero is going to be equal to to um And then for part B we're gonna find F. Of one. So f of one is equal to this two times one square which is two times one minus three times one plus two. Which is going to be equal to one. And then for part C that we want to do um F of negative two. So F of negative two is going to be equal to a two times negative two squared. That's gonna be two times four and then plus negative three times negative two, that's gonna become a uh minus three times negative two becomes a minus uh minus six plus six. And then we have a plus two, so that's going to be equal to 16. And then we have uh f of three halves, so f of three halves is going to be equal to while two times three halves squared, that's two times nine force and then minus three times three halves. That's minus a nine halves. And then plus two, Which is going to evaluate the two. Take care.

Hello. So here we have F of X. Is equal to the absolute value of X plus three and then minus five X. So part A. We are evaluating F. Of zero so we just plug in zero. Here is we have the absolute value of zero plus three minus five times zero. That's just equal to the absolute value of three minus zero. Which is the absolute value of three. Which is going to be equal to three. So we have for part A the F of zero is going to be equal to three. Then the card be we are evaluating F of one. So F of one is into the absolute value of one plus three minus five times one. That's going to be equal to just um four minus five which is going to be negative one. So F of one here is equal to negative one. And then for part C you're evaluating F of negative two. So F of negative two is going to be equal to the absolute value of negative two plus three minus five times negative two. That's going to be equal to just one plus 10 which is going to be equal to 11. And then to part D. We are then evaluating F of three halves. So of three have gonna be equal to the absolute value of three halves plus three minus five times three halves substituting and three have now in for X. So therefore this is going to be equal to the absolute value of Um 9/2 -15/2. So that's just nine halves minus 15 halves which is equal to negative six halves. Therefore it's gonna be equal to negative six halves negative six have just negative six divided by three which is equal to negative three. Therefore f of three halves is going to be equal to negative three. Take care

Hello. So here are given F of X is equal to X squared minus two X. So for part A we have F of negative X. So F of negative X. We just go ahead and plug in negative X for X. That's going to be equal to a negative X squared minus two times negative X. Which is going to be equal to a well negative X squared plus X squared. It's gonna be equal to a X squared plus two X. So f of negative X is gonna equal to X squared plus two X. And then for part beef we have F of one over X. So f of one over X is going to be equal to well one over X squared minus two times one over X. Which is a one over X squared minus two over X. Which is going to be equal to a one minus two X. All divided by X squared. So there we have um F of one over X. And then for part C we are evaluating F of A plus B. So F of A plus B. Let's go ahead and plug in A plus B now for X. So this is going to be equal to a plus B quantity squared minus two times A plus B. So therefore that's going to be equal to a squared plus B squared plus two A B. There's a plus B squared and then minus the minus two distributes here minus two A minus. To be just combined, which we can factor this little bit. This is going to be equal to a A squared plus B squared plus two times the quantity A B minus a minus B. And there we hey have it. All right, So there is um F of A plus B. All right. Take care.

Hello. So here we have active X is equal to two X divided by the absolute value of X plus two plus X squared. So part A. We are evaluating F zero plug in zero here. So F zero is going to be equal to two times zero over. The absolute value of zero plus two plus zero squared. That's just equal to two times zero is zero over. Um The absolute value of two which is two plus zero. So this is a zero over to what's going to be equal to zero so therefore F zero is going to be equal to zero. And then for part B we are evaluating F of one so F of one is equal to two times one of the absolute value of one plus two plus one squared. That is equal to 2/4 which is going to be equal to one half, so of one is equal to one half. And then for part C we have f of negative 22 F of negative two is going to be two times negative two which is a negative four divided by the absolute value of negative two plus two. That's zero plus negative two squared. That's just zero plus four which is negative 4/4 which is equal to negative one. So therefore F of negative two is going to be equal to negative one. And then for party we have f of three halves. So F of three halves is equal to about two times three halves, divided by the absolute value of three halves plus two plus a three have squared which is going to be equal to the numerator is just three divided by a seven halves plus nine four plus +94 Which is going to be equal to 12/23. So therefore F of three halves is equal to 1223. All right. Take care.


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