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In outer space rock with mass and velocity <3300, 2800 _ 2000> m/s_ struck rock with mass 15 kg and velocity <210, -270, 300> m/s_ After the collision t...

Question

In outer space rock with mass and velocity <3300, 2800 _ 2000> m/s_ struck rock with mass 15 kg and velocity <210, -270, 300> m/s_ After the collision the 9 kg rock' s velocity is <2900, -2100, 2300> m/s. What is the fina velocity of the 15 kg rock?vf450420120msWhat is the change in the internal energy of the rocks?AEinternalWhich of the following statements about Q (transfer of energy into the system because of a temperature difference between system and surroundings) are

In outer space rock with mass and velocity <3300, 2800 _ 2000> m/s_ struck rock with mass 15 kg and velocity <210, -270, 300> m/s_ After the collision the 9 kg rock' s velocity is <2900, -2100, 2300> m/s. What is the fina velocity of the 15 kg rock? vf 450 420 120 ms What is the change in the internal energy of the rocks? AEinternal Which of the following statements about Q (transfer of energy into the system because of a temperature difference between system and surroundings) are correct? (Ignore heat transfer by radiation:) Check all that apply: Q ~ 0 because there are no significant objects in the surroundings Q ~ 0 because the duration of the collision was very short. Q = AEinternal of the rocks_ Q = AK of the rocks_



Answers

(III) A $975-\mathrm{kg}$ two-stage rocket is traveling at a speed of $5.80 \times 10^{3} \mathrm{m} / \mathrm{s}$ with respect to Earth when a pre-designed explosion separates the rocket into two sections of equal mass that then move at a speed of $2.20 \times 10^{3} \mathrm{m} / \mathrm{s}$ relative to each other along the original line of motion. (a) What are the speed and direction of each section (relative to Earth) after the explosion? (b) How much energy was supplied by the explosion? [Hint: What is the change in KE as a result of the explosion? ]

Good day. The topic is about heat. We note that when a substance loses or gains heat, its temperature may change. The heat that is associated with temperature change of the substance is solved as Q equals M. C. Delta T. Where Q. Is the heat M. Is the mass C. Is the specific heat which value depends on the type of substance and DELTA T. Is the change in temperature. Which can be solved as the difference between the final temperature T. F. And the initial temperature. The A Let us consider a bullet which mass is three g and moves at the speed of 1 80 m per second. The specific it of the bullet is given to be 1 28 joe's program for a kilogram degree sell shoes. We assume that all of the kinetic energy of the bullet as it moves is transferred to itself in the form of heat. So in this case we wish to find the change in the temperature or by how much the bullet holes temperature will change. So that this first note that since we're using the mass in terms of kilograms to suffer the kinetic energy. So we need to convert 3g into kilograms. And that's done by dividing this by 1000. Since we know that one kg is 1000 g. And that gives us 10000.3 kilogram. So we start by solving for the kinetic energy which is equal to K E kinetic energy one half times mass times the square of the speed. And this gives us 1/2 times the mess .003 times the speed, which is 180 squared. And then Katie will be equal to 48.6. This kinetic energy of Katie will be converted into heat and that it will be observed by the bullet so that the temperature of the bullet will change according to the given equation. So your cue is 48.6. The mass is 0.003. And that specific it is given to be 128, solving for identity gives us 48.6 Over 0.003 times 1 28. And that is equal to yeah, 120 7°C. It follows that the temperature of the bullet will rise up by 127°C. So I hope that helps. Yeah.

This question is about a collision of two spheres. He still one s and 10.5 kg And the initial velocity, It's event to be to I minus gj last k. You just put second and this against your ass mess 1 25 kg. Their initial velocity is given to be minus. I class to Jane minus cheeky you just for a second. Okay, then. That's a, um even that The final velocity off and one yes, minus I class she chain minus its k. He wants to find me to f. Okay, so to do this will be using conservation of momentum. So we get this and one b one I us em to me too. I it goes to and one you want f pass and to be two f So putting in the numbers, I'm going to use the column. Former practice tu minus tree one. This is for everyone and for him to be, too. I This is what we have. And then and one B one f plus 1.5. Me too. Okay, so, uh, rearrange. So you generate the right hand side of the left hand side. Done bringing in uh, um, turns from there. Right hand site. You can see that this throughout the course of zero, which means that you two f yes. Zero. Yeah. And then, um, you look at, um, compare kinetic energy. So Okay, candy energies before and after collision. Okay, So can the energy before is ah, half everyone and one we want I square plus have them to me to I square everything, putting in the numbers I am. One is your five and completing everyone I square will be something that squares off the components. Yes, if you repeat a step for, uh and to And then you calculate this any shaking adding energy to be 14 juice and then the final looking at the energy. Uh, it's just a and one B one f skway happened when we went ex quay. So Okay, so this is 18.5 shoes. So we have k I, uh, less than chaos. So which means that a collision in this case with me, uh, elastic. Yeah, it's not completely. It's not perfectly any lasting, but it's just last. Okay, so this is, uh, the answer for a Yeah, that's right. Stiff then for parts B. So you assume that, uh, final velocity off and one is given to be, uh, my name is your 0.25 I class to your point. Third time J minus two. Okay, he does put second. Then we wants to find me to wrap a gain. So, uh, we just we just repeat from this equation. So this is the part that needs to be changed. So we have 1.5 me to f is equal to my name is 0.5 1.5, minus hole, minus five. This is anyone and everyone else is even in such. Okay, this is found to be is your 0.375 1.1 to 5 my ministry. And then after the writing, 1.5 both sides, he gets me to have to be. Ah, what is your 0.25 I see Appointed by J and minus two. Okay. And if this one Yeah. So, uh, the collision is affect me in lasting. Okay? Because the both spheres have the same velocity final velocity after the collision. Okay, so the answer for that's B. All right, so we move on to proxy. Okay? Now, um, given that b you want f is minus. I plus d j has a k you just for a second. Uh, you want to find me to African? Okay. So to do this on the conservation of momentum. Okay, so we have, um, 1.5 me to f eyes equal to minus 51.5 or my ass for I guess, your 0.5. When it's one tree A, it is equal to 00 Uh, minus school. My name? 0.5 a, um, back there. Okay. So, me too. F you think we're too 1/1 45 minus four, plus your 40.5 e. Okay, you don't split second. Okay? Okay. Then you need another equation because the collision is, uh, you lasting. So the we have conservation off connecting energy. Okay, so that means, um huh. And one, we want every square that's half them to you to ask. Where is a photo? 14 Jews. It is the number that we are thing completed. Impress me. So putting in the numbers or, uh, finally getting energies. So So this is the final kinetic energy for M one. And then for him to Okay, So this is the equation for the conservation of kinetic energy. Ke So, uh, so continue to do the math. Um okay, so continue. Yeah. So when I do this, I'm not declining three throughout the whole equation. So this is the question I get and then simplify. You get this quite reading Christian to a squared. Plus, it's a minus. 37 goes to zero. So here you used the quadratic formula English to, uh, minus eight. Last minus, uh, be square rightness. Who I a see? Square it and then divide by four. So from here, get a go, Sue 2.74 oh, minus 6.74 Able, our values are possible. So we can completely finally velocity fall m two for each case for any goes to 2.74 you have me to have to be Ah, minus 3.58 Okay, you just go second. And then for a he goes to minus 6.7 full. You have you to half to be minus your point for one night. Okay? You just put thinking okay, So that two answers for this question. So this is one of the 1st 1 of the possible answer. The second possible answer is given Estes. So that's all for this question.

Kimpler singing the study is that any other velocity is given by Delta Air. What does that teach was as over? Um, now angular Momentum is constant Over here, we have got end equals and the be for the apple pilyeon. And there's just put the aperribay suffixes in there. So we have the annular moment of this constant. So that's always em. El it was. This equals. I am on C at his Ian times and we zap Ilyin. So from here we can find that V A A over, um equals V B be over to Aaron. So we find that with gossipy at the AP, idiot equals velocity to be be over A. It was 55 times 10 to the three time 17 point 8/0 point 586 It was 1 16 point 706 Damn stand to the five. Made up for a second

Okay, so here, initially bullet off mass M with speed V is colliding with em. So we have initial momentum. M v. It was final moment. Um yeah, v finals. So we find this is the initial theory initially equals m plus m over m can three final now it will go in this projectile motion. This ranges D on this height is age. So we have got h equals half G t square Because the initial rise on the spirit zero so t equals swelled off to age over G. So range de comes out to be the final times t equals. Okay, Sophie, final equals Do you have a t So we have the initial equals m plus m over em. That's the final. Which is D over tea. Yeah, Our thesis is Empress em over em. Times Square, load off. G B squared over to age.


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