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. $1+1 \neq 2 .$ Consider the following argument. In subtilisin, mutation of Ser 221 to Ala results in a $10^{6}$ -fold decrease in activity. Mutation of His 64 to Ala results in a similar $10^{6}$ -fold decrease. Therefore, simultaneous mutation of Ser 221 to Ala and His 64 to Ala should result in a $10^{6} \times 10^{6}=10^{12}$ -fold reduction in activity. Is this reduction correct? Why or why not?

So in the enzyme mutation at serene 2 to 1, this results in a 10 to the sixth fold decrease in activity. So another individual mutation of history in 64 also results in a decrease in 10 to the sixfold in activity. So when both of these mutations are present in the same enzyme, then we have a 10 to 12 fold reduction in activity. But this is not the case. This is because once the catalytic activity is reduced to almost zero by the mutation off the required residue, the introduction off the other residue cannot further reduce the activity. Yeah.

So here are going to be calculating Mill Aridjis Um, given the mill Aren t and K a of other solutions. So for a V of age Cirio plus there's a strong acid. So it's 30 physical stage five, which is a equal to 0.0 nine to allergy. Um, we have the reaction. We have H C three h 502 plus h +20 those two c three h 50 to minus plus h Theo Plus. So this is your ex and we know this is your 0.892 plus X and this is your a 0.275 minus maximise like so, the K A here is equal to X time zero boy zero a nine to trust specs divided by 0.275 mining specs, which is equal to about 0.92 x. Is there a point your 892 by by 0.275 which means that X is equal to four times 10 to the negative fit polarity, Um, and the hilarity of aged 30 plus Z equals 0.892 So now we can use this and calculated for the rest of them. So be so h minus, which is equal. Okay, w over where did that, which is equal to 10 to the negative 14 over. Was there a 0.892 which is equal to 1.1 times tender than I get 13 polarity. Never see that we know is equal to X, which is equal to you four times tended and I get 1/5 polarity. And lastly for D you have I minus is evil too. H i, which is equal to zero quay 0892 polarity.

This question says are the following instructions for diluting a 10 Mueller solution to a one Mueller solution. Correct? The instructions are take 100 milliliters of the 10 Mueller solution and add 900 bill leaders of water. Is this correct and explain? So it's close. Technically, that will get you the right answer. But that is not how you should make these types of solutions. So let's think about this. We have a 10 Mueller solution and we go one to go to a one molar solution. So this is a 1/10 delusion, and we know from the equation, see, one V one equals C two B two or M one V one equals and to be to the concentration or the polarity. Since these air indirectly related, if one goes up, the other has to go down. If we're taking 1/10 of the concentration, we have to increase the volume by 10. So if we're gonna take 100 mill leaders of the 10 Miller solution, the final has to be one leader or 10 times 100 milliliters. So the way you do this is you don't simply take your original solution and add a set amount of water to it. You take your starting solution and you add water until you reach a point. So the way you might write this is you take the 100 milliliters of the 10 Miller solution and with stirring. So you want this to be mixing the whole time. Add water until the total volume is 1000 milliliters were one leader.

Then then yeah. Then answer food solution each boiled with an with an and h c 03 solution. It will produce integrated, produce, Yeah. Then ceo three as the final product. Therefore, according to the option option C age, correct and said obstinacy is correct. Answer for this problem.