5

Consider the following data for iodine:atomic mass126.90 molelectronegativity2.66kJ 295.2 molelectron affinitykJ ionization energy 1008.4 molkJ 7.76 molheat of fusi...

Question

Consider the following data for iodine:atomic mass126.90 molelectronegativity2.66kJ 295.2 molelectron affinitykJ ionization energy 1008.4 molkJ 7.76 molheat of fusionYou may find additional useful data in the ALEKS Data tab_Does the following reaction absorb or release energy?releaseabsorb(1) I (g)I(g) +Can't be decided with the data given_Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above?yesnoIf you answered yes to the previous

Consider the following data for iodine: atomic mass 126.90 mol electronegativity 2.66 kJ 295.2 mol electron affinity kJ ionization energy 1008.4 mol kJ 7.76 mol heat of fusion You may find additional useful data in the ALEKS Data tab_ Does the following reaction absorb or release energy? release absorb (1) I (g) I(g) + Can't be decided with the data given_ Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? yes no If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): kJlmol Does the following reaction absorb or release energy? release absorb (2) I' (g) + e Itg) Can't be decided with the data given Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? yes no If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): kJl mol 2



Answers

Use the following information to answer questions 1-5. $\begin{array}{ll}{\text { Reaction } 1 : \mathrm{N}_{2} \mathrm{H}_{4}(l)+\mathrm{H}_{2}(g) \rightarrow 2 \mathrm{NH}_{3}(g)} & {\Delta H=?} \\ {\text { Reaction } 2 : \mathrm{N}_{2} \mathrm{H}_{4}(l)+\mathrm{CH}_{4} \mathrm{O}(l) \rightarrow \mathrm{CH}_{2} \mathrm{O}(g)+\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g)} & {\Delta H=-37 \mathrm{kJ} / \mathrm{mol}_{\mathrm{rxn}}} \\ {\text { Reaction } 3 : \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightarrow 2 \mathrm{NH}_{3}(g)} & {\Delta H=-46 \mathrm{kJ} / \mathrm{mol}_{\mathrm{rxn}}} \\ {\text { Reaction } 4 : \mathrm{CH}_{4} \mathrm{O}(l) \rightarrow \mathrm{CH}_{2} \mathrm{O}(g)+\mathrm{H}_{2}(g)} & {\Delta H=-65 \mathrm{kJ} / \mathrm{mol}_{\mathrm{rxn}}}\end{array}$ What is the enthalpy change for reaction 1$?$ (A) $-148 \mathrm{kJ} / \mathrm{mol}_{\mathrm{rxn}}$ (B) $-56 \mathrm{kJ} / \mathrm{mol}_{\mathrm{rxn}}$ (C) $-18 \mathrm{kJ} / \mathrm{mol}_{\mathrm{rxn}}$ (D) $+148 \mathrm{kJ} / \mathrm{mol}_{\mathrm{rxn}}$

Of elements within the same group is observed to increase from top to bottom of the periodic table. A student is at the bottom of group seven and so, based on its position in the periodic table of elements that can exist as a mon atomic metal rather than a die atomic molecule. So the energy required to remove an electron is 9.317 electron volts. That is what our units are here. Electron volts. We convert this to Jules, which is 1.5 times 10 to the minus 18 jewels. We then convert this tequila jewels Permal, which is 903 kg joules. Permal. So the ionization energies that we have been supplied with do not support the first part of this podcast on Now. This is because the ionization energies off these elements increase from left to right across the periodic table. This means that the metallic nature should decrease from left to right across the periodic table of elements.

Hello. So today we're going to be talking about this compound right here, and we're going to be it talking about how originally it was believed that this compound was Ionic. So it was predicted that this that that this supposedly ionic compounds a lot of synergy You would have been 360 killer jewels. Permal. So let's talk about whether this is consistent with what else we know. Well, think about it this way. So Zine on is a fairly large molecule, and this an eye on is also quite large. If we draw it's separate ions. So well, we know is that both the cat on and and I on have a plus one and the negative one charge, and they are fairly large. Well, let's take a look at potassium iodide. Potassium iodide is composed of potassium cat ion and I had died and I on and the Gladys Energy is 432 Kalid Jewel's per mole. So the zine on Cat ion in the end, I on they're both larger than potassium, and I don they have the same magnitude of charge, but their larger so it would be expected that they're lattice energy will be lower then the then the lattice energy for potassium iodide. And as we can see, that is what is going on. So that means that this is consistent with what we know. Now let's calculate the energy for basically the formation of this. So if we have Zien on gas and this gas, and then we make this I on a compound while will did the energy the ability change be. So let's calculate this. So first thing that's gonna happen is een on gas is going to lose an electron to form on Cat Ion. This is the ionization energy, and in this case, it's 1170 Kalid Jewel's Permal. Now let's take a look at the second step. So after we magazine on a cat eye on, we need to make Dan I on. So we're adding an electron and until be changed for this for the step of the reaction would be the electron affinity and the Elect and the MLB change will be negative because energy is being released when an electron is added to and an eye on so it will. So then they'll be. Change will be negative. 770 killer jewels. Permal. Now, let's so look at the very last step. So once we have the C nine cat eye on and the and I on, they will come together to form on Ionic solid. And if he noticed, this is the negative of the lattice energy which, as we mentioned before, was 460 collegiality a mole. So if we look throughout, this will notice this will Hansel it This the electrons will cancel so we have what's on the top. And so then it will be changed for the overall reaction would be the addition of all of the end of the changes of the steps. So 1170 minus 700 sandy minus 460. And we should notice that overall that until P change should be negative 60 Kalid Jewell's Permal so tangibly change is negative. So that means that this is an excellent thermic process. So that means that this compound will form However, if we compare it to say another until pia formation safer lithium fluoride. The until p change was negative. 594 0.1 killer jewels promote, so this ionic solid will form. It's probably not as a stable of lithium fluoride, because it's not as a claw, thermic, but it will form, so it is stable, and there we have.

Number eighty eight of chemistry to Central Science. Chapter five. So considered reaction. It's two gas plus I, too. Salad yield to h I. So we're going to bond and compete in Table five point forth. That's made out of a tree reaction, ignoring the fact that I don't in the solid state. So here's our bond and puppies. It's ever going to do this two times. Two ninety nine I don't forget. We're using Has his law. Don't think reaction is. You called out there. Eight approx myself that h of reacting. So now we subtract. Fact one fifty five plus four. Thirty six. Sick. So we're gonna put this in our calculators two times tonight. Nine last one fifty one plus four, thirty six six. So that is going to equal eleven. Killer Jules eleven killer deals promoting. So if I had to guess whether or not now for Part B, they want us to guess whether the estimate we make in party for our that is more or less negative than the true reaction entropy. And I'm going to say it's a problem. It's probably going to be more negative than the reaction will be. And Toby because when we're looking into reaction, we're looking and I too, in Excellency. However, if we look at the when the reaction occurs, I too in its solid state is going to be converted to a two as I threw gas. Yes, and the conversion from solid gashes face that's going to be. And in endo thermic process posit that process is missing in our estimation. So the actual anto Pete e for this reaction, who is going to be more more positive than our estimate we have here? Yeah. Now there, gazing at the information from the true reaction to be So we have our doubts. The h i I I doubt that the ageing permission for a job right here, twenty four point nine killers prole Now remember if a Delta formation for and mulch for an element in Sanders State is always zero. So we have a issue that now man Stan state. So it's Delta zero and we have eye through solid, which is elements here in state. So it's always Europe. So the death age of reaction for this process for this reaction is going to B the equal to the H information of H I and so we can see that they don't age for you. Concede that healthy for a patient that they are of a guy is in fact act more and more positive and rs made out eight and bean, as we said before, that's due to the fact that we're not taking into account out the conversion of I do. So I threw gas which is going to end the current process, and that contributes to the positive number that we see here.

Here we are continuing to look at bonding. And so we're looking at a reaction that forms a single bond between two eggs atoms, energy is released. So this reaction is eggs a thermic. And so the bond entropy is the energy that is required to break a bond. And so during the breaking of a bond we have energy consumed in part B. This means we have an endo ceramic process. So the bond entropy of X two is a positive quantity. And so in part C We would estimate the bond entropy of X two. So that is delta H. Is roughly about minus 500 kill jules promote into the bond entropy Will be approximately 500 kilo joules per mole, wow. And so continuing on. We need to calculate delta rates for the reaction in part the which is found to be 500 kg joules per mole at 750 kg joules per mole. Subtract To lots of 1500 kg joules per mole We left with 1750 killer jewels, Permal and Sudan. In party, we're looking to calculate the formation of A. X. By calculating delta H. And the using the born harbor cycle. So Delta H. comes out to be 25 kg jewels. So in a reaction a compound is formed if the reaction is eggs a thermic. So for the reaction where we have the value of delta H. This needs to be negative. So because the value of delta H. For this reaction is positive. This is an endo ceramic reaction. And so finally in part F if in the reaction of compound is formed, the reaction is eggs. A thermic. Delta H. Is negative. So therefore the formation of A X. In the above reaction, the minimum required amount of lattice energy of A.X. 100 Kilo jewels. At 25 kg jewels. This gives us 1 to 5 kg jewels. Yeah.


Similar Solved Questions

5 answers
Change the Cartesian integraldx dy into an equivalent polar integral. Then evaluate the polar integral.Choose the correct equivalent polar integral below: sin 0 [ r2 cos 0 dr d0 sin 0 cos 0 dr cOsin 0 1/ 2cos 0 dr d0 341/2 (2/ sin & cos 0 dr d0The value of the double integral is (Type simplified fraction )
Change the Cartesian integral dx dy into an equivalent polar integral. Then evaluate the polar integral. Choose the correct equivalent polar integral below: sin 0 [ r2 cos 0 dr d0 sin 0 cos 0 dr cO sin 0 1/ 2 cos 0 dr d0 34 1/2 (2/ sin & cos 0 dr d0 The value of the double integral is (Type simp...
5 answers
Whal Uk hybridization on €, theg,c,c angle and type o (bondson G70, [EspechaN}Select Ore sp, CCC} argle = 109 50 20 bonds _ 6 $ CiCC, angle 10359, Cie bonds Csp , Cic Cyngle 1202 _ Cr= bords 0 -# d sp , CCC;angl 120" _ Cr-0 bonds = Za 0; sp" C,6C; argle 90" Cjeze bonds
whal Uk hybridization on €, theg,c,c angle and type o (bondson G70, [EspechaN} Select Ore sp, CCC} argle = 109 50 20 bonds _ 6 $ CiCC, angle 10359, Cie bonds Csp , Cic Cyngle 1202 _ Cr= bords 0 -# d sp , CCC;angl 120" _ Cr-0 bonds = Za 0; sp" C,6C; argle 90" Cjeze bonds...
5 answers
PROJECT ONE PROJECT PER GROUP Ahmed RashedLaling Cllcrnt Narnttyplec Funcllen (OJd ur Eum|Fr Rchmarolnr cunrtinn aannuiEnd IehuJvlor otthe Function (Rehl EadiSumeer nERr_ZrtuiLol Ral Eroi4inimumSumtzr ul Turinaal Tumine FuntAHu374
PROJECT ONE PROJECT PER GROUP Ahmed Rashed Laling Cllcrnt Narntty plec Funcllen (OJd ur Eum| Fr Rchmarolnr cunrtinn aannui End IehuJvlor otthe Function (Rehl Eadi Sumeer nERr_Zrtui Lol Ral Eroi 4inimum Sumtzr ul Turina al Tumine Funt AHu 374...
5 answers
A wire of length $L$ and cross-sectional area $A$ is made of a material of Young's modulus $Y$, if the wire is stretched by an amount $x$, the work done is(a) $frac{Y A x^{2}}{2 L}$(b) $frac{Y A x}{2 L^{2}}$(c) $frac{Y A x}{2 L}$(d) $frac{Y A x^{2}}{L}$
A wire of length $L$ and cross-sectional area $A$ is made of a material of Young's modulus $Y$, if the wire is stretched by an amount $x$, the work done is (a) $frac{Y A x^{2}}{2 L}$ (b) $frac{Y A x}{2 L^{2}}$ (c) $frac{Y A x}{2 L}$ (d) $frac{Y A x^{2}}{L}$...
1 answers
Find all points of intersection of the two curves. $$ \left\{\begin{array}{l} x=t^{2}+3 \\ y=t^{3}+t \end{array}\right. \text { and }\left\{\begin{array}{l} x=2+s \\ y=1-s \end{array}\right. $$
Find all points of intersection of the two curves. $$ \left\{\begin{array}{l} x=t^{2}+3 \\ y=t^{3}+t \end{array}\right. \text { and }\left\{\begin{array}{l} x=2+s \\ y=1-s \end{array}\right. $$...
5 answers
Lssipnment Scorngbest submission for each question par used %or your score19_ (-/1 Points]DETAILSOSPRECALCI 8.5.367, 0/100 Submissions UsedRound Yout nuInerical a ueneutex hundrodth:Usi the rechanquiaipoalTeatultha graphlng calculatorpoltutnmdnnt Entor YourWhn lontVlew Previqu: Queon Quesilon 19 08 20 Viaw Next QueslionSralich
Lssipnment Scorng best submission for each question par used %or your score 19_ (-/1 Points] DETAILS OSPRECALCI 8.5.367, 0/100 Submissions Used Round Yout nuInerical a ue neutex hundrodth: Usi the rechanquiai poalTeatul tha graphlng calculator poltutn mdnnt Entor Your Whn lont Vlew Previqu: Queon Qu...
5 answers
Electrode Reduction Potentials: ActinidesAmo 4p0/ PLD/Uo * LtoJd-Npoz
Electrode Reduction Potentials: Actinides Amo 4p0/ PLD/ Uo * LtoJd- Npoz...
5 answers
Minimize C = 13x + 57ySubject to:6x + 10y > 1203x + 2y > 42x > 0y > 0Give the optimal value of the objective function.The optimal value is
Minimize C = 13x + 57y Subject to: 6x + 10y > 120 3x + 2y > 42 x > 0 y > 0 Give the optimal value of the objective function. The optimal value is...
5 answers
The starting salary of HR employees in the Niagara Region arenormally distibuted with an average salary of $52,950 with astandard deviation of $4,370. If you are hired in the NiagaraRegion, what is the proabibility that your starting salary will be:(diagrams must be provided) b) Between $55,000 and $57,500? (4marks)
The starting salary of HR employees in the Niagara Region are normally distibuted with an average salary of $52,950 with a standard deviation of $4,370. If you are hired in the Niagara Region, what is the proabibility that your starting salary will be: (diagrams must be provided) b) Between $55,000 ...
5 answers
Gaseous methane (CH,) will react with gaseous oxygen (0_) to produce gaseous carbon dioxide (CO_) and gaseous water (H,0): Suppose 9.5 g of methane is mixed with 24.9 g of oxygen_ Calculate the minimum mass of methane that could be left over by the chemical reaction, Round your answer to_ significant digits.
Gaseous methane (CH,) will react with gaseous oxygen (0_) to produce gaseous carbon dioxide (CO_) and gaseous water (H,0): Suppose 9.5 g of methane is mixed with 24.9 g of oxygen_ Calculate the minimum mass of methane that could be left over by the chemical reaction, Round your answer to_ significan...
5 answers
4ti7t 6" 7 2 S 0 7 1 { 1 JA % 4h {33325 4 GJc 6 ~ 1 417 1
4ti7t 6" 7 2 S 0 7 1 { 1 JA % 4h {33325 4 GJc 6 ~ 1 417 1...
5 answers
6) 9"+ 4y'+4y=0 .Y(-I)= 2, 4'4)=1
6) 9"+ 4y'+4y=0 . Y(-I)= 2, 4'4)=1...
5 answers
Given the symmetric equation of the line La; equation of the planes P and PzLine LiX-5 =y+7-32 Plane R 4r+y-3z = 24Plane P 8r +2y-62 =8Show that the line La is not parallel t0 the planeMarksZFind the point of intersection between the line Lu and the planeMarks)(iii)Sketch the plane P and hence, find the distance between the plane P and the plane Pz_ Marks)
Given the symmetric equation of the line La; equation of the planes P and Pz Line Li X-5 =y+7-32 Plane R 4r+y-3z = 24 Plane P 8r +2y-62 =8 Show that the line La is not parallel t0 the plane MarksZ Find the point of intersection between the line Lu and the plane Marks) (iii) Sketch the plane P and he...
5 answers
Find the limits:lim 9_2 a) X--3*+3x+x-6 b) lim YCI 2x? _ 816x-x3 c) lim X+3
Find the limits: lim 9_2 a) X--3*+3 x+x-6 b) lim YCI 2x? _ 8 16x-x3 c) lim X+3...
4 answers
View the Diagram, put the following Urine Flow "Structures in Order by Number starting with the collection area Ist:
View the Diagram, put the following Urine Flow "Structures in Order by Number starting with the collection area Ist:...

-- 0.019716--