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In the diagram, 91 = -6.39*104-9 C and q2 = +3.22*104-9 C. What is the electric potential at point P? Include a + or sign: 920.424m0.636 m(Remember; V adds as a sca...

Question

In the diagram, 91 = -6.39*104-9 C and q2 = +3.22*104-9 C. What is the electric potential at point P? Include a + or sign: 920.424m0.636 m(Remember; V adds as a scalar; NOT a vector (Unit V)

In the diagram, 91 = -6.39*104-9 C and q2 = +3.22*104-9 C. What is the electric potential at point P? Include a + or sign: 92 0.424m 0.636 m (Remember; V adds as a scalar; NOT a vector (Unit V)



Answers

Two points, $A$ and $B$, are separated by $0.016 \mathrm{~m}$. The potential at $A$ is $+95 \mathrm{~V}$, and that at $B$ is $+28 \mathrm{~V}$. Find the magnitude and direction of the constant electric field between the points.

Over here. We have even two different scenarios and we need to find the potential difference between them. Okay. So in the first part we have given our charges cube is placed over here. Okay. And plus to a distance of uh, data from me, this is G two from me be went and this is the one the one from a point of energies. Distance of the one. And what we have more information given his tax. Q has a magnitude. You had a magnitude of uh, one microphone. Okay, secure equals to one Micropal. Um, and what what more thing do you to equal to the two equal to one m? And they want equal to two m, right? The two equal to one m and they want to call it one m and the two equal to one. So did to equal to one m and they want equal to two m. Right? So first of all we need to find them potential difference. Car's potential difference across the miners baby. Right? So for the human activity we can find that P. M. S very bright. Okay, that was for the person or two upon our mistake and minus of KQ upon DB. Okay. Are they too? And the the one over here we have given the one is greater. That was the one is two. So you mean this care is nothing but nine out of nine you already know. Mhm. If you take common this game you is nothing but one macro key in the development of six one upon at once one by two minus one appointment it will be minus of one by two from whatever managed to my as well on my minutes of one by two. So it will be minus of 4.5 into 10 to the power of three three. Bold. Okay, so there will be a negative for insulin because B is at large contact and support that. And in the next 2 19 have you have given that charge uh at the same distance Centenary what the court said that? They say the one is over here one and this is the two point because again the distance we remember the same. So that Mr Delta B. That means the M. S. Maybe again BM minus baby. When you were saying they don't kick you upon one upon the one man is gonna want you to do this. We're going to see him because the RCMP others are saying with that reminds of 114.520 got off three Bold. Okay, thank you.

In the first part of this problem, we have to find the potential at X equal to 0.500 meter. So we need to find we. Let's slide the we vehicles to. Did you do to charge one, which is okay too minus to kill you wanted by X plus, don't you do to try to ok, do, uh, the charges five to you wanted by 1.0 is you don't meter minus X. Well, this convenient. Another week will stool Good. Do we have taken these two things as common? And then we can white uh, minus tool you wanted by X plus, here it is life divided by 1.0 meter minus x. Well, call it equating number one now inserting the weather's into disquieting weaken y it equals two we have developed for cares eight point my nine multiplied return this far night tennis ball Tonight you tell me to square by Colon square and then we have developed for you as a four point 11 multiplied by terrorists far minus nine Kula and uh then we can write for the times says minus two divided by the innovative for excess. As you know, point 500 meter. And that is plus I and five rewarded by 1.0 minus 0.500 meter. Well, that is well, you. So this would give the value for we as we equals two. 200 on duh 21 point six. Mine would. So this is the answer. The first part of this problem Knowing what to we have toe find the point. We have to find out point and be the potential is zero. So let the point is X since that potential is you know, so we can write zero equals two the potential due to Charlie. Want care into minus two. You wanted by X plus, don't you do to try to Is canto five cool You wanted? By what 0.0 mita minus six. Well, all this question can be rooting as a zero equals two to be wanted by minus two. Divided by thanks. Plus five divided by 1.0 meter. Minus six for this can be written as they do in tow. 1.0 meter minus six equals toe five picks. No, from here. If we sold disc waiting for X weaken. Right. X equals two 2.0 beater you wanted by. That is silly. What for? This will give us the wider for X equals two zero point to nine meters. So this is the answer. The second part of this problem. Thank you.

Okay, so we're in Chapter 23. Problem. 11 says a uniform electric field e of negative 4.2 Newtons for cool. The negative I direction points in the native ex direction is shown in this finger here the X and Y coordinates appoint a B C forgiven right here and there End meters. All this and beaters we want determine the potential difference between different points. So for a potential difference between parents, be in a so for all these, we can apply equation 23 4 b to solve what the potential differences are awesome. So note that the electric field always points from high potential potential. So now, going from B to A here, you see that you're not your only traveling exactly perpendicular to the electric field. So that means there's exactly gonna be zero potential difference. Let's move to part B. Okay, Part B use asking us to find the between C and D. Okay, so this is given as the potential difference at C minus the potential difference at B and we should see here that this becomes e times the distance between C B. And you should see that along the direction of E. There is a difference of seven meters, so this becomes negative for proof to this prick cooler part seven meters, and that comes out to being negative. 29.4 Bolts School Parsi This is asking the voltage between sea and a well. This is given by order of C minus 40 eh? But we can also write that as fortune of seeing minus me plus V and B minus fee. Hey, and that's given. That's the same thing as V C B minus V. B. But we already found these amino that V B A zero for part A. So this is just the CD four Negative, 29.4 balls cool.

So we're trying to find the potential difference across these two charges So we can say that Q AA cues of A is going to be equal to one point two micro columns or we can say one point two times ten to the native. Six cool arms we have charge of B is going to equal negative three point three micro columns or three negative three point three times ten to ninety six cool arms. And for these too charges they have a separation d of ten centimeters or weaken, say point one zero meters now velocity across a velocity. So baby would simply be the electric potential at a minus the electric potential that b this is going to equal que que es divided by d And then this will be plus cake use up to a better buy the radical, too, minus K cues up to over tea plus que tu other. We shouldn't say not to further, but B My apologies. So minus k Q. And then this will be divided by D and then plus que Q a divided by the radical, too. So we find that the baby is going to be equal two k Q sub a minus Que ce of B over D times one minus one over. Radical, too. Thanks. So at this point, we can solve and say the baby is going to be equal to a point nine nine times ten to the ninth. So that would be cool arms constant. And then here it's going to be, Ah, queues of a so one point two micro columns minus negative three point three micro columns, um, divided by point one zero. So the separation distance and then we'll be one minus radical, too. So this is going to equal one point approximately one point two times ten to the fifth bolts. Again, we have to round two to significant figures because that is ah, our least accurate measurement is Has two significant figures are charges on ly have two significant figures. So therefore, our final answer can only be accurate to two significant figures. So have surround Onda again. That final answer is one point two times ten to the fifth votes. That would be the electric, the difference in electric potential. And that is the end of the solution. Thank you for watching


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