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Draw the organic product that is expected to form when the following compound is treated with aqueous NaOH:dipropyl etherNaOHYou do not have t0 consider stereochemi...

Question

Draw the organic product that is expected to form when the following compound is treated with aqueous NaOH:dipropyl etherNaOHYou do not have t0 consider stereochemistry: Include counter-ions; &g. Na T,in your submission_ but draw them in their own separate sketcher Scparate multiple products using the sign from the drop-down menu_ If no reaction occurs, draw the organic starting material

Draw the organic product that is expected to form when the following compound is treated with aqueous NaOH: dipropyl ether NaOH You do not have t0 consider stereochemistry: Include counter-ions; &g. Na T,in your submission_ but draw them in their own separate sketcher Scparate multiple products using the sign from the drop-down menu_ If no reaction occurs, draw the organic starting material



Answers

Draw the structure and assign $Z$ or $E$ stereochemistry to the product you expect from E2 reaction of the following molecule with NaOH (green = Cl): (FIGURE CAN'T COPY)

This question is as the reaction off. Ah, one mess hopes cycle hex symbol with the striations. So within our eight in a h sodium hydride isa base. So it will be pro tem late. Ah, this Ah, I said it. Broughtem. And so the product of this will be sorry. Um, song What's sodium chloride? No reaction will happen Which ate beer The ah, the uh ah h plus we're problem, mate The age and then it will generate the Kabul can tie in Would just stay boy enough and then would be our minus It will farm one. Missed you Uh Psychlo Hexen one bro My eyes, the air war happen the same reaction with HBO from Kabul Katana will he give us and then subsequently will see a minus will generate the coordinated product sum for it, as it, on the other hand, react with it will also from ah generate the kabocha tie in. However, the next step will be s so far to minus attached. This and this one go back in here and so it will generate this often the most substituted all the fit is the most able proud of sodium hypochlorite. More reaction. Sorry. Sorry of hypochlorite sodium bicarbonate sodium hydride. Then see a story series to be Are so the first step, uh, we've seen in the previous page will farm the sodium salt and then we'll see is three cs to be our The old miners over here's gonna attack. This one is a living group, and the product will be a neither. So, last poc 03 First reaction with P o seal three will generate off course what the hell appeared in. Oh, yeah, that's right. And then see a minus attack here. Make this one become a good living group. She's a final brother.

All right. Reaction. Uh, this question has us or it's the product of reaction off one medal Sacra Jackson on with this creation over here. So the 1st 1 this one's really strong base sodium plus H minus eight minus will be pro tem It this one and you will have the product off Minus Enable us with this saw. HBR is to be out with us Broughtem night the ah ah ohh group which make it become a good living group and then generate a couple car tie in and b R minus will farm the pro might compound a CEO. It's ah same mechanism. And so the product will be see over here. So boric acid or act differently Supported gas. It will also farm first also farm Ah, broughtem late. The whole group generate the cable car tie in. But then the, uh s so far to minus gonna attack this hydrogen. And so it generated all off in over here, the most up student olive being is the strongest nuclear fire or sorry. I think I blew a sodium bromide and solve your problem. I will have no reaction. Ah, sodium bicarbonate potentially can't deport, mate No, it cannot. Sorry. Um no reaction. Sodium hydride will assist you see, in the previous space the first time with sodium hydride, we will generate the, uh, costs I first oh minus and a bus. And then with ch three c is to be our wonder go nuclear flick substitution over here. And the final product is an ether. Ah poc l three and Peter then poc 03 imputed In the first reaction out, Holbrook will react with p o c l three simple nuclear very substitution with the have a period in will generate this intermediate over here and then period in with the lamp here on the hydrogen. Sorry on the night vision will attack this product. This one now become a good living girl. And so you will end up with this kind of products to substituted all the fit

So first here you would create. So the ring opening occurs of the tertiary carbon to give a carbon cat on, like, civilly to the transition state. So here is that transition state, and this is going to come in right here. So then this would work. Um, so the brahmi and approaches 100 degrees from the c o h. Bond, as it would like in an SMT reaction. So then this would lead to you'd Havenaar and here you could have an s.

Okay. I want to get the formula for the following reactions in the first one we have. And and I'm ethel said Ahmad zero, I think with the sodium hydroxide and water. So this is under base conditions. And the first step is that the oxygen on sitting hydroxide is going to attack carbon carbon. We'll get your cock sit down as well as the addition of a rich. It's a study um just the spectator ion. It's not going to add to the structure. And um at this point the only difference is that the next one is in a deeper innate water because it's a stronger base, then the cox that I own. So if you look at the content asset of each of these, because you get acid of the Kochs hidden inside your oxide, which is a fairly strong base and therefore weak acid. Look at the county acid of Inamine. It's ammonia, which is a weak base and therefore um we can't get this is gonna be strong to the PKK. Abra of hydroxide is around take 15.7. But in general, the Peca of Inamine is around 35. So it's stronger beasts. And it's gonna department water oops. And as a result, will turn itself into a better leaving group because it'll be a weaker base. You got cox that I wanted to reform the gold bond and expel. Do you mean we're still, you know, a shirt. So yes, so we get acidic acid or ethanol, Kassid and dimethyl amine as well. As soon my truck's out back for the next one, we had the structure. So this is similar to a where the hydroxide ions going deeper in eight or it's gonna attack carbon carbon. We'll get the cox that I own and then the aim i it's going to be permanent water to open the ring. So I have this interview, it's gonna reform and open up soon. Carbon one of the key tune or a car box of acid and carbon fiber can be the men, the NH two group. And we also get sort of hydroxy back to, so we only get two products here, as opposed to three in the first one because it's really just kind of a ring opening reaction. We went from a my to an amine.


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