In this problem of motion along the state line, we have given a figure, I'm showing you first. So this is difficult and We have given that a pilot flies or urgently at 1300 km/h. So this is 1300 km/h or gently At height is equal to 35 m. So they said equals to 35 m above initial level ground. However, however, at time t is equal to zero, the pilot begins to fly over ground sloping at an angle, this is 4.3, so this is angle theta is equal to 4.3 degrees. This is a figure. If the pilot doesn't change the airplanes heading at, what time does the plane strikes the ground? So this would be continuing. Now we have to find the time at which this will be is striking the ground. So If the plane with the T. V is equal to 30,800 km/h, maintains its present course. And if the terran continues its upward slope, which is equal to 4.3 degrees, then the plane will strike the ground after traveling. So they said delta X and delta X equals two divided with 10 theta. We can take, this is at and this is 10 to to so here Putting all the values, so h equals to 35 m and 10 4.3°. So this age then 4.3°. After solving, we get the city equals two 465.5 m. Or this is approximately in km, we can say this is zero food 65km. Now this corresponds to a time of light, so we can say ved equal, so everyone citizens, it is constant, so T. Is equal to delta X divide with me. So we have to solve 40 Delta X. is equal to 0.465 km and will city in terms of kilometers power, so this is equal to 1300 km. But now when we solve it, message equals to 0.000 35 m 358 hours. So when we convert it into second, so the city equals to 1.3 seconds that went after. So we can say after 1.3 seconds. Or we can say 0.000358 hours. The plane strikes the ground. So we can say plane. It strikes the ground. So this is the answer.