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Menclature Hanna Patel: AttemptQuestion 12 (1 point)Name thc following compound:Hide hint for Question 12Ms| be numbered Apply the For this molecule one of the two ...

Question

Menclature Hanna Patel: AttemptQuestion 12 (1 point)Name thc following compound:Hide hint for Question 12Ms| be numbered Apply the For this molecule one of the two outer groups Broups break the tie; The center alphabetical priority rule on ethyl and methyl group will be on carbon #2.Page 3 olNorerazoFncyQ

menclature Hanna Patel: Attempt Question 12 (1 point) Name thc following compound: Hide hint for Question 12 Ms| be numbered Apply the For this molecule one of the two outer groups Broups break the tie; The center alphabetical priority rule on ethyl and methyl group will be on carbon #2. Page 3 ol Norerazo FncyQ



Answers

Give the structure corresponding to each name.
a. 2-methyl-3-phenylbutanal
b. dipropyl ketone
c. 3,3-dimethylcyclohexanecarbaldehyde
d. $\alpha$-methoxypropionaldehyde
e. 3-benzoylcyclopentanone
f. 2-formylcyclopentanone
g. ($3R$)-3-methyl-2-heptanone
h. $m$-acetylbenzaldehyde
i. 2-$sec$-butyl-3-cyclopentenone
j. 5,6-dimethyl-1-cyclohexenecarbaldehyde

The straw condensed structures reach of the fallen for it. A We have Bethel beauty mean, so this would be our structure for muffle beauty for be We have psycho vaccine. It should be 36 cycle vaccine. Double bond for C. We have to muffle three x Sign you four by six. So six carbon chain for hex at carbon three. We have a triple bond carbon to be of a methyl group in their carbons. And there would be to Bethel three. Heck, sign for D. We have two beautiful you teen four carbons Carbon to We haven't alcohol. And there would be the structure for two beautiful e we have fo I saw Pro Poor either fo group Thanks. Appropriate group. We teach three to H three in a three, so there would be helpful isopropyl ether. And for f, we have prop and Al So we haven't l defied double Bond. Oh, what the end three h two and h There would be propane out

So he was just drawing out some condensed structures. So fastly we have said 135 tribe Ramo to painting. So breaking this name down, How long is carbon chain is five carbons. We have a double bond on the second carbon. We have three Bruning atoms. Tribe Roma Onda. We have our Bruning atoms on the first, that on seventh carbon atoms on. We have a sad structure, meaning that we have assess confirmation. A second example. We have sad three missile to help Dean. So we have a seven carbon chain with a double bond on the second carbon on a missile substitute on the side carpet again, we have these that confirmation. Next. We're looking at a trance structure. So we have the e form here. Well, I want to die, bro. Most re I support pile to vaccine. So using the same rationale is above We have six carbon chain double bond on the second carbon I supported pile group on the sad carbon to brew mean atoms on the fussed on second carpet In that says confirmation on that trans confirmation. Sorry. Ah, seconds. The last example. Vinyl bromide. We have a ch two C H p r double bond attached to a halogen. That's quite a simple structure to be looking at. And now we have want to die. Missile cycle Pantene, where we have five carbons and not ring a double bond onto me, found groups on the fast on second Carbon. Why are double bonded also on the fast carbon? Lastly, we have die a lile a mean so Amy, meaning love that night steering group. It's a second ring nitrogen What we have hydrocarbon chains on We have SP two hybridized carbons are either end off those changed.

This is the answer to Chapter four. Problem number 41 fromthe Smith Organic chemistry textbook. I'm in this problem. We are given many I you packed names and asked to draw the molecule for each of these. Um and so just a heads up. This is gonna be, ah, a bit of a longer answer than usual on theirs. Quite a few names that were given, and so I am just gonna start drawing them out. I mean, so remember the way to approach this. The end of an AIPAC name tells us either the longest carbon chain or the biggest ring. If if there's a ring that's bigger than any of the carbon change president and so that's a good place to start. Start with that bass name again. That's the end of the name. Um, And then I used the rest of the name to fill in some information about substitutes. So, for a we have three ethel to metal. Heck, sane. Um, and so again, the end of the name tells us this is a hack seen derivative, so we can go ahead. Six. There's a hex ain on. Then again, it's three ethel to metal so want to three Ethel to metal. So there we go. There's three Ethel to metal hack sane for a time. And so that's Ah, that's the way that I'm going to solve these. I'm gonna look at the end of each AIPAC name. Used that to determine, um, the base chain or the base ring on and then use the rest of the name to fill in the substitue INTs. Um, okay, so that was a B. We have sec. Beautiful psycho plantain. So Psychlo plantain is the bass name here. So five members ring Psychlo pen tain, um, and then on any of these carbons, we can draw a sec. Beautiful group. So I don't like the way that looks. Um, So there we go. There's a better sex. Okay, um, and again, it could be any carbon because we're not given a number or anything. And really, there's no way to number it, because all the carbons air equivalent until we put a substitute on there. So that's Ah, sec. Beautiful Psychlo plantain. So then looking at sea, we have four isopropyl 245 Try metal. Hep teen. Okay, um and so again, obtain is the bass name here. So 1234567 Then let's see. Four isopropyl 245 Try metal he obtain. So, uh, I like to go left to right whenever possible. So this will be carbon to there's, um Ethel Carbon four. There's, um, Ethyl carbon five. There's a metal. Ah, and then four ice a pro bowl. So actually, let me back up a little bit. So there's one on carbon five. There's one on carbon four. Ah, and then here is our isopropyl group. Also on carbon for okay. And that's for isopropyl 245 Try metal hip teen s. So then d is gonna be Psychlo. Beautiful Psychlo. Hep teen. Okay, so this is a seven member ring with a four member to ring attached to it. Okay. Seven members rings, um, are are always a struggle to draw. Ah, I like to pretend that I'm drawing a six member dring. I'm And then instead of, um, bringing the last two sides together, as I would for a six member drink, I bring each of them down on Lee a little bit. Ah, and then put a connecting peace between them. So that's That's how I do it. Um, that's not great looking. There we go. It's a little better. So there's our Psychlo hep teen on then anywhere we can put a cycle of beauty. So there we go. There's day e is going to be three Ethel 11 dime Ethel Psychlo vaccine. So we need to draw a cyclo hexane to get started. So draw a hexagon, and then it's three Ethel 11 dime, Ethel. So we can pick any of these carbons to call one, so I'll start here. This is carbon one. Ah, that makes this carbon three. Um, you know, or you could have done the bottom carbon as well. If you name that carbon one. Ah, it doesn't really matter. Just as long as you know your numbering is consistent. Ah, and so there's e f is going to be four beautiful 11 die. It'll psychlo octane. Oh, boy. Psychlo octane. Okay, so this is gonna be an eight member ring. I'm so bear with me as I tried to draw this, so All right, let's see here. No, I know how to do this. Okay, so right. So this is just like drawing a seven member ring, but you do the same at the top and the bottom. So there we go. There's an eight member drink. Okay, Um and this is four beautiful 11 die, Ethel. So let's make, uh, this carbon number one. So one ethel group two other groups on and then four. Beautiful. So we'll go to three. Four, and again, you could go the other way. A CZ Long as you are consistent in your numbering. Ah, so beautiful one, too. 34 Alright, there we go. Um, there is Ah, four beautiful 11 die a full psych low octane. Okay, um and so I'm gonna move on to a next page here. G is asking us to draw six isopropyl to three. Dimethyl na name. Okay, So non ain is ah, the base of our name here. 123456789 There's non ain six isopropyl to three dime, Ethel. So again, I like the number left to right. There's nothing that says that you have to, but that's how I do it. There's 23 I would should make 456 ice a pro bowl. There we go. there's G, um, Kane's h h is gonna be 2 to 67 Penton. Ethel Octane. Um, so we start with octane. 12345678 2 to 667 So five methyl groups here. So 22 345667 Okay, um, so next eyes gonna be cysts. One ethel, three metal Psychlo painting. Okay, so, again, Psychlo plantain is our base name. We can start by drawing a five member ring cycle plantain. And then this is cysts one ethel three metal. So, um, we can draw them dashed or wedged as long as we draw them both the same since they're cysts. Um, and so arbitrarily make this carbon carbon number one. I'm so one asshole. Three meth. Eliza's gonna look like this. So there we go. Uh, one Ethel. Three metal psych, Lapentti. Okay. Um, so that's I on again for I, Like I said, we could have made them dashed, uh, or wedged as long as they were. Both are the same. Okay. And so, uh, it looks like J. Uh is is the last thing we're asked to draw here. Um, S O. J is Trans one tert Beautiful four Ethel Cyclo Taxi! So the first thing to do is to draw a cyclo taxi. So again, it's just gonna be a hexagon. There's our hexagon. And then let's see Trans one Turk beautiful for Ethel Cyclo taxi. So Ah, we can start with Ah, the one tert beautiful. So there is Ah t Beetle Group. Ah! And then we need to put on Ethel Group on four. And remember, we want that to be trans to the turbulent group. So since I made the Turk Beetle group wedged, I'm gonna make the Ethel Group dashed on. So there, that is. Um we could, of course, do the opposite. Where the Turk Bugle Group is dashed on, Ethel Group is wedged. It doesn't matter, so long as they're trans to one another. Um, and that's the answer to J. Um and that's the end of this problem. And to remember, the way to approach this is to look at the eye you pack name, um, and remember that the end of the AIPAC name tells you the base chain or the base ring. Um, start with that structure and then use the rest of the name to figure out what the substitutes are and what number carbons they're located on. Ah, and that's the answer to Chapter four. Problem number 41.

So for a the structure would look like this for be even have a structure that works like this for see, you have a structure that looks like this because you would have on the third and fourth carbon a oxide or D. It's a cycle pinto off. So so have a five ring and a six carbon ring with an oxygen connecting them. There's a six covering oxygen that I fired covering. And then, lastly, we have e. So you have four. A little too metal. Oxo Fit also started fiddling, and then after the second wave of that missile, axel with myself, fennel. So there's a wage coming off of it. Then on the 4th 1 is a little.


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