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2 Findthezed and equation containing for the the 1 'poinepdicukzo 3 to the line...

Question

2 Findthezed and equation containing for the the 1 'poinepdicukzo 3 to the line

2 Findthezed and equation containing for the the 1 'poinepdicukzo 3 to the line



Answers

Write an equation of the line that passes through the points. Then use the equation to sketch the line. $$ (3,-1),(-2,-1) $$

Were given a pair of lines and rest pair of points where has to find the equation of blind passing through these points and to sketch it so the points are too negative. One in one third negative one. Now to find the equation of the line, let's think of a reasonable way of writing the form of this line, so were given two points. It makes sense to use the two point formula for a line here. This tells us that why minus the y coordinate first point negative one over X minus the X coordinate. First point to is equal to by coordinate second point of negative one Linus White Coordinate first point of negative one over X coordinate 2nd 0.1 3rd, minus x coordinate. First point to simplifying the right hand side. We get zero over one third, minus 21 3rd minus two is equal to one third, minus six thirds or native five thirds. Of course, zero divided by anything is just zero. So now it's sold for why we get that. Why plus one is equal to. And then on the right hand side, we have zero times X minus two, which again is just zero and therefore we have in slope intercept form. Why equals negative one? So this is an equation for the line now or to plot the line. Let's plot the two points were given and draw a straight line between them. So we see the X coordinates range from one third to LME draw the X axis from 0 to 3 in the white coordinates range from negative one. Well, just a negative one. So I only draw the y axis from negative 3 to 0. So I'm really only drawing the fourth quadrant here. A point to negative one is located about here, and the point one third negative one is located. Let's see about a third and negative one. It's about here and drawing a straight line through these two points. We get the line for our graph, check our answer graph of our line to check our answer here. Well, noticed that we have the equation for the line and slope intercept form, so we see that the slope of the line should be zero. That means we would expect the line to be horizontal, which it is also the y intercept of the line should be negative one. So you would expect the line to intersect you. Why access at negative one, which certainly appears to do so. So our answer makes sense.

In this question. Where you calling about the question on the line? Why, including AM Express p going to aim Stand from the slump at negative two months. 11 over the next two minutes. Next one being here We stand from the Hawaii intercept now in discussion were given a two point and ah, one month to and we have the three months to notice that we can identify the X one way one x two y two and then you were blind. A formula for the slop. I am include you. Why do you manage when one So have the managed to manage Managed to x two months X 13 months one Then we're gonna go to zero with two If we 20 And when you get in a slum with zero, look into here. The weekend is really eager to There are times X plus B means that Why would you be Now look at here. We see that why I'm was equal to manage to therefore why must include you manage to And this will be the question with the confirm now she scanned the graph Here we have no y axis and X X is Yeah, We had a very equal to minus two. They found the light will be this one. Why you go to minus two.

So how our slope recalls to one certain and also you know, those one passing through the 10.33 So we're have the equation line minus three. Cultured, slow times X minus three. So how high my nose three you call to while works reacts. Right now it's one. So why Yukos? Who? Our three acts minor last two.

Okay, so give him a following. Two points to negative one and one third. Negative one. Okay, So first I want to find the slope of the line that goes through these pair of points. So I'm gonna let this first point the X one. Why one and I'm gonna let the second on the x two y two. Okay. So to find the slope em, I'm gonna take y tu minus y one over X two minus x one. So this is going to give me negative one minus negative one. So just become negative. One plus one, Then we have one third minus two. Okay, so this will actually give us zero over. So one third, minus two. That is negative. Five thirds. So this just simplifies to zero. Okay, so now, knowing that this line that goes through these two points as a slope of zero so I can now try to put this in slope intercept form. So So open intercept form is why equals m X plus B. So we have em as just being zero. So it would look like why equals zero ax so we could try to find our y intercept, be okay, so we could take any one of the points that we have above. So let's use to negative one. So we're gonna have negative one is equal to zero times, too. Must be so This will just give us that b is equal to negative one, since this drops to zero. So the equation for our line is gonna be Why equals negative one. So if we go ahead and we can plot two points, we can plot to negative one, and we can plot the y intercept zero negative one. So if we do that, we start with zero negative one to negative one. And we plot those two points and connect them with a line. And we have this line y is equal to negative one, which has a horizontal slope or a zero slope.


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