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Question

Nda 12-0 banen 6-v01 bettory re dobionad eleclrcal circuil ccnlalrrig Ihrcu rGalblors schumilic bold*5onaMps aro the sol67Ioboanno systsm colatonsUsing Kifchnoll & Iho Ihrua Ciryn s whora Rie R Arinuns1, m nnquredRili + Rzhz 40 Rih RslsCq [email protected] Lnu syatom 0" Egrators ectonnolrus krow d thero wll bo currenl {Iw ng through Andiei Manis Secins Anonte circun Gunenl Ilowina ihmugr ard detormine II Ihero

nda 12-0 banen 6-v01 bettory re dobionad eleclrcal circuil ccnlalrrig Ihrcu rGalblors schumilic bold* 5on aMps aro the sol67 Ioboanno systsm colatons Using Kifchnoll & Iho Ihrua Ciryn s whora Rie R Arinuns 1, m nnqured Rili + Rzhz 40 Rih Rsls Cq [email protected] Lnu syatom 0" Egrators ectonnolrus krow d thero wll bo currenl {Iw ng through Andiei Manis Secins Anonte circun Gunenl Ilowina ihmugr ard detormine II Ihero



Answers

Find the currents and voltages passing through the resistors using Kirchhoff's rules.

Social students in this question we are asked to write the mps are better law. So what is a modified form of mps circuit from a closed loop in integration? Look integration of Magnetic 3rd? The Communal Times. The Moon plans integration. Oh okay. Yes. Mhm. The no the duty. Yes. So so in this particular thing we will get like um you know I you know, I just do not in order and deep by by DT. Okay. Do you see the final answer? So at party given options, our options seats cramped. Okay. So you don't need to uh european how I eat this because uh immediately not in our service, we just need to remember that the final equation of closed loop and parts of twitter law. Right? This is a modified formally. So I hope you understand. Thank you.

In this problem, plucks of be certain arbitrary moment of time T is given by this is equal to be dot as which is equal to would be by a square by two because Omega T from Friday's law endured. The MF is given by EIN is equal to minor D five by DT, which is equal to minus D. We fight A square by two because omega T by D T, which on further simplification, I can like devalue edge B by a square omega by two Sine omega T. An induced current I in his equal to E in by our which is equal to be pie A squared by two are omega signed omega T. Now thermal power generated in the circuit at the moment is equal to T. Is given by P T is equal to E. In my duplication I in which is equal to be pie a square omega by two. Holy Square one by our signing Square Omega T. Which one for the simplification mean thermal power generators is given by P is equal to Be by a square omega by two. Holy Square one by our integration of 0 to T. Signing squad. Omega T DT by integration of 0 to TDT, which is equal to one by you are buy. Omega is squared B. Bye to hold the square is the answer

Okay. The question is the dimension formula of capacitance is as we know that the capacitance is equal to judge per unit uh judge. But in its potential difference. Yes we know that the potential depends B. S. W. Out of like you. So the dimension came Britain S. M. Elsewhere. The race to the government is too divide by and peer into D. So we know that C. Is equal to Q. O. W. W. O. W. Kim. So therefore capacitance C. Is they will do I divide by Divide by M. L. scared to us to Devour -2, divide by D. So therefore she is. It will do a scared d. Scared divide by M. L. scared the raise to the power -2 and therefore competencies. It will do I am raised to deport -1 And raised to the Power -2. Dear is to the Power four. And the areas to the power two.

Let's talk about this question. We need to find the values of the current in the world is using the child's laws. Uh So the first we're gonna apply uh the rule of north. So incoming current must be equal to the ongoing going girls. It means that I want to say let's use different color over here. So you're gonna say that I want plus I too must be equal to I. Three. So incoming should be equal to the outgoing current. That let's name this equation one Let's apply which lets supply. Let's take this loop. And uh get its equation start. That's gonna be negative eight. I won uh Then we have negative five I. Three and we have negative one I. Three. And this is negative for that should be zero. This becomes eight I one. We're just multiplying by minus on both sides. Plus six I three plus four equals zero. And I three can be replaced as I went to aside from this equation one so I three is replaced by I one plus I to plus four is equal to zero. So if you open up the parenthesis we have eight I one plus six I one plus six I two plus four is equal to zero. 806. I one is 14. I won. This plus six I two in this plus four is equal to zero. This quality vision. And now we're gonna do the same thing but over to the other loops. So this is the loop which we are taking. Uh So what does the equation is going to be? Uh We're going from here. So that's gonna be four plus I three plus 53 Plus three are too uh Then we have we're going in this direction so opposite to the current again. Plus I too -12 is equal to serious. That's going to be equal to 4 -12. Is -8 plus six. Three plus four. I two is equal to zero. Again. I three is replaced by Ivan plus I eat when we are adding it both sides. So this is how it's gonna look like. And this becomes if you have another parentheses six times I want plus six. I two plus four. I do is just 10 I two. And the secret wait they're in my to both sides that's going to be three. I one plus five. R two is equal to four. Let's call the situation number three. So we have to equation in terms of two variables. We have I wan and I. So from equation three let's try to find out the value of Iowa and that's going to be four minus five. Fire to over three. This let's name it four and this we're going to substitute over here. So if we do that we have 14 times 4 -5. R 2/3 plus six are two plus four is equal to zero. So if you open up the parentheses 14 times four is 56. Foreign times five is 70. I too and we are multiplying by three both sides. So this is 18 And this is Joel is equal to zero. So this becomes 56 plus 12 as 68 and this is -1860. This is going to be 52, I think there's 50-60 and 70 years. And so from here we have 52. I two is equal to 68 which gives us the value of fire to us 68 over 52. I think five is four is a common factors of four times one and seven or 17 or 13. So this is a required value of fire too. We can get the value of I one now from the equation four. So we have the value of I one as 4 -5 times 17/13 over tree. So this is going to look like uh 13 times force four entries 12 to one's. Uh This is gonna be uh five over here. So 13 times four is 52 we have 17 Times five is gonna be 85. And over here we have 30 times three is 39. Uh So 50 to minus 85 is negative 33 so negative 33/39. Common. Divisor is three. So that's gonna be negative 11 over 13. So I want is negative which means that it is opposite as to the direction which we assume assume. So we can get the value of A three. Now I three is nothing but I one plus I to so we're going to add the boat. So I think it's going to be equal to iowan. Uh I one which is negative 11/13 and I do which is 17/13. So this is going to be equal to 6/13 amputees required value of I. Three. And this is what we needed to. So we got the value of each of the current and this is actually what we needed, if you want to find a potential drop across each. So let's call this, we won let's call the Suite two. Let's call the Suite three. Let's call the suite for let's call this we five. So we can easily get that since we already have the values of current. So if you talk about we one that's going to be eight. I won if we talk about we too, that's gonna be five I three. Let's talk about the three. That's gonna be I three. We talk about V. Four. That's going to be three I two. We talked about the fire that's gonna be I do if you have the value of I wanna in two and 93 already. So it's a I just interested in the manager. So that's 11/13, 17/13. So let's talk about I one that's 11 or 13. 11/13. We substitute. That's gonna be 88/13. Uh then we have I Three which is 6/13. So for 6/13. Uh There's gonna be six times five is 13 13/13, 13. And this is 6/13. If you talk about I too. And let's move this a little bit down. We talk about. I do I do as 11 or 13 for 11 or 13. That's going to be 33/13. And this is 11/13. So this is the required voltage drop across each of the resistor. Thank you.


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