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4.) Indica te Which mechanism) (6l ,E1 SNz, Ez,au4] bae 2) Draw aU productf CIrclu which Product MaorOTsNa OCHg hochg not...

Question

4.) Indica te Which mechanism) (6l ,E1 SNz, Ez,au4] bae 2) Draw aU productf CIrclu which Product MaorOTsNa OCHg hochg not

4.) Indica te Which mechanism) (6l ,E1 SNz, Ez,au4] bae 2) Draw aU productf CIrclu which Product Maor OTs Na OCHg hochg not



Answers

Draw a stepwise mechanism for the reduction of epoxide A to alcohol Busing $LiAIH_4$ . What product would be formed if $LiAID_4$
were used as reagent? Indicate the stereochemistry of all stereogenic centers in the product using wedges and dashes.

In this problem, I can write this solution as and then die metal. So pen I blue then am I when react with or treated with allies L. At 4? Then the product form it? C h t c h t Ch two CH two, N ch three hole to therefore according to the options option B. It correct therefore option B. Each correct answer. Therefore Option B. It correct answer for this problem. I hope you understand the solution of this problem.

Hi everyone. So in discussion they asked the product acting higher. Obscene regulation Jessica plus, additional support of beauty and one will give a B is A is CS three CH two C o C. S, three beads, CH three ch, two ch, two ch oh then seeds, CH three ch two ch chocolates that Cholo and the CS three CH two CH plus and sewage. So in this case option is correct. Option E. It's correct current. Yeah. Your time Ladies CS three CH 2 C2 Taliban. See edge built one in on reaction with Ngos corporations and so forth & c. s. L. four. It should be a self old. Yeah, gives Yes CH three CH two C double bond. Oh ch three. Okay.

Already. We have this, uh, this quarrel period in undergoing some kind of addition. Ah, or a substitution of that chlorine for this dimethyl amine. Um, so you might recognize that it looks like a nuclear folk. A CEO home. I got a nuclear filic aromatic substitution. Only because you don't have a nacho file here and you're replacing ah Corning with ah Inamine, which is a base. So bases can be nuclear files. In this case, that is the case. Um and you may be thinking Okay, so what is the, um where is the electron withdrawing group? So impurity in that nice train being more Electra negative than carbon, the carbon atoms around it can act as much wrong Withdrawing group, Um, in this example. So in terms of our in previous video explanations, I've described the nuclear folk aromatic substitution mechanism is almost a pull push type Arab pushing cascade where your first pulling the electrons towards the electron withdrawing group after nuclear filic attack on the rig and you push them back towards the leaving group to force that leaving group out. So I just want to give a minute or two to talk about, um why you don't make ah this nuclear file and minus right. So why don't you make an an ionic base here and you might just be able to think like, Well, Matt, obviously that's not an acidic proton. Um, and it's not right, so Visa means so. Ammonia, for example, has a PK a of roughly 36. Um, these die algal amines might be somewhere in the mid to late twenties. So maybe 25 to 30 um, period in on the other hands or the Puritan iam. So let's say we were to probe made that period in this period in IAM cat ion ah has a PK around five. So this period idiom is similarly acidic to acetic acid, for example, so it's a weak acid, pretty close to hydro knee. Um, I'm not caught me. It's 10,000 times weaker than hydro me. Um, but it's a much stronger acid. Um, then, um, then that this guy right, So therefore you're gonna shift the equilibrium to keeping the period in deep resonated, keeping the amine pro nated, keeping the amine as n h r. Two and h as di methyl amine. So you're gonna leave this species as they are. Um, you may just from a PK argument. Um, also, because this is a weak acid. The end, um, the end and I on is a strong base. So even if you did form this Puritan IAM, it would immediately deep renate. But you're not gonna do that. Connecticut you That's impossible. So, bottom line, I just wanted to make a quick peek a discussion, um, to show that you're gonna have to react to your nitrogen nuclear file as is. So it does have that lone pair. Um, and therefore, that's what we're gonna use to, um, to conduct our our chemistry here. Right? So you know that the first step in a larger phone aromatic substitution is, um, nuclear Filic attack. So we're gonna go ahead and use our lone pair to attack, and you're gonna push the electrons away from the chlorine push that bonds onto the electron withdrawing group in this case, is the nitrogen. Yes, which already has a lone pair. So now you're gonna have the c l. That's bonded to this dime, Ethel. A mean now it's an ammonium, positive charge there. Sorry, that's on the ring. So here's your ring. Make room for nitrogen Here. Where now? We have bonds. Bonds Now, election has to own pairs. There is your negative right there. So, um, now you're going to, um, which is gonna happen first. Do you think d pro nation of this proton to make a neutral species on the nitrogen or you're gonna regenerate a romantic city? And the answer is, um, regenerate or a Metis city, um, be honestly, even in solution right now, you don't have a strong enough base unless you come in. Whether never another equivalent of ammonium. Um, that could act as a base, But you're going to regenerate automaticity first in terms of lower energy. That's what's going to lower the energy of the entire species. Um, right, So you're going to now you just pull the electrons towards nitrogen, and I were gonna push them back, um, away leaving group gets kicked out. You've regenerated aroma tous ity. I should actually draw the bonds as I ara pushed them. So that would be like this. Now you have this dime, Ethel Amenia, ammonium plus C l minus that you just kicked off. And then you can either use the chloride, um, to take the proton. Or you could bring in another equivalent of, um, the dimethyl mean because you're just gonna get dimethyl amino ammonium chloride, which is really just having hcl ends the ammonium anyway, So you could use either base to make this, um, dimethyl amino period in as your final product, plus HCL.

Hello Today we're doing problem nine point fifty eight. And this problem tells us that we're starting with this Alcohol is beautiful and we're reacting it with a strong acid sulfuric acid as well. A sodium bromide. We observed the major product being our alcohol bromide substituted reaction with our elimination product and anethe information as a minor products. So this asking us why do we observe these, uh, the's products in either major and minor product and draw the mechanisms that accounts for information on each of these products? So I feel remember no sodium will associate, so they won't associate any plus on br minus. I remember our sulfuric acid and associate too, because strong acid to H plus and a minus. So if you identify a nickel follow you see that we have the auction of the alcohol being a very good nickel file, they can pick up the proton from our strong acid. So what are we left with his pro native water? So this water ken has it can potentially fall off on its own. But if it were to do that, it would form a primate carpal carry on and remember primary karma, Catalans are not stable, Hossam. It must be either secondary or tertiary carbon kata and for it to go through s and one reaction mechanism. So because of that, it would form a primal, carnal Karen, we know that this is going going to go through an S and two reaction mechanism in which the new glove file must nuclear physically attack are left for the carbon to make a new bond. And when you make a bond, we need to break a bond. The bundle break is going to be a good leading group that we just formed, which is water. And this gives us our major product. Obviously, we see that this is a very spastic reaction, because sn two, it's two arrows all in one step. This is a one step reaction and therefore that is why it's going to be our major product. Just due to the reaction rates and the number of steps involved, it's now for the minor products we see that we have in an elimination product and we also have some sort of either formation. So if I was uses intermediate, we can also see that at the same time is competing for s and two reaction. We would have competition for E, too. So instead of our medical file attacking this electoral Philip Carbon, we can observe that this carbon is called alpha position. So right, how right next to right, adjacent to our alpha carbon is our beta. Carmen's right here. So next to the beta card on the beta carbons we have beta protons are a minus. Can pick up those protons making you bond When you make a bond break upon the bond that breaks his formation I'll king we make a new bond with the brake upon The bond that breaks is our good leaving group, which is water. This forms are elimination product plus H A V formation of our asset catalyst plus age too. So this was why this is going to be a major and minor product because this involves a little bit more steps and is not so straightforward as an s and two reaction. So obviously we know that s into will out compete are you into reaction? So we when we're dealing with organic reactions, we're starting with one molecule. But in actual organic reactions in the lab, you have thousands of these molecules reacting in your solvent of choice, which is sulfuric acid. So because of that, yes, One of these molecules has permanent water, but they're going to be hundreds. If not thousands of original stun reacted starting material still in the reaction mixture. And because oxygen has nuclear filic properties which we exploited in the very first step to pick up that proton oxygen can actually be used as a nuclear far and kick off the water on this activated electro file. So now we have a potential either formation in which we have a formation of water and we have a pro native ether. Remember, we have that a minus still So a minus can be used to depot. Nate, that and reformer Asset titlists Is that how we have either formation? So, as you see here, the probability of this happening is a lot lower than the electrified. Reacting with some sort of nuclear followed me out into the system. But because this is our solvent system and this is Thayer, hundreds and thousands of more molecules of UN reacted original story material Then are activated Electoral Father, This is also a possibility, but obviously s into will help compete and will be the major product


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