5

Twelve different video games showing substance use were observed and the duration of times of game play (in seconds) are listed below: The design of the study justi...

Question

Twelve different video games showing substance use were observed and the duration of times of game play (in seconds) are listed below: The design of the study justifies the assumption that the sample can be treated as simple random sample Use the sample data to construct 99% confidence interval estimate of the standard deviation of the duration times of game play: Assume that this sample was obtained from population with noma distribution4,422 4,4634,267 4,7234,569 4,7074,635 4,534887 3,9294,459

Twelve different video games showing substance use were observed and the duration of times of game play (in seconds) are listed below: The design of the study justifies the assumption that the sample can be treated as simple random sample Use the sample data to construct 99% confidence interval estimate of the standard deviation of the duration times of game play: Assume that this sample was obtained from population with noma distribution 4,422 4,463 4,267 4,723 4,569 4,707 4,635 4,534 887 3,929 4,459 4,960 Click the icon to view the table of Chi-Square critica values_ The confidence interval estimate is sec <0 < (Round to one decimal place as needed:) sec:



Answers

Twelve different video games showing alcohol use were observed. The duration times of alcohol use were recorded, with the times (seconds) listed below (based on data from "Content and Ratings of Teen-Rated Video Games," by Haninger and Thompson, Journal of the American Medical Association, Vol. 291, No. 7). What requirements must be satisfied to test the claim that the sample is from a population with a mean greater than 90 sec? Are the requirements all satisfied? $\begin{array}{cccccccccccc}84 & 14 & 583 & 50 & 0 & 57 & 207 & 43 & 178 & 0 & 2 & 57\end{array}$

So this question says that 12 different video games, 12 different video games I'm showing alcohol used webs act on the direct direction. Times of alcohol use were recorded with the times in seconds listed below. On, um, the question says, what requirements must be satisfied to test the claim that the sample is from a population with me. So we want to find out what we climb. It must be satisfied to test the clean that the sample is from a population with mean. So I want to know what that example has a population as a population with a mean greater than 90 seconds greater than 90 seconds. So we want to know whether that what requirements will be satisfied on def. The requirements are all satisfied. And by the way, the division time zarco used or seconds are 84 foot scene, 583 on this all in seconds. 50 um, zero. 57. Um, 207. What's the three 178 zero shoe on 57. Yeah. So, um, yeah, it's a soft this. We know we're going to know that the requirements that that's required requirements or that the sample is a simple random sample and that the population is normally you should be there for the sample size. For example, all the sample size is 30 or more. So therefore, do you come into the example? Is a random sample because it just has random numbers on population Is normality shooted? So that's what we're gonna rights. So requirements that a the sample, we can say that example is a random sample on the population is no matter distributed. The question is normal, AGIs present. That's what becomes self. So yeah, and we're going to create the instagram on the weeds off each bar has to be equal on That has to be called the frequency. So it recreates the instagram. So the instagram should look something like this. Um, gonna draw a straight line like this and drew this over like this. Andi, we're gonna have AIDS. We're gonna have from several. We're gonna have to We're gonna have four here. Um, six year now. I think I should have space this up. It's Kool Aid's here on then. Um, clean this. So yeah, we're gonna have zero over you. There are gonna have 100 over here. No, to 100 over here. 300 400 500 on 600. So this is where the line is gonna be, and it's gonna be all the way up to eat. Um, yes. And it's gonna be all the way up here. I'm sorry, I might not be the best at drawing, but make sure there's no actual looks, something like this. And then to schools that were here Mhm. The next one. She looked like this from two. All the rates have saw dried on something. Then the next one should be from my 100 each. So there's so yeah, this is what the Instagram should look like. And they used to go. There is no roughly bill shaped and therefore the just the population distribution is no approximately normal. So we can tell that the, um the instagram is in bill ships. Andi distribution is not opposed merely normal. So therefore their sample size is also less than 10 etc. As we can see on the requirements are not satisfied. So he's the requirements and satisfied

I want to test the claim that my population mean is greater than 90 seconds. Okay? And I want 0.5 significance level now if my significant level is 0.5 which would mean that when I'm conducting my statistical tests, my Alfa is 0.5 Okay, so what is going to be my confidence level? My confidence level. My confidence level is going to be 95% right. It is going to be 95%. If I show this over here, what is going to be my Alfa? This is the value of Alfa. The region in both the tails is going to be 0.5 So this is 0.95 and this is my confidence level. Now they have given us an interval. And they're saying that if the interval is found to be between 21.1 seconds, if the interval is found to be between 21.1 seconds, this is mute. And in the 1 91.4 seconds 1, 91.4 seconds. Okay. What can we conclude? I'm testing the claim that my mu is greater than 19, right? I'm testing the claim that my mu is greater than 90 seconds. Which means this becomes my alternative hypothesis. My alternative hypothesis. So what will be my null hypothesis? It is going to be mu less than equal toe 90 seconds night. Now, in this 95% confidence level, I have this interval and in this interval I can see that values below and above 90 both are present. Which means, for example, is a 35 seconds. It is also present here, 68 seconds that is also present over here. So all the values, about 21.1 seconds are presented this in trouble. Okay, So can I say that I have enough statistical evidence to reject my null hypothesis? No, I cannot say that. So I will say that I do not have enough statistical evidence to reject h not so we cannot reject H not V. Gone. Reject. Can't reject. H not. We do not have enough statistical evidence to say that the mean is greater than 90 seconds. And this would be our answer way. Our conclusion

In problem. Six. We're going to be using some data on their lifetimes off handheld video games tested clean that there is no difference in the lifetimes of two fronts off these handheld video games. And we're going to the doing so using their Wilcox on rank sum test at the 0.1 level of significance. So we have to follow for five steps with the first step is to step in hyper. This is, then we give the critical value Iraq the data, walk out the value of set and then compare them critical value of that and the but little by only upset that we can make the decision to fail, to reject or to reject the night. But this is so let's do the fasting, which is to state the hypothesis then now have. But this isn't the alternative policies, so they're not. Hypothesis is that there is no difference in the distributions off light lifetimes for the two brands. There is no difference in the distributions of lifetimes for the two brands, then the alternative report this is is that there is a difference in the distributions, more like times for the two brands next week going to give state the critical value. Um, and in our case, the level of significance 0.1 and therefore the critical Valley will be plus or minus two point my feet. Next, we have the details, runt for the two Brunt's of video games. And, uh, we're going to consider and n one and n two. We're in this case, and one is a sample size with this small a sample. And since these samples have the same number off, we do Kim's 11. We have to pick any of the truth, and in our case, we're going to use Brand B has N one. You can also use brand A and still arrive at the same position at the end. So they're some of Bronx for Brand B is given by 140. When we add up the values three for all the way to 22 then new are obtained from this formula is 126 0.5 sigma are obtained from the substitution is 100. No one is 15 points to three, and now we can substitute the values into the formula for that, and that would be 140 minus 136.5, divided by 15 points to three. When you walk that up to you, teen zed value 0.8 eight 65 At this point, we can compare the calculated that value, which is 0.8865 to the can critical belly of that, which is 2.5 feet. In our case, we see that 0.8865 is less than 2.58 and for that we make the decision to feel to reject that now. Thankful this is so in our case, we conclude that Bay's not enough evidence to reject the clean, that there is no difference in the distributions off light homes for the two runs. So there is such a harder clean that there is a difference in the in the distribution of nine times for the two brands. But there's no evidence to support this claim.

Hello. This is a problem. 45 and first we need to do a one sample T test um to find the confidence interval for the population mean the average can be found through Excel And there are 20 numbers. Your sample size is 20 And the average that we got is 24.1. No, Once we do the one sample T test we need to input our sample mean In the sample start aviation which is 4.3 in our sample size. We write down that it's a confidence interval for form you And we give it a 90% confidence interval And we find that the 90% confidence interval is From 22.4 4- 25.76. If we want to find a 99% confidence into the only thing that changes is this part here And we get that the lower limit is 21.35 And the upper limit is 26.85. So the 90% confidence interval form you is going to equal 22.44 To 25.76. And for the 99 confidence interval whore. Um You It's going to be from 21.35 To 26.85. Yeah. And now let's interpret the confidence intervals with 90% confidence. In the meantime us adults spend watching television using DVRs each day is and interval 22.44 To 25.76. No. For the other confidence sensual, it's the same thing with except the percentage with 99 confidence. The means time U. S. Adults spend watching television using to yours each day. Yes. And uh interval 21.35 to 26.85. Now if we take a look at the widths the west of the 90% confidence interval is 3.36 which is smaller then 5.5 for the 99% confidence interval.


Similar Solved Questions

5 answers
Pan AListthe values of the tour quantum numbers (n,€,mt,ma) tor each of the electrons in the ground slale dneanEssay answers are limited t0 about 500 words (3800 characters maximum, including %p3ce ) 3800 Character(s) remanngSubmaBeeVmi
Pan A Listthe values of the tour quantum numbers (n,€,mt,ma) tor each of the electrons in the ground slale dnean Essay answers are limited t0 about 500 words (3800 characters maximum, including %p3ce ) 3800 Character(s) remanng Subma BeeVmi...
4 answers
(b) Check the controllability of the following system:1 =Compute contTOI u(t) which takes the system state fTom the origin at time to (2.1)T at time Compute control u(t) which takes the system state from (2. 1)T at time to (3.3)" at time
(b) Check the controllability of the following system: 1 = Compute contTOI u(t) which takes the system state fTom the origin at time to (2.1)T at time Compute control u(t) which takes the system state from (2. 1)T at time to (3.3)" at time...
5 answers
Let S = {(€,y,2)lz,y,2 € R,z > 0}. Show that S is not & subspace of R3
Let S = {(€,y,2)lz,y,2 € R,z > 0}. Show that S is not & subspace of R3...
5 answers
Verify: sinh(x + y) = sinh xcoshy + cosh x sinh yHint: Use the definition sinh and cosh
Verify: sinh(x + y) = sinh xcoshy + cosh x sinh y Hint: Use the definition sinh and cosh...
5 answers
IetHnalRnnl alnenlanaealru naiye) WlDacaltoMerdHp?
i et HnalRnnl alnenlanae alru naiye) WlDacalto MerdHp?...
5 answers
Have small open top tank Into Which | could pour some water. The edges are all 2Ocm long: Ata top edge mount laser so that it points below the horizontal at 45". This means that the beam would hit the bottom of the tank right at the far side now pour water ( nwiter 33 ) to depth of 1Ocm into the tank; how far from the far side does the laser beam hit the bottom of the tank? Be sure t0 drawa good picturel Submit an Image of your solutlon below;
have small open top tank Into Which | could pour some water. The edges are all 2Ocm long: Ata top edge mount laser so that it points below the horizontal at 45". This means that the beam would hit the bottom of the tank right at the far side now pour water ( nwiter 33 ) to depth of 1Ocm into th...
5 answers
Provide an appropriale responseIx +y = 9and dxldt = ~3,then what is dyldt when x = 1 andy = 22Select one:A. 3B.C.D. 2
Provide an appropriale response Ix +y = 9and dxldt = ~3,then what is dyldt when x = 1 andy = 22 Select one: A. 3 B. C. D. 2...
1 answers
A scuba diver releases a 3.00 -cm-diameter (spherical) bubble of air from a depth of 14.0 $\mathrm{m}$ in a lake. Assume the temperature is constant at 298 $\mathrm{K}$ , and the air behaves as a perfect gas. How large is the bubble when it reaches the surface?
A scuba diver releases a 3.00 -cm-diameter (spherical) bubble of air from a depth of 14.0 $\mathrm{m}$ in a lake. Assume the temperature is constant at 298 $\mathrm{K}$ , and the air behaves as a perfect gas. How large is the bubble when it reaches the surface?...
5 answers
CDSHP332Jolou Idcntill-tien: ~Ll"n deecu Elion and anion r itilled Uhe pumIe lavenist color Icllawit? nsul E.turI Il:mck "cre' ngiltive_ Ic WiIlIc VIed oleIhitt The anium lest #as Jgaltive anoni [L45 prodlrcd EIs bubble Ule Icsl tuhe suluuen[Xetetire the chewnical olmul of $oxr Urkn01n salt hased these lests;(Unkron salt fotrrwulaExpralion;Fellf1?
CDSHP332 Jolou Idcntill-tien: ~Ll"n deecu Elion and anion r itilled Uhe pumIe lavenist color Icllawit? nsul E.turI Il:mck "cre' ngiltive_ Ic WiIlIc VIed oleIhitt The anium lest #as Jgaltive anoni [L45 prodlrcd EIs bubble Ule Icsl tuhe suluuen [Xetetire the chewnical olmul of $oxr Urkn...
5 answers
JEzatclzs =equcuze {2n } aid to be Ccuchy KV > U JeN #l#e N,i." > N Isn -ml< . Fil ku tb dulaL @: *w Izllowing pusl (EatevOry coytrgert #quCDcO Cauz1%,S646 wich ~ura KCIl Llr= 6>1 Cl & Nauch Ik4 vk € N #>N I" = 2<{ Now skow tkut tbbs N setiatisa (ha dlicinz cexlition fer Cxuchy;
JEzatclzs = equcuze {2n } aid to be Ccuchy K V > U JeN #l#e N, i." > N Isn -ml< . Fil ku tb dulaL @: *w Izllowing pusl (EatevOry coytrgert #quCDcO Cauz1%, S646 wich ~ura KCIl Llr= 6>1 Cl & Nauch Ik4 vk € N #>N I" = 2<{ Now skow tkut tbbs N setiatisa (ha dlicinz ...
5 answers
Find Ine Intarval on whlch the graph &t f is cocave upward. Ine Interval on which the groph & {i5 corcave downward and ho coordinates ol the Iniecon points .fl) x +122'_ Tr + [Answerthe inlervawhich ine graph of f is concave upNardIhe interval on which the grapn offis concave dowmtardand Ihe X, coordinates of the infectionpoints:_
Find Ine Intarval on whlch the graph &t f is cocave upward. Ine Interval on which the groph & {i5 corcave downward and ho coordinates ol the Iniecon points . fl) x +122'_ Tr + [ Answer the inlerva which ine graph of f is concave upNard Ihe interval on which the grapn offis concave dowm...
5 answers
(b) The male award winner who was 74 years old was identified as a potential outlier. If this award winner had been 54 instead of 74 years old, what effect would this decrease have on the following statistics? Justify your answers.The interquartile range of male ages:The standard deviation of male ages:The mean of male ages:The median of male ages:
(b) The male award winner who was 74 years old was identified as a potential outlier. If this award winner had been 54 instead of 74 years old, what effect would this decrease have on the following statistics? Justify your answers. The interquartile range of male ages: The standard deviation of male...
1 answers
Sdve the initial value pr ablem1-3 Y(.1) =0,996 Wth h=0.1Use () the Inproved Euler method tofind y (1.2); (II) faurtha der Runge Kutta method tofind y (1.3).
sdve the initial value pr ablem 1-3 Y(.1) =0,996 Wth h=0.1 Use () the Inproved Euler method tofind y (1.2); (II) faurtha der Runge Kutta method tofind y (1.3)....

-- 0.024295--