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Find v*u,v=3i - 2j and u = ~ 8i + 6jOA 24i - 12j 0 B. 36 0 c 5i + 4j 0 D. 12...

Question

Find v*u,v=3i - 2j and u = ~ 8i + 6jOA 24i - 12j 0 B. 36 0 c 5i + 4j 0 D. 12

Find v*u, v=3i - 2j and u = ~ 8i + 6j OA 24i - 12j 0 B. 36 0 c 5i + 4j 0 D. 12



Answers

Find $ a \cdot b $.

$ a = 3i + 2j - k $ , $ b = 4i + 5k $

So for this problem we are given that A. Is going to equal the vector um five I plus three J. We're just going to put this in component notation 53 And then the b vector is going to equal negative i minus two J. So putting in component notification will get negative one negative two. So then when we add these together um A vector plus the B factor will end up getting that A. Plus we equals 5 -1, which is 24 And then 3 -2 which is gonna be one. That's a. Plus the vector. And then we can also calculate other things. Let's do the magnitude of a. So we see that the magnitude of a is going to equal the square root of five square. So Square 25. What's The Square Root of 9? Okay, now, between the square root of 34 as our final answer.

Yeah. For the given problem, we want to evaluate some of the functions knowing that A. Is going to be vector for negative 32 Mhm. And B will be the victor two negative four or 20 negative for so some of these factors A plus B is going to be four plus 26 maybe a three plus zero standing free. And then to minus four is going to be negative too. So that the sum of the vectors in the components. Now let's look at how to calculate the magnitude. It's gonna be very similar to how it was before the square root of fourth grade, which is 16 Plastic Square root of negative surplus. A negative free spread which is nine. Um so it's gonna be 25 And then 25-plus 4. So we'll have route 29 as the magnitude.

Okay. This question wants us to find the dot product of you envy, given that the vectors are as follows. So to do this, let's just use our formula for you dot the So all we do is multiply correspondent components and then add them together. So we're gonna multiply the I had coefficients, and then we're gonna add them to the product of the J hat coefficients. So our first I had coefficient is three. And our 2nd 1 is negative too. Then we're gonna add that to our product of the J hats. So our first coefficient is too, and our second is minus three. So this gives us negative six plus negative six, which is equal to negative 12 as our dot product.

All right. So we want to find Thea at that price off to Victor's, which are represented by I N J. The 1st 1 is three I plus four j and sick Morning seven I crust to J. All right, so that these are just, ah special weight of represent representation of factors. Bye, I and J, where I is the Univ actor of 10 and J issue unit Vector 01 So that would be three for for you in seven negative, Two for V all right, So that that pulling off this, too, would be three times seven plus four times negative too. And that will be 21 minus eight, So that's 13.


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