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Prolon entens paralle -Dale capacilor Iraveinarigh: 7r0 (mM Trom each plate_speed or 1.279 410 snowt (nenqure Ine Qistance decreen e plales 1-56 Cm_ ne proror enie...

Question

Prolon entens paralle -Dale capacilor Iraveinarigh: 7r0 (mM Trom each plate_speed or 1.279 410 snowt (nenqure Ine Qistance decreen e plales 1-56 Cm_ ne proror eniefs ue capachor nallmay belwieen (ne [Dp plale a10 (ne Doidcm Dare Wsacce sncxin the figure cadacito NYC un form lectric fleld between the plates that nts downward from te top plate bottom Dlate Neqleclino nrvitationa morccs Mhat honzontal Cistancc docs tnc Droton travcrsc Dcforc protcn hits thc bottom platc?

prolon entens paralle -Dale capacilor Iraveina righ: 7r0 (mM Trom each plate_ speed or 1.279 410 snowt (nenqure Ine Qistance decreen e plales 1-56 Cm_ ne proror eniefs ue capachor nallmay belwieen (ne [Dp plale a10 (ne Doidcm Dare Wsacce sncxin the figure cadacito NYC un form lectric fleld between the plates that nts downward from te top plate bottom Dlate Neqleclino nrvitationa morccs Mhat honzontal Cistancc docs tnc Droton travcrsc Dcforc protcn hits thc bottom platc?



Answers

Fluids of viscosities $\mu_{1}=0.15 \mathrm{N} \cdot \mathrm{s} / \mathrm{m}^{2}, \mu_{2}=0.5 \mathrm{N} \cdot \mathrm{s} / \mathrm{m}^{2}$ and $\mu_{3}=0.2 \mathrm{N} \cdot \mathrm{s} / \mathrm{m}^{2}$ are contained between two plates (each plate is $1 \mathrm{m}^{2}$ in area). The thicknesses are $h_{1}=0.5 \mathrm{mm}$ $h_{2}=0.25 \mathrm{mm},$ and $h_{3}=0.2 \mathrm{mm},$ respectively. Find the steady speed $V$ of the upper plate and the velocities at the two interfaces due to a force $F=100 \mathrm{N}$. Plot the velocity distribution.

Capital and the battery seven in this question says that a square plate 0115 m side most barrel to second plate, Well with the velocity .1 m/s, both players being immersed in water. The viscous forces given coefficient of viscosity, ETA. Has been given to the stand between the plates to find the distance between the plates. Okay, A little bit started. You know that with task force F is equal to eat a D. V by dx. So we need to find the X. D X. Will be equal to eat a by the. And here it is D. V. Now the day has been given 0.001 poise, 01 piles into 0.15 squired. And this is DV 0.1, divide by 4 0.0025 Newtons. So if you calculate This comes out to 0.000 nine m. So they should be dancer. Thank you an option number C. Thanks

In this question, the relationship between see it is trees and force is given by how is equal toe up by Newton per meter square And how X y can be written like this. Now, in the next step, how x y can be further return like this? I just put the value now, going forward and solving it. We can write that equation like this. So in the next step, I just put some values which are given in the question. So just look at it carefully wise, coming as minus etched by two. And how X y can be written like this. I just put the values here. So on solving we get a question like this on in the next step, I will calculate it. So just look at it carefully. I just put all the given daughter here. So we get how x y as 2.2 it Newton meters square Newton per meter square. So I can be calculated like this. I just put the value and get this as our answer

In this question we will understand about some basic mechanical properties. Offload The question is there's a square played off .1 metal side. So it is a place to find. one m. The velocity is given us. Do you know .1 m/s? The whiskers force is given as Judah, point Judah Judah to Jordan and the coefficient of the viscosity. He's given us to the point to the one boys. Right. So we have a didn't mind the distance between the blades in middle. So first of all, with the help off the edge, we can calculate the area. That would be called a 0.1 and 2.1 That is point to the one made a square. Now we can convert poise into the cowboys. So this would be called the trigger point. You wanna point then That is fine. To the judo one. The cowboys. Mm With all the expression 44th that is given by FS equals sunita a davey divided by the X. Right. So forces given us .002 Coefficient of his skull cities point. So you guys were the one Because sectional area is point to the one. The change in the velocity across the land is 0.1 and the distance between the plate is ex like So when we simplify this we get the value of access judo point judo judo judo five made a late. Hence the correct option is the

The solution off the answer. His dad Retain the falling properties off water from the table that is physical Properties off water table. Be point to corresponding toe the temperature off 20 degree Celsius. No dynamic viscosity of water that is mu equal toe 1.0 to multiply by 10 to the power minus three and Esper Meter Square obtained the following properties off the filing glycol at 20 degrees Celsius from any standard test book. Now dynamic viscosity off. It'll in glycol that is new E G, equal to 1.99 Multiply by 10 to depart minus toe. An Esper meter square. Now toe hold The center played is a stationary position. The sheer force on the top and the bottom side off the Centerplate must be equal in magnitude and oppose it in direction. In other words, the share stress at the top and bottom sides off the plate must be equal, since it has same area on the top and the bottom. So now uh huh, it required the sale stress on the both sides off the plastic plate do toe water, and it's highly black hole from Newton's law off viscosity that tea towel atop is equal Toto at bottom. So here we put it. We know the equation. And we by simplifying the simplifying this equation, get mu w equal to veto by B one equal to Mu is equal. Toby bottom by b two and we consider it as equation one. Now here Mu is the dynamic viscosity V is the velocity off the plate? B one is the thickness off water. They'll be too. Is the thickness off ethylene glycol layer and D V by D. V is the velocity off Great Dent. So here all the variables are cleared. Now we will calculate the velocity of bottom played by using the equation one here, This was the Christian one. Now substitute the values that 1.0 to multiply by 10 to the power minus three and s per m a square form you w 2 m per second for Vito, 0.0 01 m that is 0.1 centimeter for B one, 1.99 multiplied by 10 to departments to an s per meter squared for music and 0.2 m at 0.2 centimeters for B to. So here in this value we substituted, we are substitute the values in the equation and we get we bottom equal toe minus 0.2014 m per second. Therefore, the velocity off the bottom plate is 0.0 0.2014 m per second, minus zero point toe 014 m per second Health. The negativity signed indicates that the bottom played moves towards the left. So this is a complete solution and detailed step by step. Please go through this. Thank you.


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