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Q1 The following are two nuclear decay reactions"Fr + {He + %At "N _v_%e+ "0 It Is common that the electric charges Is not indicated (but can be): Wh...

Question

Q1 The following are two nuclear decay reactions"Fr + {He + %At "N _v_%e+ "0 It Is common that the electric charges Is not indicated (but can be): What are the products of the decay of Francium-220? b What are the products of the decay of Nitrogen-16? c Is an alpha particle gained or released in the decay of Francium-220? d. Is an electron gained or released in the decay of Nitrogen-16? e. What is the mass number of an alpha partide? What is the charge of an alpha particle? 9. Wha

Q1 The following are two nuclear decay reactions "Fr + {He + %At "N _v_%e+ "0 It Is common that the electric charges Is not indicated (but can be): What are the products of the decay of Francium-220? b What are the products of the decay of Nitrogen-16? c Is an alpha particle gained or released in the decay of Francium-220? d. Is an electron gained or released in the decay of Nitrogen-16? e. What is the mass number of an alpha partide? What is the charge of an alpha particle? 9. What is the mass number of a beta particle? ha What is the 'charge of an beta particle?



Answers

Questions 1–3 (A) Alpha decay (B) Beta decay (C) Gamma ray (D) Fission (E) Fusion Select the term from above that identifies the nuclear reactions described in questions 1 to 3. $_{92}^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow_{38}^{90} \mathrm{Sr}$ $+\frac{143}{54} \mathrm{Xe}+3 \mathrm{n}+$ Energy

Okay, this is this is a softball. Were given three equations. You have to identify the decay. So the main thing you're looking for here, you can pretty much ignore all of the elements, right? You're just trying to find, um what decay is happening here by what particles were being admitted. So you're gonna want to focus on these guys right here. So make she I copied it right, which I did, Right. So in the first, that is an electron, which means that electrons are being admitted and that happens in beta decay. They'd, uh second, you have helium. Helium is enough. Particle. That's gonna be Alfa decay. And there, in the last one, don't be deceived by the E. There is a positive one there for the charge. So it's not an electron. It's the antimatter equivalents of an electron, which is a positron. So we had that. We say that is a positive. You could see positive beta particle, but it's really a positron. So that's gonna be positron emission. So a is beta decay. B is Alfa decay. See? Is positron a mission

Yeah, the beta decay, we have given that each uh massive trans particulars concurrently. one. So basically in the first scenario, we have given that in a bitter decay profound is undergoing to become monitoring. Right So and two particles like the electron on uh or up a project that is just having a same charges electron. But in the positive. So basically if Peter is converting into neutron proton is converted or neutral, that means what one positive charges lost lost in right. So for the sake of the charges remain, you know, con job or rather balance or rather it becomes child, you know, charged. So that means one electrons would be emitted so that if you want to put, you know, the neutron have zero charge that was if this is losing one port town. So similarly they will emit electrons so that it will, you know, give me a stable. So in the next part, if bitter in the bitter decay, if neutron is converting to program, that means one positive charges created, One projective charge is created. Or rather what we can say each that, uh, if a proton, uh, undergo, and if neutron undergo a bigger dick, it to become a proton, uh, if under grow, which are addicted to become important that so now charge less quantity becoming positive charge. So now in this case, what will happen? So now the project runway limited. Okay, thank you.

So the answer to this problem is going to be option A. That is an Alfa decayed on. I'm going to explain. Why is that so? Basically an alpha particle Is the nucleus off a Sheila Martin? That is, Did not it as this. Now, when two protons and two nutrients are released from Tori um 27. So from this two protons until Nugent's are released on dhe, we get a resulting isotope off J D a 2 23 No. Okay, let me just lighted the correct way to 23 on This is I told you to 21 Mar adding together the atomic numbers off helium on DDE ready and 2 23 as well as adding together the atomic masses. The drivel fought in 2 27 So if you add the atomic masses and a comic numbers off Celia Andre, don't radio. Then you'll be able to get the atomic number and atomic masses off Valium. Therefore, we can say that the whole process is on Alfa Dick. It because that is a decayed off on as a particle mentor, IAM goes to stadia

Let's look at this reaction for its anti Proton. When the writer inside, we have the messes off the neutron and the mess deposit China, which is the same as an electron. Some of these masses gives us one point zeros, you know, nine to one full, you and the mess off the proton. On the other side of the reaction is 1.0 seven 276 you and then we can see at the messes on either side of this equation on the bed. It's that is the mess of the neutron. Best a massive positron is greater than the mass of the proton, and therefore this reaction cannot occur because energy input is required. So this reaction would violate the more conservation of energy. Secondly, what happens? Protons are not bound to the nucleus. Well, if these protons are not free and they have voluntary nucleus in this reaction, Mayo cop you to electrostatic repulsion off the protons in the nucleus. His reaction now becomes possible. And in our example, off this reaction, we can calculate a Cuban you if we add seven electrons to both sides of the action to obtain the reaction from neutral atoms. We get that nitrogen 13 seven at him it comes He common 13 at him, plus in postural plus an electron. That's it. You clean up new and then we can calculate the Cuban you. But its reaction que venue we know is the mess off nitrogen 13 minus the message of the right hand side, which is the mess common 13. And because it trying electron both have the same mess. That's minus true comes a massive electron by honest, a massive neutrino. All this multiplied by C squared so we can put all bad using using our tables. The mess off imagine 13 in atomic mass units is 13. When's your owes you? Five, 739 You minus a mess of carbon 13 13 00 three 55 tends you minus two times the mass of an electron which is to into five point for nine claims to into the minus four you and the mass of the neutrino zero. Now all this multiplied by C squared, which is equivalent to 931 five Makeup electron volts. But tell me mass unit against we can calculate our energy mega electron volts to be one or two, make a electrical holes


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