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Question

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Answers

5. In the figure below, R1 = 100 ?, R2 = 50 ?, and the ideal batteries have emfs ?1 = 6.0 V, ?2 =
5.0 V, and ?3 = 4.0 V.
(a) What is the current in resistor 1?
(b) What is the current in resistor 2?
(c) What is the potential difference between points a and b?

Hi friends in the given circuit we have to find total conductance. Now you can see and doctors lot with green color who have been baron. So 12,100 12 million hendrick. 12 many Henry marked with green color in parallel. It will give you the value one over one by 12 plus one by 12 plus one by 12. So it is to be food micro Henry. All these are micro handy not the million handy so that we make a correction yet all these are my group. Now this circuit can be modified and this here's a modification of it. Well micro Hendrick, mm hmm. Yeah, This is also 12 Micro Henry here you will get for my true Henry and for micro Hendrick. No in the end DR Marx with blue color to be in parliament. So 12 Micro Henry and 12 micro hand ready marked with blue color in parallel. So total in the sense of the resulted we will get six micro ended and finally six micro hungry for micro 100 and for micro Henry in series. So total independence of the circuit will be six plus four plus four, package 14 micro 100. That's all thanks.

Students we have given the land. Uh huh Charlene Lloyd is 0.92 centimeter. And cross section area is 0.32. Number of Tens is 104. Um you notice for him to 10 to the power -7. Now we have to find the self conductors. So the formula for self inductive since is a call to do not and Squire A I. L. His self in a tense. The cult of New North and a squared A. By and right. So we will put the values communities for bye or buy into 10 to the power -7 Number of tons 104 area of cross section, A 0.032. This is in centimeters the Squire. So we will convert it into meters square. We'll be playing with 10 to the power minus four divided by length, which is 0.92 centimeter. So I will convert it into meter by multiple language tend to be far minus stood. So this is the self injectors. We will calculate this. So this is a call to four point 73 into 10 to the Power -6 Henry. This is the answer. I hope you understood. Thank you

The question. And we have been given and ask the adults circuit with the register and register. Okay. It's been given up a step. Read distance has been given. So our is 1-44.4 on Capacity resistance X is 79.3 home. And Indacctive resistance. Excel is 131. .5 home. So I have to find the impedance of the aral sea. Is it? We know that impedance of viruses entities that will be equal to uh square plus X. L minus X. C. Hold square. So 144.4 whole square less 17 9.3 -103.5 Old Square. Okay, so from here we can find a value of said by using it is 144.4 Hopes Quest. Yes, 79.b 123.5 foursquare under rule. Uh huh. 151.01. So impedance Approximately 151 on. Thank you.

So here in this problem we are given this circuit diagram and the resistance are one, we are giving us 100 home under registrants are too, we are giving us 50 home and the aim of E one, it is six fault E M f E two. We have five walt and finally a three we have forward. Now there are three parts integration in the A part. We have to calculate the current and the register one in this register, we have to calculate the current. So we'll be holding the A part first. So let me show the direction of current. We can assume that the direction of current in this loop is like this Iowa is flowing like this and here I too would be flowing like this and it's a junction and I three will be flowing like this. So this would also be I won and this would also be I won and here it would be I three. Next we can apply the junction rule and we are naming that. This is loop number one and this one is loop number two. Next we can apply at the junction rule now. So the junction rule and it will be applying junction rule at this point at this point. A So we can write that the current flowing in to the junction should be equal to the current flowing out to the junction. Basically we're using the conservation of charge. So I three. It should be called to I want bless I too. Next we can apply the loop rule which says that the sum of voltage around a closed loop is zero. So basically a party to calculate the current register one. So we can apply the loop rule here. So we're gonna start from this point, this is now we are moving towards this direction and the current is also moving like this. So the voltage we're going to decrease here so minus I three times Erdogan. Plus now here the voltage we're going to increase. So it would be plus a. Two is equal to zero. So from here the current I. Three, it should be equal to B two over our one. So the M F E two, we have five fall and the value of registers are when we have 100 homes. So from here the current I three comes out to be us 0.5 MPO. So we can say that the current I. Three, he calls to 0.5 ampere and which is the current in the regions in the register Erdogan. So this is the answer for the A. Part. Next we'll be solving the B part and in the B part we have to calculate the current in the register. All too. So here we have to calculate the current. So he also, we're going to buy the loop the loop rule. So we'll be starting from this point. This is from plus to minus or voltage. We're going to decrease here so minus E. To and Harold Wall is going to decrease some minus E three. Next we are moving in this direction and the current is also in this direction of voltage blew into degrees here so minus I want times are too bless. This is E one. Head of old age is going to increase as equals two zero. Now we can put the values this is minus two, is five minus 83 is four minus I one. We have to calculate times are too we have 50 home bless you one. So even we have six fault and it is equal to zero. It's not going to simplify for I one and we get value of Tijuana's negative 0.6 ampere you hear negative signs notes that are assumed direction of current is wrong. So actually it should be flowing in the opposite direction of the resumed direction. All we can say that I won that is the current and register to is 0.6 ampere. So this is the current and the register to next. We'll be solving the C. Part of the problem. Now in the C part we have to calculate the potential difference between point A and B. So we a minus V. B. We have to calculate. So I'm gonna start from this point so we a minus here. The world is going to degrees so minus 82. Similarly minus E three is equals two VB. So from here we a minus VB. Is it called to A two plus C three now? But the village either we have five plus E three, we have four. So from here we'll get the answer. Us. Nine World. Therefore, the answer for the C part S nine volt. So this answer for the C part. I hope you have understood the problem. Thank you.


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