So let's look at all the courses that we have. We have. I'm Michigan. Call it M 1 15 for math. M 1 16 m, 1 85 m, 1 95 C. S, 101 CS 102 C s 2. 73 CS 4 73. Um, then we want to look at which ones can be paired because we compare those. Then that means we can have fewer time slots because a lot of them we have students that aren't in either there in one or the other, but not both. So we'll have. We see that no students are taking both 1 15 and 4 73. So the red time slot could be our first time slot. And then we see we have no students taking 1 16 and 4 73. Um, But before we can do this, we have to make sure that no students can take 1 15 and 1 16, and we see that that is one of the cases. So because two students can't take be taking both 1 15 and 1 16, we can make 1 16 one of the final blocks. Oh, that can all be in one block the red block. Um, and then we see 1 95 and 101. Um, none of those students are in both. And then 1 95 in one or two 1 95. 1 or two. Let's see if 1 95 and all right, let's see if 101 in 102 can be together, though based on what we see 101 and one or two could potentially have students in both. So for that reason, we cannot, um, have students. We can't group them all together. We'll have to separate them to an extent. So what will end up doing is just letting one of to stand by its own. And then we'll at 1 95 and one a one b in the same time slot. Then we have 1 15 and 1 85 and 1 85 and 1 95. So since we have 1 15 and 1 85 but we know that 1 85 does not go with um, since 1 85 doesn't go, it goes with 1 15. But since it doesn't go with 1 16 or 4 73 for that matter, Um, it's gonna have to stand on its own then. We also see that to 73 will have to stand on its own as well. So we get Yes, sir. Right here. And then we see that total. We have five blocks of time. We have read s. That's one. Green is to blue is three. Purple is four and Pincus five.