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{107#What is the pH ofa 0.245 Mammonu Joluton? Exptes Your answe numericelly [7o decha placeeView Avallable Hint(s)9.31SuhmiPuexlou AniwatIncorect;Aquin; attampte r...

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{107#What is the pH ofa 0.245 Mammonu Joluton? Exptes Your answe numericelly [7o decha placeeView Avallable Hint(s)9.31SuhmiPuexlou AniwatIncorect;Aquin; attampte remalningPart BDeteen 187iz4men Iton corceallon? Ekprese the perot nipe crank thfee tuuilicant fiqures.Ayailable HInacsl69

{107# What is the pH ofa 0.245 Mammonu Joluton? Exptes Your answe numericelly [7o decha placee View Avallable Hint(s) 9.31 Suhmi Puexlou Aniwat Incorect; Aquin; attampte remalning Part B Deteen 187iz4men Iton corceallon? Ekprese the perot nipe crank thfee tuuilicant fiqures. Ayailable HInacsl 69



Answers

Determine the $\mathrm{pH}$ of each solution. a. $0.10 \mathrm{M} \mathrm{NH}_{4} \mathrm{Cl}$ $\begin{array}{ll}\text
{ b. } 0.10 \mathrm{M} \mathrm{NaC}_{2} \mathrm{H}_{3} \mathrm{O}_{2} & \text
{ c. } 0.10 \mathrm{M} \mathrm{NaCl}\end{array}$

Similar to the previous problem. We need to identify what is stronger for part A. We have potassium hydroxide and we have barium hydroxide. They are both strong bases, so they contribute equally by completely dissociating according to their concentrations. Potassium hydroxide is 0.5 Moeller barium hydroxide is 0.15 Moeller, but we get to hydroxide is for every barium hydroxide. So the total hydroxide concentration from both of these strong bases completely dissociating is going to be equal to the contribution from potassium hydroxide at 0.50 Moeller and two times the contribution from barium hydroxide. Because there are two hydroxide for everyone. Barium hydroxide. So two times 20.15 Mueller and we get a total hydroxide concentration of 0.80 Moeller. So the pH is going to be the negative log of the hydro knee, um, concentration, which is going to be the hydroxide concentration we just calculated divided into K W. We take the negative log of that ratio and we get a pH of 12.90 for the next one. We recognize that we have ammonium, which is a weak acid, and we have hydro satanic acid, which is a weak acid. So we have to weak acids, and we want to figure out which weak acid is stronger. So we'll solve for the que a value of ammonium by taking the K B value of ammonia, which we looked up and dividing it into K. W. And we get 5.68 times 10 the negative 10. Then we look up the K a value for hydro satanic acid, and it's essentially the same. 4.9 times tend to the negative 10. So one way to handle this is to assume that both of them are behaving to the same extent. And we can some there to concentrations together to get a total weak acid concentration and then just use an average K value something around five times 10 to the negative 10. Then the hydro knee. Um, concentration would be equal to some average K, a value multiplied by the some concentration of both of the weak acids with essentially equivalent K A values. And we get a hydro knee, um, concentration of about 1.4 times 10 to the negative five, and then we take the negative log of that and get a pH of 4.85 for the next one. We have a solution that contains rubidium hydroxide, which is a strong base, and we have sodium bicarbonate where bicarbonate is AMFA, Terek and can behave is an acid or a base. So it is likely that if we have the strong base rubidium hydroxide in a solution with potassium carbonate that that rubidium hydroxide is going to react with the bicarbonate and produce just carbonate. However, the solution in the solutions manual does not consider that complex reaction. So I'm not going to either. I'm just going to assume that the solution has already reached equilibrium, and these are the concentrations of rubidium hydroxide and sodium carbonate after reaction has occurred. If that's the case, then we focus on the stronger of the two, which is rubidium hydroxide, and we get a hydroxide concentration equal to the rubidium hydroxide concentration of 0.75 So the pH will be equal to the negative log of the hydro knee, um, concentration, which is the hydroxide concentration coming from rubidium hydroxide divided into K. W. And we get 12.88 then for D. We see that we have a solution of the strong acid perk Lorik acid and a solution of the strong base potassium hydroxide. Now, in this case, in order to get the correct answer, we do need to recognize that there is a reaction between these two and that some of the potassium hydroxide is going to consume well, all of the potassium hydroxide is going to consume some of the perk Lorik acid. So the concentration than of HCL 04 is going to be the 40.88 minus what reacts with potassium hydroxide. 0.0 to 2 and we get a concentration then of the strong acid, um, folkloric asset of 0.66 So the ph, then it's going to be the negative log of 0.66 or 1.18 Then for the last one, we see that we have a solution of sodium. Ah, hypochlorite hypochlorite came from the acid Heiple Cloris acid. So itself is a base, and then potassium iodide does not do anything to affect the pH of the solution. Potassium coming from the strong based potassium hydroxide and iodide coming from the strong acid hydro hydro I otik acid. So we focus on the c l o minus to determine the pH of the solution. We can calculate the KB of Cielo minus by dividing DK a value of HIPAA Cloris acid into K W to get a K value of 3.45 times 10 the negative seven. Well, then get our hydroxide concentration by taking the K B value multiplied by the concentration of Hippo. Cloris, I'm sorry. Multiplied by the concentration of hypochlorite ceelo minus at 0.115 Take the square root of that and we get 1.99 times 10 to negative four. This is definitely less than 5% of the 50.115 So we don't need the quadratic we can then get the pH by taking the negative log of the hydro knee. Um, concentration, which is the hydroxide concentration we just determined divided into K W. And we get 10.30

This one similar to the previous 11 37 where we have to identify what it is we have in solution. Is it a strong acid? A weak acid, a strong base or weak base? Is it coming from assault? Is it an anti on? Is it a cat eye on for the first one? We have H N 03 Hopefully you've memorized your strong acids and you would identify H n 03 as nitric acid, one of the strong acids. So with a concentration of 0.650 for nitric acid, we have a concentration of 0.650 of hydro knee. Um, we take the negative log of the 0.650 to get our ph of 1.19 for the next one. We have a weak acid, nitrous acid, H N 02 and to solve for the pH the hydro Nia, my on congee calculated by taking the concentration of nitrous acid 0.150 multiplied by its K A value which you could look up at 4.6 times 10 to the negative four, and we take the square root of that product to get 8.31 times 10 to the negative three. Moeller. We verify that this is less than 5% of the original 50.150 and it's not so we're going to have to use the quadratic. We'll go back then and solve using the expression K A is equal to the hydro knee. Um, concentration squared, divided by the original concentration of the weak acid minus the hydro knee. Um, concentration. Using the quadratic, we get something very similar to what we had up here because this was a close approximation of 8.8 times 10 the negative three. Moeller. We then take the negative log of 8.8 times 10 the negative three Moeller to get our ph of 2.9 for the next one. We recognize that we have a strong base in solution. Potassium hydroxide is a strong base that completely dissociates and produces because it's concentration was 10.15 Moeller a 0.15 Moeller hydroxide To get pH. We need to take the negative log of the hydro knee, um, concentration. But the hydro knee, um, concentration is going to be K W 1.0 times tend the negative 14 divided by the hydroxide concentration of 140.195 So taking the negative log of this ratio, which is the hydro knee um, concentration gives us our pH of 12.29 for the next one. We recognize C H three n. H three is to conjugate acid to methyl amine, so we need to look up the K B value for methyl amine so we can solve for the K a value of its conjugate acid. We divide the KB value of methyl amine 4.4 times 10 the negative four into K W to get R K a value for its conjugate acid, which is what we have at 2.27 times 10 to the negative 11. Then using that K a value we can solve for the hydro knee, um, concentration by taking the square root of the concentration of the conjugate acid of methyl amine multiplied by the K a value that we just determined. And when we square root that we get 2.36 times 10 the negative six Mohler and this is definitely with the power of 10 the negative six. Less than 5% of 50.245 So we do not need the quadratic here. Then to get Ph will simply take the negative log of 2.36 times 10 the negative six and get 5.63 for the last one. We recognize that C six h 50 is the conjugate base to the acid phenol. So we can solve for the K B of this conjugal base by taking the K A value of final 1.3 times 10 the negative 10 and divided into K W. To get our KB value of 7.69 times 10 to the negative five. Then to get our hydroxide concentration, weaken solve for it by taking the square root of the K B value we just determined, multiplied by the concentration of that conjugate base, which is 0.318 and we get a hydroxide concentration of 4.95 times 10 the negative three and you can verify this, but this ends up being less than 5% of 50.318 so we can use this hydroxide concentration and to determine the hydro knee, um, concentration by simply dividing the hydroxide concentration into K W at 1.0 times 10 the negative 14 and we get a hydro knee. Um, concentration of 2.2 times 10 to the negative. 12. Ben with this hydro knee, um concentration, weaken. Simply take the negative log of it in order to get our pH, which is 11.69

Guys doing problem? 1/20 Chapter 14 Actually the pH of each of the solutions. We'll start off with 140.1 to Moller que Anna too. So we're gonna us. So we have our base. It's goingto alien eyes and then produce hydroxide. So we're gonna have our K B value just going to be 2.5 times 10 to the negative 11th We're gonna have it equal to X squared, just a product of our BHP listener. But which minus and then we'll soon is less than 5% I ionization. So we're going to put the concentration 0.12 Bowler X X squared is gonna equal come three times 10 to the negative 12. That means X is going to be equal to 1.7 times. Tend to negative six. We can see that this is significant. Less than 5% ionization. There's gonna be a hydroxide contrition. Find a P H for this solution of of potassium. A Sorry Kono to we do 14 minus p. O. H and P. O. H is equal to negative log of hydroxide concentration, which is gonna be 1.7 times 10 to be naked of six Moeller pH for a that's going to be 8.23 All right, let's go to the next one. We're gonna use hypochlorite and the K B for the sodium hypochlorite. That's gonna be 3.4 times 10 to the negative seventh. And we're gonna start at 1.5 moller. And most, um, there's less than 5% ionization. I mean, X squared is going to be equal to 1.53 times 10 to the negative seventh. And then that's going to be three. X is going to be 3.9 times 10 toothy negative. Fourth, We see there's less than 5% ionization because, as 0.45 is going to be does is several orders of magnitude less than sorry. 0.45 Several orders of magnitude greater than 3.9 times said, and they get 1/4 for work. So we're gonna find Peach of the second solution, which is gonna be equal to 14 minus the law. Sorry. 14 minus the negative log of 3.9 times had to negative four. So P H is going to be 10.59 and next we're gonna look at point 0.40 So I'm gonna assume less than 5% ionization. That's me. 1.36 times 10 to the negative seven vehicle tracks where? So it's gonna be 3.7 times 10 to be negative. Seventh is going to be equal to X X. Sorry, not to seven to the fourth. That's gonna be Moller. And we can see this several orders of magnitude lower than 0.40 So oh, it's less than 5%. Ionization disappeared. She's going to be equal to 14 minus the negative log of hydroxide. It's a pH for for see, that's going to be 10 0.57 So that's the ph of ah.

This'll question would take from us time, but it's easy question, not difficult. So concentrate with me, please. The 1st 1 we have solved, which she is in which four. See, uh, it's concentration is open for minority, and we want to know that the edge off the solution I have to start this salt wind this solving in the water It's completely soluble. Tow N H for pasta Blast C l and negative. So the daughter concentration will be in any 24 posted in the ceiling. Leggett. Okay, it's in this in a tree for posted in the water. Maybe reacted with the water tow for So there are lucre to form is ammonia and h story and form neccesary or postive? That's me. The open boner city. Small amount of decrees to form is ammonia and four. How drone you mind? She's mean anything to foresee. N is for a city in a border. So now this equilibrium we can see it is K a dash because it's represent the image of four plants acidity, which you don't need brought on the border. Gaidar's is come from equal kw divided boys, a k a. Zesty off ammonia So it is represents a kid, a blue violet bar. Kay be off a moment, which is his means. E K. It has is equivocation this stem power negative 14 divided by its value off baby over money, which is 1.8 times part him over negative fight. So, no, these equilibrium can write it at a four way. The K either that is equal timber Negative 14 divided by 1.8 times by steamboat, were negative. Five is equal their concentration off ammonia, which is X times wiser concentration off droning, which is also X o X square, divided by the concentration off millennium remaining, which is opened one negative x the value okey damage. If we calculate ate its first month, we can neglected the extra come bearing toe open one. So that means the eggs trees represent the concentration off. The hydro in your mind is equal. The roof off 10.1 times Bar theme. Bauer Negative. Four Teal divided by 1.8 times by temp. Our negative five. Then the value off these extra represents an opportunity. We can use it to calculate the B H A directly, which is a B H is equal negative. Block the value off eggs that will be equal at final 5.1 to Susie, Zones are off the first saw. Let's go to Rose's Luck and the Soul, which is a soldier, a city so demonstrated concentration is open to one, and when the solving in water is completely suitable to formally a positive and acetate negative, so open mom completely converted to this. The problem on estate is we'd see the water. He acted as a baby's, which except a proton from the water tow convert toe aesthetic, a set and form or itchy negative in waters. That's mean so domesticated in water is basic. So no total amount off a city converted to a city, which is small. Amount off that represented by eggs. It's convert toe ascetic acid wonderful right side. So this equilibrium represent eight K B Dash, which is representing kw divided by the acidity. Constant off ascetic acid, which is a want timber or negative 14. Defined it by one point seven times by thing bore Negative five. So now we can ride a K p off the easy question, which K. B Dash, which is representing our negative 14 divided by 1.7 times by 10 over negative five is equal. The concentration off acidic, which is eggs. Times buys a prostitution off. I do. Besides, she's extra Alexis Square, dividing the ones that initial concentration, which is a 0.1 negative, ends. The value of keeping this is very small so the X can being connected numbering toe open one. That's mean eggs equal, which represents a concentration off hydroxide, is equal the route off, opening one times by theme our negative 14 Divided by one boy seven Times by Kim Bauer Negative five. So now we can calculate the B. 00 H value, which is equal negative. Log the value off these, and then the result will be used to calculate the beach, which is equal the 14 negative value off the riches that go from here. And we found it will be equal a born 87 The 3rd 1 which is so do provide sodium chloride, is come from sodium hydroxide and seal. Come from what you see, which these is stronger. These and this is a strong acid. So the full neutron so so this soul mate don't effect in the B H off water, so it make it equal seven. Thank you


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