Question
4.Using the graph of f_below; find the following limitsExistence of Limits[iLfLLfI"_[unufa=5. Find the following Iimits algebralcally: W 37' +5x - b) IlmX
4.Using the graph of f_below; find the following limits Existence of Limits [iLf LLfI"_ [unufa= 5. Find the following Iimits algebralcally: W 37' +5x - b) Ilm X
Answers
In Problems 35-38, use the graph of the function $f(x)$ to find each limit. $$ \lim _{x \rightarrow-5} f(x) $$
10 from the graph, they're off to a quick to me from the graph limit extends to two off ever X is equal before, uh, because x X approaches to implements approaches we're, ah deliverance off extents before every X is important for because when X approaches to every X 20 except Bunches war If Iraq's approaches four from here from the ground limits off extends to fire off everyone acts is different too. Whose ex winds of Fortune Why in for X approaches to?
It's gonna find the limit of the function as X approaches negative seven. So negative seven is right here. So we want to approach negative seven from the left side and you can see the left side, we're coming in at a height of two, And we want to approach the Xviii -7 from the right side, and you can see the right side is also approaching a height of two, and when these two match, you have your overall limit.
So I will find my limit off f of X. My limit off off eggs when my ex is tending to minus two. Okay, If I go to the graph, I can see that my graph actually breaks. This is minus two. It actually breaks on minus two. So the limit does not exist. I will see that my little is going to give me the value as four I keep on walking from the left hand side I'm reaching for I keep on working from the right hand side I am reaching do. And since four is not equal toe in this case, my electoral is not equal to my art shell. In this case, limit extending toe minus two minus is turning out to be actually four and limit extending to minus to plus is turning out to be too. Since these two are not equal, I will say that this limit does not exist and we can also see directly from the graph. The graph is actually breaking on minus two so the limit does not exist
Limit off F off X when my exist ending to minus five. When my exist ending to minus phi. Let us go to the graph over here. This graph is actually going below as well. This is a continuous graph which goes below also. So this is not cutting here now. This is minus five minus one minus two minus minus one minus five years. This point is minus five. This is a continuous craft, and I can see that on minus five. My values zero. So my Ellis and my my little and my rsl will be equal to zero. So in this case, I can say this limit exists and is equal to zero, and this is my answer.