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With R = 0.06 m Add a screen shot of the Logger Pro plotMagnetic Field from a Wire Lab2dFieldLabQuestRaLadCH 1 Magnetic Field 21.14pTLounor !Ztitcl;Distances (cm)e...

Question

With R = 0.06 m Add a screen shot of the Logger Pro plotMagnetic Field from a Wire Lab2dFieldLabQuestRaLadCH 1 Magnetic Field 21.14pTLounor !Ztitcl;Distances (cm)eCONNECTED SCIENCE SYSTEM Field StrengthLocation of Field SensorDirection (Conventional Current)CurrentChange t0 Electron Flow6.3 AI(A)1.52.83.44.45.66.37.1B (pT)0.004.889.2211.1814.6218.6421.1423.63

With R = 0.06 m Add a screen shot of the Logger Pro plot Magnetic Field from a Wire Lab 2d Field LabQuest RaLad CH 1 Magnetic Field 21.14pT Lounor ! Ztitcl; Distances (cm) e CONNECTED SCIENCE SYSTEM Field Strength Location of Field Sensor Direction (Conventional Current) Current Change t0 Electron Flow 6.3 A I(A) 1.5 2.8 3.4 4.4 5.6 6.3 7.1 B (pT) 0.00 4.88 9.22 11.18 14.62 18.64 21.14 23.63



Answers

Apply the Ampère-Maxwell law to one of the circular paths in Fig. 22.3 to find the magnitude of the magnetic field at the locations specified.Find $B$ outside the wire at a distance $r \geq R$ from the central axis. [Hint: The electric field inside the wire is constant, so there is no changing electric flux.]

And why that max up that solenoid is wrapped around solid silicone steel. So here is the solid to the constant When we just use a different color is wrapped around here in a park area for us to find them male dick field inside this whole load due to the current and Mantis Ishan in total maintain fields, we can find it by considering a long, so annoyed and off 60 terms. Ah, buddy. Unique. Uh, centimeter. And it carries a current off I that is there a 0.15 on pier. We'll let you permeability off a core. His silken still is Can is 5 to 00 The Manti feel inside this alloy, as usual, is given by being or is it called me more end times. I we know what will be then. You know, Lord Capital And if I know total number off terms divided Lent I, um we substitute the given values and find it Be not, We know four by times 10 to the power line. The seven times 60 divided by that important general one times and their report 15 years. These gives us be not to be 1.13 times 10 to the power minus three Tesla. The Total Man tick field daughter Romantic field bees given by km times B nard This means of 5 to 00 times 1.13 times 10 to the power minus three Tesla. And this gives us five 5.88 Tesla, the man's physician, is given by, um be physical to be nod plus me, Lord m from here solving for em and substituting for a B. We know he's okay and guns b nard physical to being odd. Plus, um, you him over romanticization then will be km minus one times b nard divided by you know our next step is to substitute the values and find Americanization. M will be 5199 divided by four pi times 10 to the power minus seven is a constant. That was 1.13 dime stepped on minus three. This gives us 4.68 times 10 to the power six hands. Part meter is over Manta physician, but be off the problem. Since the silicon still is para mentee, they're ah magnetic according to the equation the direction off the total magnetic field is in the same direction off the magic field due to the solenoid Onley and in the same direction off the main position. Uh, which we can see from this figure. Let's say this is assault. Annoyed cross means they current is going in and dark is current coming out here? This is for me, Lloyd. We have a direction off. Aby is being Audis here, and Americanization will be this and our total be will be here, which is be dish Come.

This problem covers the concept of the magnetic field produced by a long wire and that is given by the equation because may not I upon to buy our her minute is the positivity constant and r is the distance from the wire. Now let's substitute the values. Uh the magnetic field is Communities four by and two tenders -7 uh Tesla meters for MPO and magnitude of the current is 1.38 MPO upon to buy. And the distance from the wire is 0.255 m. So the strength of magnetic field comes out to be 1.08 into Tenders -6 Dessler. Therefore the strength of magnetic field at a distance of 0.255 m from a while carrying 1.38 MPO current is 1.8 into it. And this minus six Tesla.

Um if induced equals V times be because they're perpendicular to each other. Velocity is 16 meters per second and magnetic field use 0.3 Tesla, so that will come out to be 4.8 world. Now the potential difference will come out to be E times d and that with equals I got in times resistance. So carried will come out to be e d. Over our so 4.8 world times. The wire is 0.75 meter long, so that's 3/4 meter divided by resistance. 11 home that will come out to be 3.6 divided by 11 ampere, which is 0.327 or 0.33 ampere.

High in the given problem. There are a loop, There is a loop in the form of the combination. Well, two arbs like this. These arcs are making an angle off 1 20 degree at the center. The smaller arc is having a radius, smaller is equal to 20 Centimeter and uh bigger arc is having a radius. Capital art is equal to 30 centimetre. The current carried by these two arcs, the same current will be carried by them. Whether these are the arcs or the street segments, so the same current will be passing through them, whose magnitude is given as 12.0 mp. Here. Now we have to find the net magnetic field here at the center of these two ox for which we will use a concept that as we know magnetic field at the center of a circular coil, it's given as B is equal to new, not I by tour. And that circle. If we consider this to be the circle. The total angle made by the circumference at the center will be two point. So the magnetic field due to the complete angle means to buy angle is do not I by two are. So. If you consider an arc, a smaller arc making an angle theater at the centre, then using unitary methods, the expression for magnetic field at the center. Do you do? Arc will be given by P. Is equal to theater by to buy or we can say this is 3 60 degree into the normal magnetic will means mu not I buy to our. And then this expression will be used in order to find the magnetic field due to the two are shaped portions. But in order to find the magnetic field due to these straight lines, we will use the concept. We will use Barton several slot which says a magnetic will do to the small current carrying element ideal at a point B whose position veterans making an angle theta. That magnetic will smaller magnetic is given by You're not by four by into ideal sine theta by our square. So if that point he comes here exactly along the length of this conductor angle, theta will come out to be zero. Means in that case the magnetic field will be zero. Hence we conclude the magnetic field at the center. See due to these two straight segments will be zero. So magnetic field magnetic fields at the center due to stripped Segments will be zero. So the net magnetic will is only because of these two are shaped portions. Now, when more concept here we will use as in this smaller arc, the current is in a clockwise direction. So this phase of the smaller coil will behave like south pole is the direction of magnetic field is into the plane of paper. And due to this bigger arc the magnetic field will be outward and as we know, the magnetosphere will be stronger due to this shorter portion, the smaller rock. So the magnetic field which is into the plane of paper that will be having larger magnitude. Hence the net magnetic field will be given by Tita by 360 into mu. Not I by two are smaller minus theta by 3 60 degree into um you know, try again, Divided by two capital are For theatre, this is 120° Divided by 3 60°.. Um you note by two and I all the things can be taken As a common out, leaving behind one by AR -1 by capital are in the Bracket. No plugging in all other known values. First of all, this is one by three into form, you know, this is four pipes Into 10 for -7, divided by two into for current, this is 12 MP er one by Our means 20 cm means 28 to 10, 8 for minus two m minus one by 30 centimetre, or 30 into 10 for -2 m. So here it is two times here it is four times. So finally this is Eight pi into 10 days for -7 and taking the standard for -2. Also in the denominator is comin out, LCM for 20 and 30 will be 60, so this is 3 -2 and that is Tesla. So finally this magnet, if it is eight in to tend bar -5 into one by 60 what we can see, This is 1.3 into 10 H 4 -6 Tesla. So finally we can say this is 1.3 Micro Tesla, and the direction is into the plane of paper, which becomes the answer for the given problem. Thank you.


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