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The following mechanism has been proposed for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution_(1) Ht+ HzOz = = HzOt-OH (rapid equilibriu...

Question

The following mechanism has been proposed for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution_(1) Ht+ HzOz = = HzOt-OH (rapid equilibrium) (2) HzOt-OH + Br HOBr + HzO (slow)(3) HOBr + Ht + Br" 7 Brz +HzO (fast)(a) Which one is the rate determining step?(b) What is the overall reaction equation for this process?(c) Write the rate law which is consistent with the mechanism:(d) What are the intermediates?(e) Draw a rough energy diagram for this mechanism: Assuming t

The following mechanism has been proposed for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution_ (1) Ht+ HzOz = = HzOt-OH (rapid equilibrium) (2) HzOt-OH + Br HOBr + HzO (slow) (3) HOBr + Ht + Br" 7 Brz +HzO (fast) (a) Which one is the rate determining step? (b) What is the overall reaction equation for this process? (c) Write the rate law which is consistent with the mechanism: (d) What are the intermediates? (e) Draw a rough energy diagram for this mechanism: Assuming the over-all reaction is exothermic



Answers

The following mechanism has been suggested for the gas phase oxidation of hydrogen bromide \[ \begin{array}{c} \mathrm{HBr}+\mathrm{O}_{2} \rightarrow \mathrm{HOOBr} \\ \mathrm{HOOBr}+\mathrm{HBr} \rightarrow 2 \mathrm{HOBr} \\ \mathrm{HOBr}+\mathrm{HBr} \rightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{Br}_{2} \end{array} \] No HOBr is found in the final products. Experimentally, the overall reaction is found to be first order in $\mathrm{HBr}$ and in $\mathrm{O}_{2}$ (Section $9.6)$ (a) Write a balanced stoichiometric equation for the reaction. (b) Show that the above mechanism is consistent with the observed orders of reaction. (c) Which step is likely to be the rate-determining step?

This question is very easy, cause considering that you're already given the equation so you have to do to find an therapy is ah, use the standard form. Ah, look up a standard and appease a formation. So for B R two, which is a guest, you have won one 1.9 killer Jules per mole point. I don't know what a nine didn't write down. Since there's two moles, you're gonna multiply that by two. We're gonna get 2 to 3.8 killer jewels for H 20 You have negative two for 1.8 times to, which is negative for 83.6. So the standard in therapies of, um 02 then is zero because it's in its simplest on mental form, HBR. That is going to be negative 36.3 times four, which is each with a negative 1 45.2 And then when you, um, do the subtraction of the products minus the reactors, you end up getting negative for 83.6 plus 2 to 3.6 minus 1 45.2 plus zero. Um, and then you do a simple plug in charge and you get your final answer in college joules per mole for this final equation.

Problem. Party. This is a this is the energy profile for the bromide catalyzed decomposition of hydrogen peroxide and on Y axis this is energy on the X axis reaction. Yeah. Part we. Mhm. Okay. No, in part A we need to calculate activation energy for reaction 14.30 and 14.3 in this car. So this is the activation energy. Yeah its value is 14 point 30 And this is the activist. And as if E. A. To its value is 14 point 31 This activation and energy for E. For cargo. This actor is energy for for equation Our reaction given in 14 30. And this act this is activation energy for reaction given in 14 point three U. So this is the answer for party. Yeah. Now in part B. The fact that they are too build up during reaction ellis was that the appearance up trends of we are too That is reacting 14.30 is faster then the disappearance of friends. We are too distant reaction. 14.31. This is is the reason reason that E. A. Of re accent 14.31 in the energy profile, mhm. Profile of hobbies profile of who is larger than certain you of Reacts and 14 30 This is explanation and and support hard to be.

First point you have to draw the diagram. Let's make it like this. You have energy one day reaction, please. Right? So first stuff you would have like this and then it would increase spending something like this. Okay, so the stock from flowers Energy is 14.3 And this is for a new one. 31. Okay, So 14 lb 30 is yeah. Or reaction taking on keys, doodle. You can find 3 1. Is it going to activation energy before the chance is going through what the box? The fact that we are too. These are giving the reaction. Oh, there's a stack of the ardennes. All we are too. Which is 14.30 is faster done disappearance what we are doing you just from Yeah, Situation 14.31. This is the reason got you All 14. Going to be one in the energy. What? Fire above? Yeah, is larger then. E off For being 130.

In this problem we have given reaction mechanism Which occurs in two steps and we have to write overall reaction and identify catalyst and reaction intermediate. Mhm mm. Given mechanism is any step one. It's too, or to react with br minus to give. We are all minus and H two and second step mhm Mhm is to go to reacts with BRO- which is formed in step one to give, we are minus plus H two and or two. Here we can observe that The BRO- formed in step one is consumed in step two and that br minus iron consumed. Any step fun is regenerated in step two so first of all, to find overall reaction ID these to step and eliminate the species which occur both side of reaction, most of it on adding we get It's true or two plus br minus Plus H202 plus beer for minus. Yes, we are all minus plus H two. That's bigger minus less age too. And also here we find we are minus and we are all minus president in both sides of the essence will be eliminated. It. I don't know. No, but the most of the time overall Mhm reaction for the given mechanism is two moles of H two or two gift, two moles of H. Tool and one more love auto. Just drop the physics of this is our answer. Four overall reaction. Okay, publicly. Mhm. Now we have to identify catalyst and the accent intermediate as we know that. Mhm. Mhm. A catalyst. This is just is a substance christmas christmas that is paid up a chemical reaction. Yeah. Mhm. What? Mhm. Without consumed? It's just Mhm. Buy it. Mhm Yeah. The catalyst is used up in one step and it. Mhm. To regenerate in Okay, subsequent step. Mhm. Our next step here we are minus iron Is consumed any step one And it regenerates in step two. Therefore. Yeah. Mhm. Mhm BR minus is yes. Mhm. Acting as catalyst. Mhm. Okay. Yeah. Look, look. Yeah. Yeah. Yeah, reaction entered immediate mediates our is pieces produced. Mhm. In one step. Mhm. But used up in next step. Mhm. Yeah. That boy here we are all minus Is produced any step one and it is used up in step two. Therefore, yes, there are reaction intermediates. Mhm. The excellent immediate in this. The accent. Mhm. What? And the the excellent immediate is B R O minus. This is our answer for reaction intermediate. Mhm. Mhm.


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