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Question

-bulanol yiclds ~hromohulancpicecnccconcenmnaco cuIunC acid [email protected]$ of sodium bromideCH,CH;CH,CHzOH (W) CH, CH,CH,CH,Br (I) of I-bromobutane; the percentage yicld of the product equub: If15.89 mL of | hulanio produced 12.23 hulantol Ptnol; ard thc molar mass of [-bromobutanc 137 gmoll ) ~butanol 0,81 @ml _ mr Iu7in95 (Assume the density of

-bulanol yiclds ~hromohulanc picecncc concenmnaco cuIunC acid end @xCEt$ of sodium bromide CH,CH;CH,CHzOH (W) CH, CH,CH,CH,Br (I) of I-bromobutane; the percentage yicld of the product equub: If15.89 mL of | hulanio produced 12.23 hulantol Ptnol; ard thc molar mass of [-bromobutanc 137 gmoll ) ~butanol 0,81 @ml _ mr Iu7in95 (Assume the density of



Answers

What mass of cesium bromide must be added to $0.500 \mathrm{~L}$ of water $(d=1.00 \mathrm{~g} / \mathrm{mL})$ to produce a $0.400 \mathrm{~m}$ solution? What are the mole fraction and the mass percent of $\mathrm{CsBr} ?$

In this problem, number of moles of alcohol, number of more itself, alcohol is equal to five point to buy 104, which is equal to one x 20. Now, the number of more salt ch food produced is equal to 3.36, bye 22.4 later, Which is equal to three by 20 so number of or as a group presents is equal to city. So according to the option, today will be the and said.

In this question. You know that density is equals to mass over volume, and then, you know, number off mole is equals to mass over molar mass, right? And also, you know that the idea guest, Lois PV, equals two and r t. So from the question of the only information you know as the Kreisher, which is 733 and did temperature, which is 46 degrees Celsius. So you don't have any mass involved. So you have to You DeVivo there's this formula, whoever's back to p and t So you need to change this formula. Well, p and t So we start from here, so PV equals nrt so and can be changed too mass over morning mass so PV can be right into mass over Mona mass times are nt. Okay, So with we bring the am to the rice, I read to the laughs I So you will have something like mass over volume Times are tee and this size pressure times molar mass. Okay, as you see there is is actually density. So we want we want to isolate that. So we further bring this to the next site. So you will have P. Times Morning mass Divided by tamp Uh, constant and temperature you closed to And mass divided by volume, which is density. Sudan City is actually equals today's. So now you can do the calculation, right? You have to pressure the molar mass. The molar mass off HBR IHS Wong plus 79 one night. So which is anti tonight? Roughly. Yeah. Any point night. So you have Mowlam as you have pressures, you have temperature. Now you can just pluck it back to the equation and then fine density eso. After you put everything back into the equation, you should get 3.0.

So now we're going to work on Problem 72 from chapter 13 in this problem. Whereas three questions, Um, we want to prepare a solution of caesium bromide, which is Ah, zero point for morality. And we have a volume of 0.5 leaders to work with of water. So we needed first know what mask of caesium bromide ad. And then we want to know also the mole fraction and mass percent of this solution. So, first for morality, we need to calculate massive assault. So we're told that we have 0.5 leaders, so let's go ahead and see how much a mass that would be. So our density is given in milliliters, so we convert to milliliters, then we multiply by our density. And then finally we convert kilograms because that's what we need for morality. And then we see, perhaps unsurprisingly, to some of you that we have 0.500 kilograms of war. So if the density is one, than the number of leaders will equal the number of kilograms. But it's always best to make sure if you're not completely positive about the conversion. Um, so we're given the concentration that we want to have a 0.400 moral ality. CCM bride. That's what we want. And so this morality here is gonna be equal to the moles of caesium bromide divided by this mass we just calculated. So if we multiply both sides by 0.5, then we can calculate the molds of caesium bromide as being zero 0.200 moles. So the first question is, what's the Mass? So to find mass, all we need to do is multiply by the molar mass, which is 212.84 caesium reminded, and so that gives us the value of 42.6 grams. So this is the mass that we need to add to our 0.5 leaders to make this ah, solution. So that's the first answer. Second, we're asked, what is mole fraction? What is the mole fraction of the solution and then mass percent. So we know moles of caesium bromide already. We just need to calculate moles of water. So we have, um, kilograms as 0.500 for water. So we need to convert to grams and then multiply by the molar Mass. Excuse me. Divide by the molar mass to get the number of moles, which is 27.75 months. So to calculate more fraction, we just need to put the moles of caesium bromide over the whole. So we have 0.200 moles provided by 0.200 plus 27.75 models. And so when we do this calculation, we get a value of 7.1 six times 10 to the negative three unit list, of course, because of cancellation of the mole unit. So the last question is percentage of CCM bride specifically, uh, mass percent. So we calculated 42.56 grams as the amount of caesium bromide that we need. So we want to put that over the entire mass 42.56 grams, plus be 500 grams of water, which we get from the the 0.5 kilograms, and then we're calculating a percentage value. So we want to make sure we multiply by 100 and that gives a value of 7.84 percent.

We have density equals mass over volume on masses half off mass of the sodium atom plus mass of clothing. Adam divided by the volume which is eat radius Cube on putting those numbers in, you find a density to be 2.17 times. Get to that three, kiddo, Grandpa.


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