5

Sapse htthdutt) Hlth , uhex [u; y)exy" . 6d xlt) ylt) We _cleetiable tudions 4l7? (b=l xla2 Ju) =S1 ol J 'U) = S> Fing @)A 2 B1 C6D8E lo _...

Question

Sapse htthdutt) Hlth , uhex [u; y)exy" . 6d xlt) ylt) We _cleetiable tudions 4l7? (b=l xla2 Ju) =S1 ol J 'U) = S> Fing @)A 2 B1 C6D8E lo _

Sapse htthdutt) Hlth , uhex [u; y)exy" . 6d xlt) ylt) We _cleetiable tudions 4l7? (b=l xla2 Ju) =S1 ol J 'U) = S> Fing @) A 2 B1 C6 D8 E lo _



Answers

I Icre, ycllow procipirare (S) is of (a) $\mathrm{PbCrO}_{4}$ (b) $\mathrm{PbCO}_{3}$ (c) $\mathrm{PbCl}_{2}$ (d) $\mathrm{Fc}(\mathrm{OII})_{3}$

In this question. We are provided with three vectors and that is we have the rays minus two. I Well that's true. A J letter B is the way minus treaty. And we will see is minus five days. And we have to find certain quantities among which first one of his two a minus four B. So you can see that we have to make twice of factor A. And minus four times of vector B. Okay so you can see here twice off factory that is having components minus two and three and minus four times of vector B. That is two minus three. Now we have to make a scalar multiplication here. So I should get here then minus of four and six. And then we can see here we want to fly by four. So we get here eight and minus tool. No we have to subtract these workers. So when I'm going to subtract minus four and eight I got here minus 12 and six plus 12. That is 18. Okay, so I can write these factories minus 12. I and a plus of 18 G. This is the answer for the first one. Now I move on the second one. Second one is we have to find the dot product coffee and be that is the product of minus two comma three with to call my my necessary. Okay, so I have to multiply the components means minus two with the two and three with minus three. After multiplying it I get minus 13. This is the answer for the second part. Now I move on on the third part. In the third part we have to find the value of the adult B plus C. So is minus two. Bomber three and or product with some of BNC. So I'm going to hurt BNC. These two comma three and bless C C is zero comma minus five. Okay, now, first of all we have go ahead because we have to solve the records. So after adding this we get here to coma minus sorry that is minus three. Okay minus three minus five. That is minus eight. Now I have to make the the scalar product or that product. So I have to multiply the components minus two with the two and three with minus eight. After multiplying them, I got minus 28. So this is the answer for the third part. Now I'm going to move on the fourth part. In the fourth part we have to find the value of minus to a plus three B. And with Lord product five C. So I have to make minus two times of A that is minus two per battery and plus three times of B B is google my ministry and this has to be made with your product with five times of C. That is five times of zero Bama minus five. Okay, now see what we got here. Yeah. So first of all, we have to make the addition here. After reading these vectors, I should get here. 10 coma minus 15 and then don't put up with the five times of the second vector. That is zero comma minus 15. Okay, you can see after making the dot product, I got 10 multiplied by zero and minus 15, multiplied by minus 15. That is it was too. You can see here sorry, minus 25 was there? Okay, because five 9 to 5. 10,000 to 25. So we should have your 25 and after multiplying them together. 3 75. So this is the answer for the fourth part. Now I move on the fifth part. In the fifth part. If they stole that, we have to find the magnitude of and multiplied by Salvador. Okay, so magnitude or we should be square root of minus two squared plus three square. And see it all they see is the local minus five and dot product with a h minus two geometry. So we can see this magnitude transport into square on top 13 and we have to make the dot product here. When making your product, I got here zero and minus of 15 And after multiplying them, I got minus 15 square root 3 13. This is the answer for the fifth part. Now I move on the sixth part. In the sixth part we have to find the value of build or b minus more or less of the new Darby means so common minus three. Dot productivity. Tacoma minus three and minus magnitude of B means square. Autopsy to square and minus three square. Now this turns are going to do, going to two and minus three into minus three and minus offs were brought up 13. Okay, this provides me 13 minus were route 13. So this is the answer for the sixth part, so you can see that. I have found it. Answer for all the part, answer for the Earth part was first part was minus 12 Y plus 18. J answer for the second part was minus 13. Answered for the third part was minus 28 answered for the fourth part was 3 75. Answer for the fixed part was minus 15 square or 13 and answer for the sixth part was 13 minus square 13. Okay, these are all the answers of this question. Thank you.

So in this question, were given vectors you the interview and were asked to do certain operations. So we'll be doing is question one by one. The first question we were asked to find the length of director You place feed. First of all, we need to find what is you place we and then we'll have to find the magnitude of the length of that vector. So when I am minus three, shapeless to case you the is I pledge city When adding those two victors, we'll be getting it as to I minus two j plus Tookie. So the magnitude is the Squire off the route off the square of the oceans so well before place for bless Forward left the summit. So we'll be getting Route 12. So by simply hang really be getting it as to route three. So this is the first answer. So moving on to the next question in the next question, you're asked to find the some off the magnitudes or the length of directors U and V. That is normal view plus normal week. So we know toe find the norm of the magnitude of any vector is the Squire of route off the Squires of the sun off their corresponding corruption. So one square plus minus three squared plus two square is the magnitude root. It'll be the magnitude of you. And before we it will be ruder one squared plus one square. Starting all these things will be getting Route 14 39 food plus one X p 14 plus two. So taking root to outside would be simplifying it to the form a road to in the road seven plus one. So that's the second answer, which is a simplified form coming on to the next question. So let me raise the A part so we can write it here. So the next question is pretty, pretty much seen as B. You'll understand it. So it would be see is actually my length, or of the magnitude of minus two times you plus two times magnitude of the length of week. So just remember this the magnitude off any vector K obvious models off K into magnitude of factor V. She'll be using this property here so that we can he pretty much easily do this problem so it will be magnitude or models of minus two in tow magnitude of U plus two times magnitude of week. So models of minus two is nothing but to, and we'll be taking to common from both these things. So we'll be getting modelers off magnitude off you, plus magnitude of we. We already know the some off length of magnitude off you. Plus we, because we have calculated didn't be it will be just equating that we'll be getting the answer pretty much easily. So with the answer for this is the route to into seven Route seven plus one. So the final answer would be to root two into Route seven plus one. So that's the answer for option. The sub question. See, moving on. Let me erase option. The question be so the next question is de in here were given the conditions. It's that three U minus five. Replace W on. We have to find the length off that particular vector. So we have to do these operations, which is three U minus five plus w. And then we have to find the model is or the length of that particular vector. So three you is three times I'm sorry. It is three times I minus three g close to key, minus five times I plus d Bless Toe I plus two J minus walking. So that would be three and five, minus 90 plus 60 minus five I minus five G plus two I plus two G minus 40. So it's two g. So I those two j minus four. So we'll have to do simplify this thing So we know three eyes here, minus five is here to eyes, ears. So three plus 25 I minus five ever be zero I So the I common and gets canceled out. So minus nine is dead minus nine. G minus. Vijay would give us 14 g plus. Tuesday would give us minus two allergy, so it will be minus 12 G plus six K minus. Focal give us two K. So the magnitude off minus 12 plus two K would be route off 12 Squire minus 12 square plus two square. That would be 1 44 plus four that would give us Route 1 48. And Route 1 48 is nothing but four into 37. So would be getting it as two or 37. Sorry, that would be two times Route 37. There's a final answer for option D simplified and find lands of options. So let me raise all these things so that we can move onto Option E. Okay, so the option e yes, one by model s off W in two w. So when we look at this, this is actually a unit vector in the direction off. W we know if we divide director by its model s or the length would get a unit vector in the direction of that particular vector. So they're actually trying to find the unit director in the direction of public. So here we know the bluest y plus to the minus four. Okay, so do I. Plus Tuesday minus four k. We have to divide it by the model is of the length of the EC terribly, which is actually to Squire plus two square minus four square on the route off that practical value. But be getting it has to I plus two j minus four k divided by Rudolf 16 plus forward plus four. That would be four plus four plus 16 which would be Route 24 which can be written us. I told to Route six. So? So I buy to Route six. That's two G Buy two Road six minus for Sorry, that's actually to load six. Let me raise it so it can be written last two g buy 26 minus four K by two Road six So we can canceled that divided by two properly. So we'll be getting I've I wrote six plus Jay by Route six, minus two by two by six. This would be the answer for this particular option. So we're going toe the last support off this question, which is F it is. We were asked to find the magnitude off Option E, which is one by models off the in tow Masari models of W into W. So we already know the the option E is a unit director, so the magnitude off Amy unit director would be one. So we pretty much know that particular condition the magnitude of the unit director is always one. So this answer it straight, or we can evaluate or check this particular condition. Bye. One by road six. The whole square less one by road six the whole square plus minus 206 The whole square and the root off. This complete thing should give us one because 106 106 and minus 206 Other corruption off the unit director. So we're just trying to find the magnitude off the unit director, which will always get it as one because let's find it out. One plus one plus 11 plus one plus food by Road six would give B six by six what is one. So in both manner, we got the same answer, which is one. So that's the final answer. I just want

In this problem, I can write the reaction and just look at it carefully. After reading the comprehension, I conclude that the reaction happen. It's something like this. B. B and no. Three or two plus two K. I will react to give the productive The VI, two, B B. I do. This is compound C. And this is yellow PPT blood, you KN or three. Therefore, according to the option of some B, each correct answer option B. H. Correct answer for this problem.

In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.


Similar Solved Questions

5 answers
Given that &, B and rare the roots of the equation 2x' _x? + [ = 0. determine the equationwhose roots areandNote: (aB) + (ay)' + (Bw)' (ay Ba ya)' _ 2 afxa + B+Y) (u + B+y) _ Z(a8 + ay + By)
Given that &, B and rare the roots of the equation 2x' _x? + [ = 0. determine the equation whose roots are and Note: (aB) + (ay)' + (Bw)' (ay Ba ya)' _ 2 afxa + B+Y) (u + B+y) _ Z(a8 + ay + By)...
5 answers
(12 points, points each) U-mx+b of the line passing through the point (3, Witn Find the equation slope of 2
(12 points, points each) U-mx+b of the line passing through the point (3, Witn Find the equation slope of 2...
5 answers
Orztmic Sycthssis ch;Ci-C-&-cc-(-(cl 84,
Orztmic Sycthssis ch; Ci-C-&-cc-(-(cl 84,...
5 answers
For any integer $a$, show that $a^{2}-a+7$ ends in one of the digits 3,7, or 9 .
For any integer $a$, show that $a^{2}-a+7$ ends in one of the digits 3,7, or 9 ....
5 answers
Find the area under the graph of y cos? (3r) sin(3r) between I = 0 andI = "/3.Drag and drop your iilles or click t0 browse.
Find the area under the graph of y cos? (3r) sin(3r) between I = 0 andI = "/3. Drag and drop your iilles or click t0 browse....
5 answers
Show that if M is the midpoint of the line segment with endpoints (X1 Ya)(x2 Y2) then d(P M) + d(M,Q) =d(P Q) and d(P M)=d(MQ)To prove d(P M) + d(M,Q)=d(P Q}), first find the d(P Q). Suppose that = '(K1 Y1) &nd (*2 Y2) are two pointscoordinate plane , delermine d(P Q) using the distance formula Choose the correct ansiver below:d(P,Q) = { (*1-Y1)? (K2 - Y2)d(P Q) = 4 (*2 -*)r+ (Y2 -Y)rd(P,Q) = { (*1 -Y2)? - (*2 -
Show that if M is the midpoint of the line segment with endpoints (X1 Ya) (x2 Y2) then d(P M) + d(M,Q) =d(P Q) and d(P M)=d(MQ) To prove d(P M) + d(M,Q)=d(P Q}), first find the d(P Q). Suppose that = '(K1 Y1) &nd (*2 Y2) are two points coordinate plane , delermine d(P Q) using the distance...
5 answers
Question 8: Changing order of integrationProctorChoose the correct change of order of integration of the following integral:{ve_ dx dyJ"" K ve" dy dx[' K" ve" dydak K" ve" dydzK" K" ve" dyda
Question 8: Changing order of integration Proctor Choose the correct change of order of integration of the following integral: {ve_ dx dy J"" K ve" dy dx [' K" ve" dyda k K" ve" dydz K" K" ve" dyda...
1 answers
An $R C$ circuit containing a resistor with $R=2500 \Omega$ and a capacitor with $C=1500 \mu \mathrm{F}$ is attached to an AC generator with $V_{\max }=3.5 \mathrm{V}$ and $f=25 \mathrm{kHz}$ a. What is the impedance of this circuit? b. What is the amplitude of the current?
An $R C$ circuit containing a resistor with $R=2500 \Omega$ and a capacitor with $C=1500 \mu \mathrm{F}$ is attached to an AC generator with $V_{\max }=3.5 \mathrm{V}$ and $f=25 \mathrm{kHz}$ a. What is the impedance of this circuit? b. What is the amplitude of the current?...
5 answers
Ina + Inb = In(a + 6) true or" false (cirele one)9 Ina Inb = In(a 6) Lrule 01" [alse (cirel one)_
Ina + Inb = In(a + 6) true or" false (cirele one) 9 Ina Inb = In(a 6) Lrule 01" [alse (cirel one)_...
5 answers
Considering the voltage equation e=740sin(wt+80degrees), what is the magnitude of the rms voltage?
Considering the voltage equation e=740sin(wt+80degrees), what is the magnitude of the rms voltage?...
5 answers
Peracetic acid has an extra oxygen atom compared to acetic acid. There is a 3.4 pKa unit difference between the two acids. What may account for the higher pKa value for peracetic acid?peracetic acid pKa 8.2acetic acid pKa 4.8OHH;cH3COH
Peracetic acid has an extra oxygen atom compared to acetic acid. There is a 3.4 pKa unit difference between the two acids. What may account for the higher pKa value for peracetic acid? peracetic acid pKa 8.2 acetic acid pKa 4.8 OH H;c H3C OH...
5 answers
Provid Reagent;Follawing Trnclorm 0iiaNHCHACeninaut Lic: (ullou nE [4o suuctun] isunlcts: 42 pomIscach panaWmich of thee TWO moleculcs MORE BASIC' Which of thc LWO mnolcules MOR STARLE? Wrhan hybridizution ofthe nitrogen LONE PAIR in A? Whanieth hybridizatiau of he nitrogen LONE PAIR in B?Rank the reactivity Ofthe following toward substitution. with being mOsurcacuvcpoints}OCHj"NCHjlz
Provid Reagent; Follawing Trnclorm 0iia NHCHA Ceninaut Lic: (ullou nE [4o suuctun] isunlcts: 42 pomIs cach pana Wmich of thee TWO moleculcs MORE BASIC' Which of thc LWO mnolcules MOR STARLE? Wrhan hybridizution ofthe nitrogen LONE PAIR in A? Whanieth hybridizatiau of he nitrogen LONE PAIR in B...
5 answers
The general solution of v +2* # d 1 14r 1 =0 isNone ofitheseolly = (Cli+ Czr + C322) eOi ly = Cer + Cze25loly FE Cl-l(cz + Cx) e
The general solution of v +2* # d 1 14r 1 =0 is None ofithese olly = (Cli+ Czr + C322) e Oi ly = Cer + Cze25 loly FE Cl-l(cz + Cx) e...
5 answers
0 with 6(C3S5U4Q3) Find the coordinate vector [U]B of u7 2 3 respect to basis B = D1 = 02 03 1 0 1 3 56-1342 :10 0 -13 3 :104 :6
0 with 6 (C3S5U4Q3) Find the coordinate vector [U]B of u 7 2 3 respect to basis B = D1 = 02 03 1 0 1 3 5 6 -13 4 2 : 10 0 -13 3 : 10 4 : 6...
5 answers
(6 points) Use part 1 of tbe Flundamental Theorem of Calculus to fnd 9 (2):g(2) =8in %? &
(6 points) Use part 1 of tbe Flundamental Theorem of Calculus to fnd 9 (2): g(2) = 8in %? &...
5 answers
Give the fina product when acetophenone undergoes the following sequence of reactions (2 points)CH;NHCH_CH; NaBH CN3.H,OGive the IUPAC name the following molecule. (2 points)
Give the fina product when acetophenone undergoes the following sequence of reactions (2 points) CH;NHCH_CH; NaBH CN 3.H,O Give the IUPAC name the following molecule. (2 points)...

-- 0.034181--