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Li 1 [tin(* + 9 = 1 5 4]-D30'88...

Question

Li 1 [tin(* + 9 = 1 5 4]-D30'88

Li 1 [tin(* + 9 = 1 5 4]-D 30 '88



Answers

$$ \text {} 8 \frac{9}{10}+1 \frac{1}{5} $$

So you have that the following sequence. A one minus 1/3. One more night by this one with seven one word 81. So when I keep a general for that for the and, um with secrets so well, cervical, these want one. So what is that? Is a bit So what? We can call the zone a one. That one too. But once we no before. So as you can see one, huh? The future of these sequences old alternating because 50 17 was it the negative? Was it? Nobody wants to take things. One was the negative. So perhaps some miners one three engine builder on if you want to start at one. So we sent out one that he was my swan didn't. Why, Miss One can put another rightness there. So? So that for one is positive. And, uh, if you look at the thing in the denominator, there's not anything I do not know Terminator. So probably just something related. Also, hear the zone is three square. I'm on this. Oh, this is a mystery square that these three streak you. That's three to the fourth grade, so you can see that sequence. Well part of you have there One. When this one, the oh won over three squared one of those one Q one or before. So the whole the world would be a very strange place because the sequence can be read in us. What was that? But, uh, if you look in there like this when we have nothing so robbery onto so it's trucked. I want from you so that anyone you see people too. Um, 221 So you can have that description. Or we could give the grieve all that's on formula. You could describe Bill's away. Uh, because the relation oh, so records. He's, uh thank you. They so with some number, start with these and then we say, What is there well, for getting into the next number. Also, as you can see here as you increase the end, you're more decline by my nose. Warren Third. So my nose 1/3 time's a so Ben you just the next time, right? Because you said we'd want well to get minus 1/3. Just moved it by 1/3 to get one of her. Nine will multiply, buddy. Aw, 30 miles. 1:30 a.m. So it was You gonna come? Here's the records. Relation is, well, the previous them a hands. So bam plus one is a little A's event. Times miners 1/3. So you have those descriptions are not, Yes, so would be decreasing alternating.

Health insurance in this problem. We have to find some of this sequence and we can observe that this is an ap because the difference here is constant. The difference of 1st and 2nd time is four. The difference of 2nd and 3rd is also for so the difference of terms difference of two consecutive terms is constant and it is an ap. Now we know that if I calculate any system of this ap using the formula A Plus and -1 times b. So this is coming out to be one plus n minus one times the common difference which is four, so one plus four and minus four and this is four and minus three which is the last time. So the number of times here would be and and we have to find the sum of first in terms here. So let me use the formula for the sum of first in terms of a P which is and upon to in the bracket two times the first term, plus the number of times -1 times that common difference. So this is an upon to two Plus 4 and -4. This is an upon to four and -2, and this is an Times two and -11 and which is the third option. So third option would be the correct answer to this problem. Thank you.

This question gives us a sequence and asked us to determine a formula. What we know that the numerator for each term is one, and the denominators essentially add the numbers after each other times, too. So, as we said, the numerator is one and the denominator times two minus one and this works. If you plug in 1 to 3, you'll got 1 1/3 1 fifth onwards.

Nine over a plus 11 Plus six over a 11 equals seven over A Squared -121. And when I factor a mine a squared minus 1 21 it's a plus 11 A. Minus 11. So my common denominators going to be our L. c. d. is going to be a plus 11. A minus 11 multiplying that by my first term A -11 cancels and I'm left with nine Times A -11 mm When I multiplied by my second term A -11 cancels and I have six times a plus 11. And when I multiply it by my last term both um By no meals cancel and I'm left with just seven. So now I distribute and I have nine A minus 99 Plus six A. Plus 66 equals seven combine my leg terms nine a.m. And six A. 15 A -99 plus 66 gives me -33 equals seven Had 33 to both sides. So I have 15 a equals 40 divide by 15. And you have a equals. And we're going to reduce this by five, Divide The numerator by five and the denominator by five, And you get 8/3.


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