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Question Which ofthe following magnetic fields? true about charged particle that moves through uniform electric AND Neither the electric nor = Both forces magnetic ...

Question

Question Which ofthe following magnetic fields? true about charged particle that moves through uniform electric AND Neither the electric nor = Both forces magnetic force depend on the speed of the particle Only depend on the speed of the particle the magnetic force Only the electric depends on the speed of the particle force depends on the speed of the particle

Question Which ofthe following magnetic fields? true about charged particle that moves through uniform electric AND Neither the electric nor = Both forces magnetic force depend on the speed of the particle Only depend on the speed of the particle the magnetic force Only the electric depends on the speed of the particle force depends on the speed of the particle



Answers

A charged particle is moving in a constant magnetic field. State whether each of the following statements concerning the magnetic force exerted on the particle is true or false? (Assume that the magnetic field is not parallel or antiparallel to the velocity.) a) It does no work on the particle. b) It may increase the speed of the particle. c) It may change the velocity of the particle. d) It can act only on the particle while the particle is in motion. e) It does not change the kinetic energy of the particle.

Question we have a charged particle which is moving in constant, magnetic field is supposed to be. Which of the following statement concerning the magnetic force F exerted on the particle is or are true. So talking about option A. It does not do, it does not work on the particle. This option is true because the particle moves on a circular path on. We know that on a circular path there is no network that. Okay now option B. It may increase the speed of particle. This option is wrong because the speed of particle do not vary. Only velocity varies. Okay, the speed remains constant. Still remains constant. Okay so it is remains constant. Always. Okay now talking about option C. It may change the velocity of the particle. This option is true. Okay because velocity has magnitude as well as the direction. So direction is very okay. Direction is wearing so velocity is changing of the guard charged particles. No talking about option D. It can act only when the particle while the particle is in motion. This option is also correct because magnetic force F. Is given by Q. V. And if this week is the steel or velocity, so if it becomes Jiro then force will also become zero. So this force will act until unless this spirit is a spirit of charged particle is equals to non zero. Okay, so this option is also true. Now talking about option E. It does not change the kinetic energy of the particle. This option is also correct. So We know that kinetic energy is given by one x 2 MV square. And here I. M. Is the mass of the child's particular and we is the speed of the charged particle. Since the speed of the charge particular is constant, we have ah top in the part B. So it means the kinetic energy E. Or K. It will remain constant. Okay, So it means option A, C. D. And E are correct. Only be is wrong. Okay.

This problem covers the concept of the magnetic force honor moving charge. The magnetic force on a moving charge equals the charge Q. Into the velocity vector across the magnetic field victor. Okay? So we can say the magnetic field force is directly proportional to the church, take her, and the magnetic field force exactly proportional to the magnitude doctor magnetic field. Okay? And the direction of the magnetic field force is perpendicular to the direction of the velocity, and the direction of the magnetic field force is perpendicular to the direction of the magnetic field. And we can also say the magnetic full force depends on borders, sign off the church. So the option A. B C. D. All options are correct. So the correct option is option E. He says all of the ever were correct.

In discussion the hell magnetic force on point that Africa Egypt was to Q. We were to cross period. Yeah. Had Have factories equals two magnetic boss queues equals to charge. We went to Egypt was to velocity of child. Okay. And we were very Egypt was to magnetic field. So we calculate dimension of magnetic. Well so bye diamonds and matter. Africa Egypt was to cure. We victor into be victor. We have dimensional BdB. So diamonds and of course H. M. One element T minus two dimensional charge. Even T. One diamonds. Novello cities equals to L. A. And T. Minus. And diamonds. And be it was to be so This is I'm 111 3 -2 and 11. Yeah A. Digital. Anyway so and the So dimension of B equals two. Yeah I am one element T -2. The world. The way L one after simplify we get dimensional be because I'm well a minus one. And do you minus this is our final answer for discussion. And this is given in often see and option she age correct. Mhm. Okay.

So true or false, a charged particle must move in a stationary magnetic field in order that have forced due to the field act on it. Well, we know that first the formula for the magnetic force F would be equaling the charge times the cross product between the velocity of the charge cross product with the magnitude the magnetic field. If the particle is at rest than the velocity of the particle is zero. And so this an equal zero meters per second in any direction we could say at rest. And so we can say that Then the force would be equaling the charge time zero cross product with we can sit. Oh, shit. So true or false, a charged particle must move in a stationary magnetic field in order that a force due to the field act on it. Well, we know that first, the formula for the magnetic for the magnetic field this would of course equals zero Newton's. And so the charged particle must be in motion in a stationary magnetic field in order that a force due to the field act upon it. So the given state the given statement is true. The charge must be in motion. And this is simply due to be formula for the magnetic force. That is the end of the solution. Thank you for


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