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Suspect that the concentration of nitrogen (moles) in the soil effects the growth rate of pecan trees in inches per year: What analysis would be best to look for re...

Question

Suspect that the concentration of nitrogen (moles) in the soil effects the growth rate of pecan trees in inches per year: What analysis would be best to look for relationship between this concentration and the growth rate?linear regression analysistwo sample testone sample testtwo sample proportion test

suspect that the concentration of nitrogen (moles) in the soil effects the growth rate of pecan trees in inches per year: What analysis would be best to look for relationship between this concentration and the growth rate? linear regression analysis two sample test one sample test two sample proportion test



Answers

In some situations, the amount of nitrogen fertilizer applied to crops is increased each year because the fertilizer decreases the rate of nitrogen fixation in the soil. Propose a hypothesis to explain this phenomenon. Describe a test for your hypothesis. What results would you expect from your test?

So we have a forest and we picked 36 trees and recorded their height. Then a year later, we found 42 more trees. Some of them could have been the same as the original 36. Most of them probably weren't, and we're told that all of these trees were planted at the same time. So is this dependent or independent? So even though it's very likely that these 36 trees and the 42 trees are not the same trees, this is a dependent sample. And that's because we're recording the heights of the trees one year and then another year we're going to the same group of trees and recording their height again, even though we didn't do all of, um, all of these trees were planted at the same time, so we're recording how much they grew in a year, and that is dependent because their heights the first year influence their heights. The second year

For this problem. We're going to be working with percent composition and molar ratios. Were given a substance that has a 30 10 10 composition. Were given the compounds that the substance is made up of And were given that the answer should be in X. Y. one format. All right. So since we're given that we have a 30 10 10% composition we with these compounds, respectively, we can assume that each of these compounds has the number of grams that the percent is given. So, for example are nitrogen which is actually going to be and two because nitrogen is diatonic, a 30% composition of nitrogen is just going to We can assume that that's 30 g because it's a part of a whole and 100 is easier to work with than anything else. All right, we're going to start with 30 g. R P 205 is going to have 10 g and r k g o. Is also going to have 10 g. All right. The first thing that we're gonna do is we're going to convert this grand values into moles. To do that. We're going to find our molar mass. We're gonna start with what we're given, which is our 30 g molar mass is the number of atoms that we have multiplied by their respective atomic masses. So, for and two it's going to be too Times the atomic mass of nitrogen, which is 14.007. And when we multiply that out, we get 28 .01g. So, we want our grand value to cancer cancel out. And that's actually grams per mole. So, we want our grams to cancel out. So we'll be dividing the grand values 28.1 g per one mole. And then to Gives us a molar value of 1.07 moles. All right. For P 205. We'll do the same thing. We start with what we're given our 10 g. So we have 10 g. Our molar masses going to We're going to list phosphorus and oxygen. We have two phosphorus five oxygen, Phosphorus has an atomic mass of 30 .974 oxygen has an atomic mass of 15.999 So we're going to multiply these things out two times 30.974 is 61.948 five times 15.999 is 79.997. And then we're going to some those two numbers together To get 1 41 .943 g per mole. When we go back up here to our conversion factor, once again, we want to get rid of the moles. I mean, sorry, the grams and be left with moles. So we put the moles on the top and we divide by our grams 1 41 .943 10, divided by 1:41.943 gives us 0.070 moles. And we'll do finally the same thing for our K20. We start with what we're given 10 g and then we find our molar mass. We have potassium and oxygen two and one oxygen's is 15.999 potassium is 39 .098. two times 39.098 is 78.196 Plus 15.999 is 94 .195 grams per mole. One more is 94 .195 g 10 divided by 94.195 Is 0.106 moles. All right now, we look at this format which is what the problem wants us to answer and we have X, Y. & one. So it wants our potassium to be in one. This is and he okay, respectively. So if we want our last value are 0.1061. We're going to divide by itself. We're turning this into a ratio so I can write this out down here as 1.07 0.070 0.106. If we want this one to be one, we divide by itself and we do the same. We divide by 100.106 for each of these values. And upon doing that Using two significant figures, We will get a 1.0 for this one For the middle will have 0.66. And then we'll have 10 For the 1st 1. This is our composition.

15. We have three graphs that represents the community of distribution of the heights of the mature piece. This means X. He represents heights 10 m. And here we have The maximum body is one that represents the fraction of plants. For party. We want to determine the height at which most of the unfertilized plants grow Most means about 50%. We can enter here by 50% then shoot the height. We can see the height about one m. This is the height for the unfertilized, right for barbie. We want to describe the effect of the fertilizers A. And B. We can do so by comparing the most, which means we compare the fraction of oh boy and fire. When we get A. Mm, we intersect at this point, which means It has a lower value than one. And when we intersect at B we get this height, which means it has higher value than not. Then the fertilizer B. Increases the average height of the plant, while fertilizer E. Decreases the average height of the planet. And this is a fender answer of our problem.

We've shown that £400 off my pigeon is acquired with the addition of £500 of force for us. So we had to find of the ratio of the stoop, so it would be something simple as for bread to 500. But just cancel the hundreds out and we had 4 to 5. That's your final answer.


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