For this problem. We're going to be working with percent composition and molar ratios. Were given a substance that has a 30 10 10 composition. Were given the compounds that the substance is made up of And were given that the answer should be in X. Y. one format. All right. So since we're given that we have a 30 10 10% composition we with these compounds, respectively, we can assume that each of these compounds has the number of grams that the percent is given. So, for example are nitrogen which is actually going to be and two because nitrogen is diatonic, a 30% composition of nitrogen is just going to We can assume that that's 30 g because it's a part of a whole and 100 is easier to work with than anything else. All right, we're going to start with 30 g. R P 205 is going to have 10 g and r k g o. Is also going to have 10 g. All right. The first thing that we're gonna do is we're going to convert this grand values into moles. To do that. We're going to find our molar mass. We're gonna start with what we're given, which is our 30 g molar mass is the number of atoms that we have multiplied by their respective atomic masses. So, for and two it's going to be too Times the atomic mass of nitrogen, which is 14.007. And when we multiply that out, we get 28 .01g. So, we want our grand value to cancer cancel out. And that's actually grams per mole. So, we want our grams to cancel out. So we'll be dividing the grand values 28.1 g per one mole. And then to Gives us a molar value of 1.07 moles. All right. For P 205. We'll do the same thing. We start with what we're given our 10 g. So we have 10 g. Our molar masses going to We're going to list phosphorus and oxygen. We have two phosphorus five oxygen, Phosphorus has an atomic mass of 30 .974 oxygen has an atomic mass of 15.999 So we're going to multiply these things out two times 30.974 is 61.948 five times 15.999 is 79.997. And then we're going to some those two numbers together To get 1 41 .943 g per mole. When we go back up here to our conversion factor, once again, we want to get rid of the moles. I mean, sorry, the grams and be left with moles. So we put the moles on the top and we divide by our grams 1 41 .943 10, divided by 1:41.943 gives us 0.070 moles. And we'll do finally the same thing for our K20. We start with what we're given 10 g and then we find our molar mass. We have potassium and oxygen two and one oxygen's is 15.999 potassium is 39 .098. two times 39.098 is 78.196 Plus 15.999 is 94 .195 grams per mole. One more is 94 .195 g 10 divided by 94.195 Is 0.106 moles. All right now, we look at this format which is what the problem wants us to answer and we have X, Y. & one. So it wants our potassium to be in one. This is and he okay, respectively. So if we want our last value are 0.1061. We're going to divide by itself. We're turning this into a ratio so I can write this out down here as 1.07 0.070 0.106. If we want this one to be one, we divide by itself and we do the same. We divide by 100.106 for each of these values. And upon doing that Using two significant figures, We will get a 1.0 for this one For the middle will have 0.66. And then we'll have 10 For the 1st 1. This is our composition.