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I2What is the current i3 through the wire coil after the coil leaves the field?i3What is the total charge magnitude |AQ| that flows past a given point in the coil a...

Question

I2What is the current i3 through the wire coil after the coil leaves the field?i3What is the total charge magnitude |AQ| that flows past a given point in the coil as it leaves the field?=lovl

i2 What is the current i3 through the wire coil after the coil leaves the field? i3 What is the total charge magnitude |AQ| that flows past a given point in the coil as it leaves the field? =lovl



Answers

A small, closely wound coil has $N$ turns, area $A$, and resistance $R$. The coil is initially in a uniform magnetic field that has magnitude $B$ and a direction perpendicular to the plane of the loop. The coil is then rapidly pulled out of the field so that the flux through the coil is reduced to zero in time $\Delta t$. (a) What are the magnitude of the average $\operatorname{emf} \mathcal{E}_{\text {av }}$ and average current $I_{\mathrm{av}}$ induced in the coil? (b) The total charge $Q$ that flows through the coil is given by $Q=I_{\mathrm{av}} \Delta t .$ Derive an expression for $Q$ in terms of $N, A, B,$ and $R .$ Note that $Q$ does not depend on $\Delta t .$ (c) What is $Q$ if $N=150$ turns, $A=4.50 \mathrm{~cm}^{2}, R=30.0 \Omega,$ and $B=0.200 \mathrm{~T} ?$

In the given problem, there is a coil and it is attached with the resistance Are area off The oil has given us zero point Tzeitel one 00 Mitre Square and a man already killed is linked to the oil initially, whose value is given us 1.10 Tesla? No. In that time delta T the direction of the magnetic field is reversed and it becomes in downward direction having the same magnet you so we can see. B two is minus 1.10 Yes, low number of counts in the oil uh 200 and resistance attached with the oil is 5.0 home. So the e M F ing used in the corn may be given as using Faraday's laws off electromagnetic ting induction minus defy by ditty. So it will become final clucks magnet flux minus initial magnetic flux divided by this changing time. So it will become be to a any of the oil minus Beaven in a video support by Delta T. So, if I put all these values taking, the serious a common are you get will be to minus 1.10 minus will be 11.10 by Delta 30 and for area 0.1 And this is wool in CNF. In news in the court. No, this will come out to be. It will become Do going do 0.1 and divided identity. This is the human. No current in the quiet will become a ER means you see 2.2 into 0.1 by Delta t by our, which is fine and beer and by the basic formula for the current. We know current has given us the time rate off low off charge so it can be given us this also. So here this Delta T will be cancer. So the charge passed through. There is a stents in this much time he's given us to going to into 0.0, even divided by fight. And here it will come out to be Yes, we have to multiply the number off rounds also. So here it will be into 200 also 200 into 200 every year into 200. So finally we get the answer for charge. Pashto, the circuit as 0.8. It hula because of this for me. Thank you

Right in this given problem. There is are square shaped coil which is and drink into a uniform magnetic field, magnetic field is directed into the plane of paper. Like this magnitude of this magnetic rule, which is directed into the plane of paper that is 0.40 s la Square shaped coil Is having a site is equal to 20 centimetre or 0.20 m Water turns in this soil. Uh given us 15 Oil is having 15 terms and it is moving towards right with a velocity B is equal to 3.0 m for a second. No actor given instant the length of this square shaped coil outside the magnetic field That is 9.0 centimetre. So in the first part of the problem, the right arm will be intercepting the magnetic aligns perpendicular early. So an IMF emotionally MF will be induced across its ends. And that emotional IMF will be given by the expression the product of magnetic field with the velocity with the land of the art. And obviously the number of turns because he's here, there will be total 15 arms which are intercepting the magnetic field lines for particularly. So the net TNF induced will be 10 times. So, plugging in all known values here Or b. The 0.40 s la multiplied by three, which is three 0.0 meter per second, multiplied by the length of this arm which is 0.20 m and number of terms which are 15. Finally the CMF induced here comes out to be 3.6 or it is one of the answer for this given problem. No, you find the direction of the CMF indios. As vendor coil is moving towards right downward or we can say inward Madrid IQ blox is increasing magnetic flux or magnetic field, inward magnetic field is increasing. So as for lenses lock in museums should be such that which may induce a magnetic field to oppose this inducing magnetic field. In short, we can say. As for lenses law, the induced magnetic field should be outward to oppose this inverted magnetic field and as we know, magnetic field comes out of the north pole. So the purpose of the soil will start behaving like and north fall and we know north polarity is due to a counter clockwise current in the coil. So finally the IMF are currently induced in this coil is counter clock wise in direction. So, here it is the complete answer for the first part of this problem. Now, in the second part of the problem, when the coil will be entirely within the field after entering entirely within the field, the flux link through the coil will become constant. There will be no change in the flux now, no EMF will be induced in it. Hence you may write it here. Then a coil enters and entirely into the magnetic field. Now there will be no change in the magnetic flux linked to the coil. So no E M F will be induced now means MF India's zero in the second part of this problem. Thank you.

Were asked to find the magnitude of the induced current in a coil which has a decreasing magnetic field flowing through it. The coil is rectangular and has a width of 0.85 meters in a height of 0.55 meters. The total number of turns in the entire coil is 75 and the total resistance in the coil is 8.7 so early. The magnetic field is decreasing at a rate of three Tesla's per second, so we can write. This is minus the change in the magnetic field over change in time is minus three. Tesla's heard second Well, the induced electro motive Force E is equal to the change in the magnetic flux over change in time. The negative of that the magnetic flux is equal to be times the area times the number of turns. So, using this, we can see that the electromagnetic force is equal to the minus of the change in the magnetic field. Over the change in time times the area times the total number of turns, the area is equal 2.85 meters times 0.55 meters, so area is equal to 0.0 4675 meters squared and that times in three times in its equal to zero point 3506 to 5. So we can get that. The magnitude these bars mean the magnitude of the electromagnetic force is equal to three Tesla's per second kinds 0.356 to 5. That number is 1.0 52 Tesla's meters squared per second. We didn't worry about the negative signs because we're just worrying about the magnitude. But then from Holmes Law, we know that the current is equal to the electromagnetic motive force over the resistance, which gives us that the magnitude of the current is equal to 1.5 to divided by 8.7, which gives us see that the manager of the current zero point 1 to 1 amperes

Hi. In the given problem, the magnitude of current induced in the coil will be given by the ratio off MF induced with the resistance of the coil Asper Homes law. And here the IMF induced will be given by the time rate off. Change off magnetic flux through the given coil, using Faraday's laws off electromagnetic induction so we can write it like one by our in tow differentiation off magnetic flux linked with the coil, which is given as total number off turns and multiplied by be the magnetic field multiplied by a area off the coil. As a number of turns, an area off the coil does not change so they can be taken as, ah constant out. So this is n into a divided by our into db by DT The time rate of change off magnetic field so plugging in all known values here for the number of turns. This is 75 for the length off this rectangular coil. This is 0.55 m for its width. This is 0.0 85 m divided by the resistance, which has given us 8.7 home and the time rate of change off magnetic field is given as three Tesla per second. So when we calculate all these things, the magnitude of current induced comes out to be 0.1 toe, one MP air and it becomes the answer for the given problem. Thank you.


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