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WuamIVconvergi 0z lens on Jullias camcra hus Hocsl lerah Oi u lolues cnlnem calculate tne distanatromlle Iens 452mniScn ucnthnchmn M Ene m thc Imaee Oistuike}IniendrInond:localeu d sta ie 0/ 2(cnmosnneenamin45mm HaneganAeilrm

WuamIV convergi 0z lens on Jullias camcra hus Hocsl lerah Oi u lolues cnlnem calculate tne distanatromlle Iens 452mni Scn ucnthnchmn M Ene m thc Imaee Oistuike} Iniendr Inond: localeu d sta ie 0/ 2 (cnmosnne enamin 45mm Hanegan Aeilrm



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(II) The eyepiece of a compound microscope has a
total length of 2.80 $\mathrm{cm}$ and the objective lens has $f=0.740 \mathrm{cm} .$ I an object is placed 0.790 $\mathrm{cm}$ from the objective lens, calculate (a) the distance between the lenses when the microscopeiadjusted for a relaxed eve, and $(b)$ the total magnification.

We have to find a focal length of component lenses solutions. So here, given that f equal in is equal to 10 sentiment and we know dak one upon F equal in is equal to Evan plus F to minus D upon Everyone. F two is here and The stance is given by two cm here. So yeah, checking the options A B c D. So now if well everyone is equal to 18 cm and after is equal to 20 cm. So now this is 18 plus 20 minus two upon 18 is multiplied by 20 is here. So that is 36 upon 18 is multiplied by 20. So that is one of content and we know that there is given that one upon F equivalent is also one upon tent. So here we can put the value of F equivalent. So this is one upon 10 is one upon 10 and this is all centimeters. So here the correct options is here everyone is equal to 18 cm and F two is equal to 20 cm. So now the correct option is everyone is 18 cm and have to wish 20 centim and that see options

So foreign. Come for a compounding is if you're going to find the distance, we can use the question twenty three point eight and that tells us that the object distance So we did nothing. One. Ah, the old one by saying that we're using the objective lens, plus the one so in its distance from the first lands on protective lens is equality the focal length of the objective lens. And from here, we can solve for the distance which is equal to F or B for one divided by D o one minus a fool. Now we're given the focal length and the object distance so we can plug in the numbers. Here it's going to be zero point seven for zero centimeter things point seven nine zero centimeter divided by zero point seven nine zero sending meter minus point seven four centimetre. And that gives us an objective in Mr Sense ofthe eleven point six nine scenting Now if we look at this equation, this is esta matic diagram the compound microscope where the first lens is thie objective lens and the second one is the eyepiece. So since we're way we viewed with Cynthia, Mrs viewed with a relaxed I. That means the final image should with infinity. Now, if the finally misses an infinity, that means the virtual image or the image that has been created from the first lens we used as an object for the second lands. And, ah, as we know that the image from the second Land should read infinity. That means the object should be at the focal length or the focal point off the eyepiece. So that's why the distance from here to here should be the focal length. And the total distance between the objective lens and the pipes should be the length total length of the compound microscope. So that means that old length is the image distance from the first lines, plus the focal length off the eyepiece. And that gives us eleven point six nine centimetre plus two point eight centimeter, with their equal to fourteen foreign four nine, sending her now for the second part. When we need to find the magnification, we can use Equation twenty for five point six a too calculated it. So it's going to be the value ofthe end for the relaxed I, divided by focal length of the eyepiece times and that's the total distance minus at me being focal length of the eyepiece divided by the Arctic distance. So let's put all the known values and find out the man in question. So for relaxed I it's an estimated five centimetre. If he has given us two point eight centimeter now end. We found out as a fourteen point four nine. If he is given us two point eight centimeter and Dio is given a zero point seven nine centimeters from here, we get the magnification is one thirty two x thank you.

In this problem who are asked to draw a re diagram for two convicts. Lanza's each having a focal length of four centimeters and a candles place tense in centimeters from the first plants. Now you are drawing this to scale. So it is important that you are using a ruler and measuring out all of these distances. Obviously, I can't do that. But I'm going to draw them out. And so again, you should be measuring out missing distances that I doing to scale. So what that means is this? Lenses are to 12 centimeters apart, and I am placing the focal off four centimeters. So about 1/3 of this distance again, I'm eyeballing it. You want to make sure that you're measuring this exactly to be four centimeters, and then our distance of the object is 10 centimeters away again. You measure this, I'm going to estimate it to be about here. This distance right here should measure distance of the object one as 10 centimeters. When you're drawing, you're a diagrams. The first rate goes parallel to the principal access, and then it goes through the focal now because this is a convex lens, the focal is going to also be a distance of four centimeters away, but on the other side, so again measured that out. So that's through the focal. And then the second ray diagram goes from the top of the object through the center of the lets. You can see where the two lines intersect is where my image is being created. So again, I'm representing my candle as a little error, which is because it's easier to drop now. For the 2nd 1 you are going to be doing the exact same thing. You're going to want to measure out that four centimeters again. I see the four centimeters is about here. One measure that number exactly. Measure it on both sides. And then same idea. Starting at the top of the object. We're gonna go parallel to the principal towards the centre, off the lens and then through the focal. And then these 2nd 1 is going to go through the center of the lunge, which is at the parallel, the lying down the center. So starting at the top of my object, you go through again. Where the two lines intersect is where my image is being created. You can see that the first lens did invert the image, and then the second lunch lens inverted the image back. Let's say that, actually forget.

Hi. In the given problem Equation 23 0.27 off. The chapter sees that the inverse off focal land off a convex lens is and minus one bracket one by our one minus one by our two. They're these organ and art are the radio off creature off both the surfaces off this convex lands and end is the absolute reflective in bags off the glass off lens. So it is said that this lens is dipped into water. We're and one is the reflective index, absolutely protected off water, which is surrounding this lands. And and two is the reflective index off glass off which this lens is made up off. Asked for that given question. So in first part of the problem, we have tow obtain, uh, changed expression for focal length means lens makers from law after making these required changes. So, in case the lens is dipped into the water, the app, the reflecting in depths off glass lands with respect, the water comes out Toby and off to with respect to one which can be given us and to bye and one so the lens makers from law becomes one by F is equal toe and off to with respect to one minus one one by our one minus one. By are to or we can say this is and to buy anyone minus one one by our one minus one by our two. So this is the expression for the focal length for the inverse off focal length off the convicts lands. Then it is dipped in the water. And this is the answer for the first part off the problem. Now, in the second part of the problem, we have to find the focal lengths off the same convex lens. In two cases, in the first case, the lens has been put in air. So the refractive index is it's absolute refractive index which is 1.5 only, and the radio off curvature off this lens are given us 40 centimeter reach. So if urban is plus 40 centimeter, then as for sign convention are you will be minus 40 centimeters as we know this is the convert flans Here, This is our one the videos off creator off which left face. So this will be positive as it is being measured in the direction off, incidentally, and this is our two, which will be taken as negative as it will be measured in a direction opposite to the direction off. Incidentally, hence now, using lens makers, Formula One by f is going toe end minus one one by our one minus one by our two and plugging in all the non values. This is 1.5 minus one one by our one means 40 minus one by minus 40. So this is 0.5 remaining outside the bracket. Then this is one by 40 plus one by 40. Here become 0.5 into two by 40 or simply won by 40. So but focal length off this convex lens in air comes out Toby plus 40 centimeter, and this is one off the answer off. Second part of the problem now, in the second part of the problem in the same second part of the problem, the second cases when the lenses dipped in water. So now in water, the absolute reflecting lacks off glass lenses 1.5, and that off water is 1.33 So now the focal length off this convex lens will be given us one by a dash is equal to and to buy n one minus one one by our one minus one by part two So plugging in all the known values again, this is end two means 1.5, divided by 1.33 minus one one by 40 minus one by minus 40. So here it is 1.1 to 8, minus one into two by 40. So it really needs as 0.1 toe eight divided by 20 as this is cancer, these forties canceled by two. So finally, dash is the focal length of this convex lens in water comes out to be 156 0.25 centimeters. So this is the last uncertain for the second part off a given problem. Hence, it is also clear that the focal length off the lens is increased. Then it is depicted in the water. Or we can say the power off this convex lens will be reduced when it is dipped in the water. Thank you


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