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J[Dpproigssulz nvosjyalau Mnsi-yeailege stldants Andu 0dge astronamy. One ccncept af intarest was the dang noor cne croallon olenmanse Sampib 145 Ireshman students ...

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J[Dpproigssulz nvosjyalau Mnsi-yeailege stldants Andu 0dge astronamy. One ccncept af intarest was the dang noor cne croallon olenmanse Sampib 145 Ireshman students belleved that the Big Barg theory accuratelY Descrlbed the creatian planetary systers. Basad Ihis informatlon , it correct at the 0.05 level significance state thal mare than 20% ol all freshren college s uderts believe Ine Big Bang theory descrbus Ihe crealion planelary syslerris?State the null and Iternative hypotheses Choose the co

J[Dp proigssulz nvosjyalau Mnsi-yeai lege stldants Andu 0dge astronamy. One ccncept af intarest was the dang noor cne croallon olenmanse Sampib 145 Ireshman students belleved that the Big Barg theory accuratelY Descrlbed the creatian planetary systers. Basad Ihis informatlon , it correct at the 0.05 level significance state thal mare than 20% ol all freshren college s uderts believe Ine Big Bang theory descrbus Ihe crealion planelary syslerris? State the null and Iternative hypotheses Choose the correct ansive Ho' p = 0.20 Ha;p > 0.20 Ho: p= 0.20 Ha' p < 0.20 OB. Hc' p# Ha; p = 0.20 D; Ho: p= 0.20 Ha' p+0.20 05. find the rejection region for the test. Choose the correc answerdeiow' 1.96 Or 2 < 1.645 2< - 196 1.645 Dr z < 1545 645 Calculatc the valuc of the test statistic. (Round cecimal placcs nceded }



Answers

Expand Your Knowledge: Sample Size and Significance of Correlation In this problem, we use Table $9-6$ to explore the significance of $r$ based on different sample sizes. See Problem 21 . (a) Is a sample correlation coefficient $r=0.820$ significant at the $\alpha=0.01$ level based on a sample size of $n=7$ data pairs? What about $n=9$ data pairs? (b) Is a sample correlation coefficient $r=0.40$ significant at the $\alpha=0.05$ level based on a sample size of $n=20$ data pairs? What about $n=27$ data pairs? (c) Is it true that in order to be significant, an $r$ value must be larger than $0.90$ ? larger than $0.70$ ? larger than $0.50$ ? What does sample size have to do with the significance of $r$ ? Explain.

In this question we're doing because car will is just so what's best completely stable by building D during columns. So we're Inc Well, so May is a different color. Why to three? Why 67 and 11 turf ended in the same. So we had positions should be tricked. 15 all right can. So it says did in. Ah, But it is Asian arts. There is no different difference in the mid ish one. It's different in defense. Peshawar is the plane and used to to to find new Chris Pariveda out of finds questions Little plan. 05 Krisel Freedom. There's a closed. Okay, they asked. Why credits 39 outside just to it's kind of video and quiet, but went 99 1 But in used to two companies, they test beta. Their formula for it is really h quarantine trend. Do it by, uh, both birthday and last line, but spread by, uh, a thread. I bet it by and a plus r b. It's great. Do anything and he plus, uh, see squared, but it by and see mine us three months right back and that's one big and is it is home number all that stuff and a plus and and that's and see which is a quality last. All right past fine, Kurt and a quote, sir, is it closed and be culture and see? But friends, uh, let's are is the brings. So are a It was a quote, sir. It's one plus three. Yes. Uh huh. Does by bless you know, then she's wonderful. I don't he isn't closure six plus seven Closed eight last night. Trust for 10. Quote you 44. Then out of C Is it cruncher to does? It's too Plus 10 Does have a point by president Point by Does She's a quote 52 then sometimes just devalues the formula. H has been quiet. Do you read it? By big end Is 15 bad by 15? That's why Want to read by gender ful squared? Do it by fine plus 44 squared. Do it by Brian Plus it would spread good it by fine mine us three by 15 plus one This is quieter The 2.16 minus 48 which is a potential for friend Wire six. Then compare You know you off. H would may critical baby Since full friend ones speaks. Sorry since opening 16 Let's then five. Blind 991 Okay. Do knows any change it is is not enough evidence to support claimed it bays a difference in mean.

All right. We have a sample of size and equal 73 of the 73 objects in the sample, 56 meet a certain criteria. And you want to observe our equals 56. We want to use this data to test the claim that the population proportion P does not equal 560.82 at a confidence level of 1% or alpha equals 10.1 Now that we've identified the confidence level, we can proceed in the following steps to conduct this test first is the normal distribution appropriate to use? Yes, it is because both NP and qpr greater than five. What hypotheses are retesting? We're testing them. No P equals 0.8 to the alternative. P does not equal 0.82 meaning we're testing or rather conducting a two tailed tests for this population proportion. Next compute p hat in your test statistic Piatt is simply are over and equals 20.77 We plug that along with PQ and and into the Z stat formula on the right to obtain Z equals negative 1.18 next to the P value. The p value can be found using it a lot google and textbook. And is the area outside of our positive, negative Z scores. This is a two tailed test, A. K. A. The area to the left of negative 1.18 An area to the right of 1.18 as is highlighted on the graph on the right. This gives P equals 0.2380 Next we reject H not no, we do not because he is greater than alpha. And we interpret this finding suggests we lack evidence that P does not equal 0.82

European number 23. Uh, it's, you know, they're not have processes. That new one is one of them repeal than YouTube. Alternative I busted in that new one is large in their music. Eso the critical value in table four, corresponding toe probability open 95. So the critical very equal to 1.645 So that the statistic is that equal toe X one bar, which is the mean off the first temple, minus the mean on the second sample minus new one minus you two over square, hold off. Think minus squared over and one lost signal to squared over. A two, which is a 2.6 and 2.62 is larger than 1.645 So we reject well, hypotheses, so there is sufficient evidence to support this claim.

We have a sample with N equals 83. And of that 83 members of the sample 64 satisfy a certain condition. Want to meet our equal 64. Now we want to use the sample data to test the claim that p does not equal 2.75 for the population at a confidence level of 5% or alpha equals 0.5 Now that we've identified the confidence level, we can go to the following procedural steps to conduct this hypothesis test first. Is the normal distribution appropriate to use? Yes, it is. Because both N. P and Q. P. R greater than five. B. One of the hypotheses were testing we're testing whether or not H not P equals 10.75 or H a p does not equal 0.75 Ak We're conducting a two tailed test. Next compute P hot. And the test statistic P hot is all over. N equals 20.77 Z is given by the formula on the right, taking in as input P hat P Q n N producing down to Z equals 0.42 Next we compute the P value. We use the table to see the area outside Z equals plus and minus 0.42 as we shaded in yellow and the graph on the right. This P value corresponds to 0.6745 Next we reject H not, no, we do not. P is greater than alpha and we interpret this signing to suggest that we lack evidence that P does not equal .75.


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