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Draw the structures and classify the following haloalkanes (alkyl halides) as mcthyl (0PC) primary ( 1' secondary (20 tertiary (3") halides pointsa) 3-cth...

Question

Draw the structures and classify the following haloalkanes (alkyl halides) as mcthyl (0PC) primary ( 1' secondary (20 tertiary (3") halides pointsa) 3-cthyl-2-jodopentanebromobutanec) methylchlorided) ten-bulyliodide[~methyl- [-bromocyclobutaneIndicale which of SN' , SN: both SN'+SN:, do you expect each of the following compvunds to undergo: Spts~2-chloro-3 3-dimethylhexane;~-sec-butyl-2-chlorononane;

Draw the structures and classify the following haloalkanes (alkyl halides) as mcthyl (0PC) primary ( 1' secondary (20 tertiary (3") halides points a) 3-cthyl-2-jodopentane bromobutane c) methylchloride d) ten-bulyliodide [~methyl- [-bromocyclobutane Indicale which of SN' , SN: both SN'+SN:, do you expect each of the following compvunds to undergo: Spts ~2-chloro-3 3-dimethylhexane; ~-sec-butyl-2-chlorononane;



Answers

Write the IUPAC names for the following halides.

In this question, we have to draw the structure for each of the given organic lives. 1st 1 is dyke Larue McCain. Okay, since it is met, so one carbon atom is here CH two CN two. Or if you draw see CN CN 88 All right now, the 2nd 1 is I'll do attack. I do in 10 CH three C H two. Hi then the next one is to floro propane. That one will be CH three CC three and the # two Carbon Atom is at us to it, their flooring atoms. Then the last one is one to die bro mo for being CH 2 C8 C83, first carbon one dominate, Amanda steer and with the second carbon another prominent at us. So it will be one to die promote propane.

Right in this question, we have to write the common name for each of that given organic lives. The first one is CA. S. three. Hi, the common name is metal. I'll died. The second one is CS three CH two. We are common name is. It'll remind. Then the 3rd 1 is CH three. See Ace to see Ace two F profile fluoride and the last one is C h T. Or to our ice C eight C N. This one is I super pile. I saw provide glow. Right? That's right here. Common name. Mhm. Mhm.

The sme reactivity of the following will be in that. Okay, so we are going to discuss how they can be arranged forgiven compound in the heart of the activity. In the assignment reaction carbon content is formed so we have to check the stability of cardiac attack. Right car back then is formed when the hell I get eliminated. So this here come positive charge, positive charge and this government positive charge at this moment this do this enough. If the molecule positive child is present on the engine drink, that's like it will be less stable in the er molecule, we can check that this is a three degree car button and it is conjugated with that tube engineering and one C three molecules. So this will be the most stable car over time Now. 2nd because in the second molecule cargo is that contributed with that vengeance now first because in the fashion molecule there is nine L five hyper contribution is very much in the fourth molecule, in the fourth molecule that is only six alpha hydrogen, four and then five. Okay.

Hello, everyone. Today we're doing Chapter 18 40 52 and this problem gives us a series of three substituted benzene rings and asks us to group each of these aerial Hey, lies in each of these group an order of increasing reactivity for your nuclear filic aromatic substitution by in addition, elimination mechanism. So what we know about an arbitrary Neagle Filic aromatic substitution reaction is that we have a bending group that is going to act as our electro fowl. And the reason for that is because the Benjamin Benzene Group is gonna have some electron withdrawing roots attached to it and a good leaving group being one of the highlights. And I'll just write that as X. So we have electoral join groups and leading groups that makes this benzine electoral, Philip, because over the electron poor nature around the benzene ring and we're going to react this with some sort of strong nuclear fall in which that nuclear followed attack and the carbon that has a leaving group and make some intermediates which will control here. The's intermediates are now putting a full car bana and a full negative charge within the ring of the benzene and are. The reason we have these electrons join groups is that once we do some residents structure, if you do some resident structures, we see that if the leaving group is also or pera to the electron with Join group or another way to sing it, if the election was John Group is, or for parents the leaving group for the nuclear follow will attack, then we will have stabilisation of this carb and ion. And the reason for that is because in the or Thor Para position, which you're yeah, election with Drying Group was going to be in the Ortho on para position that the lesson of drawing group's going to be this negative charge car man and is going to be stabilized by election. Pull towards those election with John Group here, so this will stabilize his intermediate. And this can go around to kick off here with your leaving group here and you'll get your substitution product here. Then you'll be left with your nuclear file or Thor Para to your election withdrawing group. And so, in order to rank the three of these compounds in terms of reactivity, well, there's a few factors we need to consider number one the number. The increasing number of your electron withdrawing groups on your bending rate will increase the reactivity for nuclear filic, aromatic substitution and specifically the number of electoral join groups at the Orth O and para position and respects to your leaving Grouping one of the highlights will increase in reactivity for your nickel foot. Aromatic substitution Reaction number two increasing the number of electoral negative Adams or, in this case, is going to be the Hey lines. For example, Florent broom in chlorine will increase the reactivity of your benzene derivative for your s reaction. So let's look at the series of three compounds Aaron Black. So here we have to consider two things. Number one, the electron withdrawn group must be or Thorn Pera number to the number of your Hey lad's. So in these three cases, we all have Florence, so number he lies all same. And we all have to leaving groups or sorry to electron neutron groups in each situation. But no. Now here's the difference. Don't bending groups 1/2 your electoral drawing group at the Ortho and para position. Those are going to be more reactive than something that's at the middle position. For example, the 2nd 1 So this first example here that has both nitro groups at the Ortho and met a position This is going to be the most reactive right off the bat. We're going to see that now. What about the second? One of the second has both natural electoral drunk groups at both meta positions. Well, this one has one para position, one medal position. So the one that has one para position will be the second most reactive and the one that has electoral drunk groups that both pair at both meta positions will be the least reactive. So you see, here we here we have one of the ortho one of the parent. That's why this is the most reactive. This one has only one at the Pera, while this one has zero at or Thorpe era. So we get our renting 123 So let's do the blue said, Here's the blue sets you see right off the bat that this first mark you here has no electron John group. So right away, these two already our I'll compete for reactivated in this one so we can just say this has this is number three because it's only has a hey life, but no left arm withdrawn. Now these ones have the both Same here lights. And they have the same identity for the election of Tarr groups. But their positions differ. This one is that the pair position? This one's at the medal position. Well, because this is at the medical Is that the para position? We know that in this resident structure this car Obama and is going to be located on this carbon which is going to be stabilized by this electron withdrawing Make sure that's Nitro Group. So this is gonna be more reactive than this Meta substituted Nitra Group where the carbon on will not be stabilized as much as if it was on the para position. So this is number one and this is number two. Last but not least, is this Siri's here. So this series we have a molecule to lash shall drug groups bottoming? Natural one flooring Here we have an actual national donating group being this method group here One election withdrawn group being this night Show it one Ah Hale. I've been chlorine and here we have seen that method donating electric, donating group, electoral drawing group at a lot. So right away, we know that one. Hey, liner to left arm of John Groups is better than one Hey, light with one less from a drug rip in one election donating group so we can say we're off the bat. This is the most reactive. Now, what about these two? So these two, the more election negative, Adam, the more reactor's going to be. So we know that Florida is the most were electoral negative Adam on the pier, our table. So we know that this monkey wear off the bat is going to be more reactive than this one with the Korean. So we know that this is going to be too, and it's going to be three.


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