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Give the correct IUPAC name for the following compoundsH;C_ BrCH;CH; 4H;C...

Question

Give the correct IUPAC name for the following compoundsH;C_ BrCH;CH; 4H;C

Give the correct IUPAC name for the following compounds H;C_ Br CH; CH; 4 H;C



Answers

Give the IUPAC name for each of the following compounds.

Problems with eight. We're still on our part, naming. So let's start with port, eh? As usual, let's go and find the longest chain we could find. And thanks for this, for this month's pretty obvious, all right. And here we have a double bun, right? And the rule is, whenever we have a double bond or a triple bond, we count from the side. We're we're closer. Ooh, that's fun. So what I mean by that is this double parked right here looks like it's gold or to the right side. And I mean, you don't really have to estimate you could, um, check, but I think it's pretty clear to see that there's only two carbons on the right side of the bond, and there's three on the left, so it's closer to the right, so we count flirting on the right side. What's going count? We've got one, two, three or five on our main main chain again. Let me give a space for Part eight. We got five, meaning we have a pen teen, my so pent for five and 19 because we have, um, a double bind in that double bond starts on carbon, too. right, Sergeant. Carbon tube. So this, this would actually be to painting. Okay. Just kind of round out of space there, but Okay, so we have to bend next, is rechecked our bench point. And we see here on carbon four that we have a metal group. I'm branching out, so we have a four metal foreman. Hey, so now that we have all the information we need, we could combine all of it and come up with our engine. So we have only one, um, one group we need to take care of. We got four method for metal. Two Fantine still Trib. Your answer for part eight. Go to part B. No, Part B. All right. So, again, as usual, let's find the, um, longest chain in this. Looks like our longest Jane right here. Right. Corbin's up here compared to just one. If you go, um, along a straight line and again account from where our double bind is closer, and for this one, it's pretty obvious that it's on the right side. In fact, it's out the end. The right side here. Okay, so we're counting from the right side here. 12 three or five Hey, So, uh, just like part A, We got Fantine. But this time, our double bond starts on carbon one. Right? So we have one Fantine bent because there's five carbons and pantin e n e. Because we have double bun. So next as we take care of our branch points and for this one, we actually only have one. We have a metal group connected carbon three. So we have I mean, it's a different color pen here. Um, we have three methods, three metal. So I think that's all the information we need. And we could proceed to combining all these information. So we have three muscle. The name our, um, branching group first. So three metal, one Fantine. And that's her. Answer or part be for Chino. We have a benzene ring and connected to our benzene ring or two chlorine. Adam. Hey, So got account. One on the carbon wear. Our marshal a group is or our Adam is. So this would be one and we gotta count two on the closest I'm branching group as well. So this has to be to hey is if we count to hear than this Korean beef carbon sick and we don't want that. So this Korean would be on carbon too. Okay, so we have die Koro. Right? So we have one too. One two. Since that's where we have our Corinne Adams and gotten die Claro for having to Korean Adam's, right, Like quarrel Benzie. Alternatively, the way that their positions since they are each other, we could also name that for so forthem. Shall we? Right? Oh, for Ortho. Oh di Toro, then. Hey, so there's two possible I APAC names for court. See? All right, we've been on to Port Party, as usual. Let's find the longest chain. And I think for this one that looks like it doesn't matter, right? So even if you get this metal or this metal, it's going to be the same length since it's just one method for both choices. All right, so let's just take the straight Jane, I think it's simpler and the count and see where we hit our double bond first. Okay, so if you count from the left, you got one too. 34 And if we come from right, we have one two me or Okay, So either way, like, either way, you know, it's kind of getting messy here, but either way, our double bind is gonna hit carbon to first. Hey, but if we count from the right and follow the green numbering once we hit carbon to not only do we hit our double bond, we also hit this branch point. You're good. So kind of on a shooting. Two birds in one stone right there. So we are gonna come from the right on this one, Scott, from the right. I got one. Who? Three four. And since we have or that's a beaut mean because of the double bind. And it starts when carbon too. Right? Double bond starts income number on carbon number two and gives us too beauty. Okay, I didn't write that well, but get what I mean, that's true beauty. And we have this metal group sticking out from carbon to as well. So we have a two metal. So combining all those information, we have two Bethel two. Too much too beauty. Right? And that would be your answer for party. All right. Finally, we are on part E here and again. Find the longest Jane, and it looks like it's pretty obvious whole thing here is our longest. Jane. So again, we are accounting from where our triple bond is closes. Okay, so this applies to both double and triple bond. So it's closer to the left Overcounting from the left. First, I want to Hey, 45 maybe write that of it in eight. So we get a and our triple bond starts on carbon three. So we got three. What? Right that I got it for eight. And why n e? Because of the triple bond. So we got three about a three off time, Okay? And last thing that we need to do here is to account for our method groups thinking out from carbon seven. Okay, so you got a seven metal. Hey. All right, so time to combine all the information that we have. We got seven metal three. Oh, time. Okay, so that's your answer for party. And finally, we're done here. We have names, all the molecules. We have four problem. 58

Name the Folding Elkins. Hey, which was the main chain assigned the smallest number. Prove it Double Barn, and she should be the longest. They're five carbons. So it's Bill. It has, ah, one double born. So it's in in the double bond starts at carbon one. So it's rump in June. The three methyl groups, which uh, attached to carbon free and two missile groups to four 344 Big, the longest principal chain contains six permanence and were numbered toe assigned the smallest number two the double bunk and smallest number for the substance. So the number and goes from the right to the left. The six carbons, one double bond, which starts it coming free. There is one group which is located it carbon free. See him the longest chin contains age carbons and remembering it assigned the smallest number double borrowed. So the H carbons there to double bones. They started it Trouble to in common five. That true methyl groups located it Carbon four and seven them the longest chain contains nine carbons, and we're number it from the left to the red to sign the smallest number two, the double burled. So they're men. Carbons? Yeah, this one double bond you in the double bunk stunts it's coming for. For there is a missile group, which is located if carbon seven and there is an effort group, which is like reagent of Carbon six.


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