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Roforoncos Use the References to access important values necded fcr Ihis question:Determine the pH change when 0.065 mol HI is added to 1.00 Lofa buffer = Min HCIO ...

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Roforoncos Use the References to access important values necded fcr Ihis question:Determine the pH change when 0.065 mol HI is added to 1.00 Lofa buffer = Min HCIO and 0.239 M in CIO" solution that is 0.351pH after addition pH beforc addition pH changeSubmlt Answer

Roforoncos Use the References to access important values necded fcr Ihis question: Determine the pH change when 0.065 mol HI is added to 1.00 Lofa buffer = Min HCIO and 0.239 M in CIO" solution that is 0.351 pH after addition pH beforc addition pH change Submlt Answer



Answers

Calculate the pH of 0.100 L of a buffer solution that is 0.25 M in HF and 0.50 M in NaF. What is the change in pH on addition of the following?
(a) 0.002 mol of ${HNO}_{3} \quad$ (b) 0.004 ${mol}$ of ${KOH}$

First, we'll calculate the pH of the buffer solution looking up the K value of H O C L, which is 3.5 times 10 to the negative eight. So pH will be equal to using the Henderson Hassle Baulch equation. The negative log of the K A value plus the log of the base concentration divided by the acid concentration based concentration, was given to us for potassium hypochlorite at 0.9, and then hypochlorite acid was point to, and we get a pH of 8.11 when pH equals P K. This ratio equals one, so the only way to make this ratio equal toe one is to add a strong acid. We need to decrease the amount of base by adding a strong acid and increase the amount of conjugate acid. So when the ratio is one, we have 10.9 minus X. The amount X, which is the amount of strong acid added and then 0.2 plus x, which is the amount of strong acid added. Rearranging the equation and solving for X gives us an X value of 0.35 moles of a strong acid such as HCL

First let us Cal Khalid B K A. For this value. So the foreigner we are using its peak a is equal to minus off. Log off. Hey, so the final be care value is seven point for six. Ex used the Henderson aggression to solve the it This is the hand disintegration immigration. After substituting the values in the creation, we get a B it off eight point cool. Then he h is equal to the value off B A. What offer? Transit fiction off acid is equal to the concentration off this here. The acid concentration needs to be increased by the base. Concentration needs to be decreased in order to get both have equal concentration. What's your problem? More asset is needed to be added in the buffer solution for the last, but even in the table, our initial concentration Auntie changing concentration after adding the acidic US and at P h equals toe peek A. Both asset and bass have same concentration. Hence we can solve that and get value off X, which equals Toby. Zero point 35 m. Therefore, 0.35 mole off asset. It still must be added to initial buffer. The concentration or a said the concentration off acid on base eventually equal to one another.

Here's another Henderson Hasselbach equation, and this is another voice over for this equation. Were given some information and we were asked to find the pH of a solution. And the solution is 0.20 Mueller H L C L, and were asked to find how many moles of either an acid or base so that we can guarantee the P H is equal to the peak. A. So those are our two tasks. The information that we're starting with our buffer solution is H L C L. With 2.20 polarity and Armel Arat e of r K L C L is 0.90 more. I forgot my mole arat e on my acid. So first, the pH and the pH will be equal to the K A. We looked up So the negative log of 3.3 or 3.5 times 10 to the minus eighth and my ratio will be the log of 0.90 over 0.20 Easy enough to solve. The pH is 8.11 8.11 Now, in order for the pH to be equal to the peak a. The ratio of the log of the ratio base over acid has to be equal to one because the log of one is zero. There, I'm writing. The log of base over acid has to equal zero. So the base concentration must equal the acid concentration, which they do not right now. But what can we do to get them thio equal one or equal each other? I should say, Well, we're going to have to add acid because we need to add the accident concentration increase on the base concentration to decrease. It looks like we're gonna have to add 0.35 moles of HCL. And that looks like this problem is solved once I get that colored in.


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