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Ml in 23 stakeara making you U IH tfcienoric) from Na Do and not sodium? 02, how IV Units grams 1 sodium Reportde...

Question

Ml in 23 stakeara making you U IH tfcienoric) from Na Do and not sodium? 02, how IV Units grams 1 sodium Reportde

Ml in 23 stakeara making you U IH tfcienoric) from Na Do and not sodium? 02, how IV Units grams 1 sodium Reportde



Answers

A sample of sodium liberates $2.73 \mathrm{~L}$ of hydrogen at $752 \mathrm{~mm} \mathrm{Hg}$ and $22^{\circ} \mathrm{C}$ when it is added to a large amount of water. How much sodium is used?

In this problem were asked to determine how many grams of sodium must react with 155 milliliters of water to produce a 0.175 Mueller solution of sodium hydroxide and were provided with chemical reaction shown here. The problem statement tells us that we can assume a final solution volume of 155 milliliters so we can take the polarity of our sodium hydroxide solution that we were given and Saul for our moles of sodium hydroxide because we were told that the final solution volume remains the same since we were given our volume in milliliters weaken divide 155 by 1000. So we have 0.155 leaders. Here we find that we have 0.0 271 moles of our sodium hydroxide present. We can take our moles of sodium hydroxide that we determined and translate them toe are moles of our sodium by using her story key metric coefficients and are given chemical reaction. So we know that for two moles of our sodium hydroxide that are produced, we require two moles of our sodium. We can then multiply by the molar mass of sodium to translate this into grams rather than moles. So our final answer is equal. 2.62 Ford grams of sodium.

Dan sitting of unit cell is calculated by then into um divided by divided by and me into a cube Or 30. Um in the given question then There will be given by two. That is what there is the number of atoms, number of Adams at dance, body unit sent and how do we get that? It is given to us? It is a BCC structure four BC. C. That is body centered cubic. Since it is body centered cubic. I can draw the structure like this. It is a cubic unit cell and I have atoms at the corners. In body centered cubic in itself. We have atoms at the corners of the cubic in itself for the top corners for the bottom corners. So total there will be eight or eight atoms and the corners and one item is at the center of the cubic in itself. So now the items are present in this case at the corners and at body center. So that's why if we calculate the contribution that is the number of transporting itself. So there are eight atoms at the corners. And one item is being shared by another eight units self and body centered in bodies. And a lotta. One item is at the center of the body of body, of the center of the body of unit cell. So this will be one into one because this atom which is situated at the center of the body of the unit cell. It does not being shared by any another unit cell. So that's why it will be 1-plus 1. That is it will be mm So this is how we say they're the value for that. That is the number of veterans spelling itself for BCC will be two. Now we have em for sodium here and will be taken as the atomic mass. I told me moths. So this is run deep sea given to us. You wanted the and now I am considering it as 23 ground caramel. That is For one mole of the sodium atom. We have 23 grounds math for product. Now for any any is arrogant. Rule number I will get rule number. So I have a phone number that is 6.023 into can raise the power don't give me. And a is edge length of the unit cell at the length of units at length of unit itself. Edge length of line itself. You need sell that is this one. So this is given by 4.24 and a strong If I converted into cm then it will be 4.24 into Can rest of our -8 cm. Now put all these values. All the values in the given formula for density of the sodium which is crystallized in bodies and turkey cubic unit cell which is given by their into em upon and me into a tube. Putting values there they were there multiply by am divided by and named multiply by a queue. So it will be that that is to Um that is 23. Any that is 6.023 into Multiply by can raise to power 23. Multiply by. It is a Q A Q. That is 4.24. Multiply by 10. Raised to Power -8. Feel them. So on solving it will be 1.0 zero two drum far centimeter. You. That is the the article density of story um which is being asked in the question. Your people density the article Dance city off sodium. Yes 1.00 who ground ball centimeter you

Those questions is the sodium level and a patient's blood was measured at 137 mil. Immel Sze per leader that it asks a 15 milliliters of blood is drawn from this patient. What massive sodium would be present? It's a straightforward calculation. We're gonna start with Concentration 137. Mila Mel's for a leader. They were trying to find out how many moles we have that we can convert to Mass. It's almost by this by 15 the leaders sensor units Aaron leaders will need to convert by dividing by 1000 1000 Miller leaders. Her leader. So cancel these units, but we're still up with Mila. Mel's immediate two Grams. We need to do to more conversions, Really Normally, molar masses air in terms of molds, not Mila moles. So let's convert Mill Mel's Mel's. There are 1000 Mila. Mel's her mole. Now he can't soul Miller malls left with moans. Now you can multiplied by the more mass for sodium. It's about 22.99 grams per mole. Moles cancels out. We're left with grams. That's the mass unit we need. Multiply this out. You would see if the answer is about 0.4 seven two grams of sodium

Start with a balanced equation. And the information given we have NA 202 solid plus which two oh to produce for any weight. Mhm. And oxygen gas And all of these sodium peroxide reacted and the oxygen gas was collected over water at 21°C.. The barometric pressure was 771 mm of Mercury. So this is um mm Temperature 21°C,, realistic Calvin 2 94. Tell them. And were given the pressure collected above water. So the actual pressure 771 mm of Mercury minus the amount over water. And this would be 18.7 mm of mercury at 21°C.. So this works out to 752.3 millimeters of mercury. Now let's convert this to atmospheres 752, of Mercury, 760 of Mercury devoted to one atmosphere. This would give us 0.9 90 Uh we'll do all we can do this. 246 fakes. Point 9899 atmospheres pressure. So we can calculate from our ideal gas equation, we calculate the molds which people at P. V. Over R. T. The pressure is equal. 2.9899 atmospheres were given. The volume is mhm. 31.0 mm is the volume of gas in the tube. So 31.0 middle leaders convert this. Two leaders have you A gas Constance Temperature is 2 94 Kelvin. And so the number of moles here be equal to .00127 moles. Yeah. And this would be moles of the oxygen as the values would be for the oxygen gases. That is the only gas in the system here. So now from moles of oxygen gas, we need to find the mass of the sodium peroxide That was present. So we'll use their psyche geometry here, uh, .001-7 moles of oxygen. Or start geometry here From a balanced equation, one mole of oxygen Is equivalent to two moles of the sodium peroxide And the molar mass here, one mole of the sodium peroxide has a mass of 78 0.0 grounds. Yeah, and this would give us our mouths here equal to point 198 grams of the sodium peroxide that would have to be reacted.


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