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Fnd tna - 'ort the Inctha Paae s Ihoughqon points(J,2)and (J.8) coned choice belaw and_ Tncasnin Ut Anieran comalele Yout cnoicl Seled teIha slope " (Type...

Question

Fnd tna - 'ort the Inctha Paae s Ihoughqon points(J,2)and (J.8) coned choice belaw and_ Tncasnin Ut Anieran comalele Yout cnoicl Seled teIha slope " (Type integet Tne slope undelniedsinplfied fracton )

Fnd tna - 'ort the Inctha Paae s Ihough qon points (J,2)and (J.8) coned choice belaw and_ Tncasnin Ut Anieran comalele Yout cnoicl Seled te Iha slope " (Type integet Tne slope undelnied sinplfied fracton )



Answers

Find the slope (if defined) of the line that passes through the given points. \$begin{aligned}&(0.12,0.36) \text { and }(0.18,0.36)\\&\text

Were given a pair of points, whereas to plot these points and find the slope of the line passing through them. Points are 4.83 point one and negative 5.21 point six. So first a plot. These points will draw the Cartesian plane so we see the X values range from as low as negative 5.2 up to positive 4.8. So let's let the X axis range from negative 10 up to positive five. We see the Y values range from 1.6 up to 3.1, so let the Y axis range from zero up to five. So our 1st 0.4 point eight 3.1 is located about here. So the X coordinates pretty close to five and the white coordinates just above three. Our second point native 5.2 1.6 is located about here. So you X coordinates just slightly less than negative five. And the Y coordinate is about halfway between one and two. Now, to find the slope of the line through these points will use their slope formula. This says that the slope is the change in the UAE values over the change in the X values. This is going to be 1.6 minus 3.1 over negative 5.2 minus 4.8. And so using a calculator, we have 1.6 minus 3.1. This is negative 1.5 over negative, 5.2 minus 4.8. This is negative 10 and this simplifies to 0.15 Now to check our answer, let's draw a straight line through our two points. Looking at this line, we see that it points up and to the right and so we expect this line to have a positive slope and this match is the fact that our answer is positive. However, notice that this line is also pretty close to being horizontal. So we expect the slope toe also be close to zero, which are answer point when five is. This confirms our answer. Now, one thing that's interesting about this problem is that in the previous exercises they did not deal with decimals. But here they've introduced decimals instead of whole numbers toe work with. I think this is because when you're working with whole numbers in particular, you're working with whole numbers, which have a easy computations toe work with, Um, sometimes you can forego using the slope formula. You can actually find the slope by simply looking at a plot of the line and counting the rise over the run, so to speak. However, when you're dealing with decimals here, it's a lot harder to count decimals. We would have to break this up into hundreds or tense instead of ones when you're dealing with decimals, and so you may have to count tens or hundreds of spaces to the right or up. No. So when you're dealing with decimals, you really are forced to use the point slope formula.

Hello. So here we're giving the points 8.5 comma 6.2 and the point negative 5.1 comma 7.9. So slow passing through these points is going to be changing Y over change in X. So we have X one, Y one and X two Y two. Therefore our slope is again y tu minus Y once that 7.9 minus 6.2. And then divided by changing X is going to be a negative 5.1 minus 8.5. Which is going to give us 1.7 divided by a negative 13.6, which um is going to become a negative 1/8. So our slope here is negative 1/8.

Mhm. In this problem, we are going to plot two points, sketch the line between them and then compute the slope. Yeah. Mm. Okay. Yeah. Okay. Here are two points. We're going to sketch them, remember they come in XY ordered pairs. This is the direction writer left, this is the direction up or down. So 4.83.1 would be over to the right, 4.8 from the origin and then up 3.1, It's about there and the negative 5.2 would be negative 5.2 to the left from the origin and then up 1.6 would be about there and here is our line that passes through them. Now slope is rise over run. Yeah. Mhm. With these numbers it's going to be difficult to count our rise without doing some computing, but we want to know how much we need to rise there to get even with that other point and then how much we need to run to get to the other point. So one way to do that is to use our white coordinates and subtract. So if this coordinate is up here at 1.6, Nope at 3.1 and this one is at 161 way to figure out Is that would be 3.1 -1.6 to find the distance between them. And then This point is over here at 4.8 and this point is over here at -5.2. So we could save 4.8 -5.2 -2.2. Sorry To find out how long that rise and run are. So 3.1 -1.6 Is 1.5. Mhm In 4.8 Basically Plus 5.2. That's what minus a negative does is 10 Okay, so the rises 1.5 The run is 10. We want to clean that up into a fraction that does not involve a decimal. So 1.5 is three. Halfs over 10. This would be the same thing as three Halfs divided by 10.1, which is three halfs times 1/10. So the slope of this line would be 3/20. Mhm. Yeah.

Okay, so given the following points 4.8 come a 3.1 and negative 5.2. Come on. 1.6. And we want to find the slope of the line that goes through these two points. So we're gonna let the first point b x one y one, and then the second point is gonna be x two y two. So to find the slope of that line, em is going to be equal to y tu, minus by one over X two minus x one. So, using the points that we have, why to minus y one is gonna be 1.6 minus 3.1. Then x two minus X one is gonna be negative. 5.2 minus 4.8. So this is going to give us a result of so 1.6 minus 3.1. That is negative. 1.5, then negative. 5.2 minus 4.8. That is negative. 10. So if we divide this out, we'll get a result of 0.15 So the slope of the line that goes through these two points is 0.15


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